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Ram Kushwah 6 years, 11 months ago
After all what is the question and surely
Sin60×cos30=√3/2×1/2=√3/4 not equal to
tan60 or √3
Yogita Ingle 6 years, 11 months ago
sin 60 = √3/2
cos 30 = √3/2
tan 60 = √3
Sin60 ×cos 30 = √3/2 × √3/2 = 3/4
tan 60 = √3
Note : Check question
Gurjar Naam ही भत्हैरा ??? 6 years, 11 months ago
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Gurjar Naam ही भत्हैरा ??? 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
Since 225 > 135, we apply the division lemma to 225 and 135 to obtain
225 = 135 × 1 + 90
Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain
135 = 90 × 1 + 45
We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain
90 = 2 × 45 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 45,
Therefore, the HCF of 135 and 225 is 45.
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Honey ☺☺☺ 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
a16 = P
an = a+(n-1)d
a + 15d = P --------------(1)
Sn = n/2[2a+(n-1)d]
S31 = (31/2) [2a+30d]
= (31/2) × 2 × (a+15d)
= 31 × (a+15d)
S31 = 31 P
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Posted by Shivam Gupta 6 years, 11 months ago
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Saigeetha Godavarthi 6 years, 11 months ago
Ram Kushwah 6 years, 11 months ago
253=3+(n-1)×5
n-1=250/5=50
So n=51
So 20th term from last is 51-20+1=32nd term
a32=3+31×5=158 and
Yogita Ingle 6 years, 11 months ago
a = 3, d = 5
Now, 253 = a + (n + 1) d
⇒ 253 = 3 + (n -1) x 5
⇒ 253 = 3 + 5n – 5
⇒ 5n = 253 + 2 = 255
⇒ n = 255/5 = 51
Therefore, 20th term from the last term = 51 – 19 = 32
a32 = a + 31d
= 3 + 31 x 5
= 3 + 155
= 158
Thus, required term is 158
Posted by Dhyanu Kumar 6 years, 11 months ago
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Lionel Messi⚽️ 6 years, 11 months ago
Chētnà Pandey✌️ 6 years, 11 months ago
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Sia ? 6 years, 6 months ago
We know mean ,
Mean = {tex}\frac{\text{Sum of given observations}}{\text{Total number of observations}}{/tex}
Mean of 25 observations = 27
Therefore, Sum of 25 observations = 27 {tex}\times{/tex} 25 = 675
If 7 is subtracted from every number, then the sum = 675 - (25 {tex}\times{/tex} 7)
{tex}= 675 - 175 = 500{/tex}
Then, new mean= {tex} \frac { 500 } { 25 } = 20{/tex}
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