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  • 2 answers

Aarvi Chhajed 6 years, 11 months ago

But i want it's proof

Priya Chaurasiya 6 years, 11 months ago

Thales thoerm is that- Two triangles are equal if their corresponding sides are in same ratio and corresponding angles are equal
  • 0 answers
  • 1 answers

Himanshi Sharma 6 years, 11 months ago

LCM is (48/27.32/27)....
  • 1 answers

Sinchana Sheshadri 6 years, 11 months ago

If the sum of terms is asked then you must use the sn formula but if a unkown term is given then you should find the 'nth' term using an formula.
  • 4 answers

Anu Kumari 6 years, 11 months ago

1/2

Himanshi Sharma 6 years, 11 months ago

1/2

Dad'S Angel? 6 years, 11 months ago

1/2

Archana☺ Singh 6 years, 11 months ago

1/2
  • 4 answers

Anu Kumari 6 years, 11 months ago

Plzz complete your q

Dad'S Angel? 6 years, 11 months ago

Plzz compete your question.

Himanshi Sharma 6 years, 11 months ago

Ya puja is right plz complete ur question

Puja Sahoo? 6 years, 11 months ago

Complete your question
  • 5 answers

Rajneesh Kumar ??? 6 years, 11 months ago

Board exam date sheet 7-3-19 - Maths 13-3-19- Science 16-3-19- Sanskrit 19-3-19- Hindi 23-3-19- English 29-3-19- Social science

Dad'S Angel? 6 years, 11 months ago

Are u online himanshi?

Himanshi Sharma 6 years, 11 months ago

By quadratic formula X=20 and X=5

Dad'S Angel? 6 years, 11 months ago

Two Zeroes of the given polynomial are 20 and 5

Yogita Ingle 6 years, 11 months ago

x2 - 25x + 100 = 0
  x2 - 20x - 5x + 100 = 0
 x ( x - 20) - 5(x - 20)= 0
  (x -5) ( x-20) = 0
x - 5 = 0 or x - 20 = 0
x = 5 or x = 20
 

  • 4 answers

Rajneesh Kumar ??? 6 years, 11 months ago

H.C.F. X L.C.M. = product of number 27 X 26460 = a X 540 a = 27 X 26460/540 a = 2646/2 a = 1323 answer

Himanshi Sharma 6 years, 11 months ago

A=1323......'

Puja Sahoo? 6 years, 11 months ago

a=1323....?

Dad'S Angel? 6 years, 11 months ago

Value of a=1323
  • 5 answers

Puja Sahoo? 6 years, 11 months ago

Hope yu can understand....

Puja Sahoo? 6 years, 11 months ago

Divide numerator and denominator by sin A. Then , put value of 1 as cosec square A - cot square A=1, in the numerator uske bad ap common lijiye or numerator and denominator se cancel kijiye uske bad prove ho jayega.

Anushka Jugran ? 6 years, 11 months ago

Firstly divide L. H. S by sinA

Puja Sahoo? 6 years, 11 months ago

Mai yahan pe answer kaise dun apko

Saumya Saini 6 years, 11 months ago

By mistake question is written wrong, Prove that:cosA-sinA+1/cosA+sinA-1=cosecA+cotA
  • 3 answers

Yogita Ingle 6 years, 11 months ago

Let the three middle most terms of the AP be: a – d, a, a + d.

So, (a – d) + a + (a + d) = 225
3a = 225
a = 75
Now, the AP is
a – 18d, …, a – 2d, a – d, a, a + d, a + 2d, …, a + 18d

Sum of last three terms: (a + 18d) + (a + 17d) + (a + 16d) = 429
a + 18d + a + 17d + a + 16d = 429
3a + 51d = 429
a + 17d = 143
75 + 17d = 143
17d = 143 - 75
d = 4
Now, first term = a – 18d = 75 – 18(4) = 3
Therefore, The AP is 3, 7, 11, … , 147.

Saumya Saini 6 years, 11 months ago

Describe please And the answer is 3,7 ,11,15 ....147

Puja Sahoo? 6 years, 11 months ago

3,7,11,15
  • 4 answers

Beauty Queen? Miss Sweetu? 6 years, 11 months ago

Thanks but. I cant dear

Puja Sahoo? 6 years, 11 months ago

Hope, yu can understand..........

Puja Sahoo? 6 years, 11 months ago

I cant type the answer here sorry,.......bt ap pehele tan alpha or tan beta dono side me sin or cos ki terms me convert kijiye and name it equation (1) now 1 ko l.h.s pe le ayiye or ise phir solve kijiye yu will get (cos square bita =2 cos square alpha) now put this value in equation 1 and yu will get the answer

Beauty Queen? Miss Sweetu? 6 years, 11 months ago

Please anyone
  • 2 answers

Rajneesh Kumar ??? 6 years, 11 months ago

A+B+C = 180 B+C =180- A Divide both sides by 2 Cosec square (B/2 + C/2) = Cosec square (180/2-A/2) Cosec square (B+C/2) = Cosec square (90-A/2) Cosec square ( B +C/2) = Tan square (A/2) Proved

Himanshi Sharma 6 years, 11 months ago

Cosec^2 (b+c/2)-tan^2(a/2)=1 L.H.S: =cosec^2(b+c/2)-cot^2(90-a/2) =cosec^2(b+c/2)-cot^2(b+c/2) =cosec^2-cot^2 =1 R.H.S
  • 1 answers

Himanshi Sharma 6 years, 11 months ago

Proof: In right triangle ADB and ADC so, by Pythagoras theorem, AB^2=AD^2+BD^2.................(1) AC^2=AD^2+DC^2..................(2) AB^2+AC^2=2AD^2+BD^2+DC^2 =2BD.CD+BD^2+CD^2 [given:AB^2=BD.CD] (BD+CD)^2=BC^2 Thus in triangle ABC we have, AB^2+AC^2=BC^2 Hence, triangle ABC is a right triangle right angled at A. Angle BAC = 90°
  • 2 answers

@ Aashu 6 years, 11 months ago

It is a graph which shows the cumulative frequency. In less than type ogive the graph line starts from down with raising upwards and in more than type ogive it starts from upwards decreasing downwards.

Prajwal Kulkarni 6 years, 11 months ago

Graph
  • 5 answers

@ Aashu 6 years, 11 months ago

Ya i have made

Chētnà Pandey✌️ 6 years, 11 months ago

I use Together with... .sample papers.....

@ Aashu 6 years, 11 months ago

I m a girl

Aj Raghav 6 years, 11 months ago

Self aasement bana liya ho bhai 1st ka

@ Aashu 6 years, 11 months ago

Ya me
  • 1 answers

Yaar 6 years, 11 months ago

( sec + tan )^2 - 1/ ( sec + tan )^2 + 1 == sec^2 + tan^2 + 2tan sec - 1/ sec^2 + tan^2 + 2tan sec + 1 == tan^2 + tan^2 + 2tan sec/ sec^2 + sec^2 + 2 ten sec == 2tan ( tan + sec )/ 2sec ( sec + tan ) == tan/sec == sin
  • 2 answers

Himanshi Sharma 6 years, 11 months ago

Mohit kapoor sorry ur answer is wrong.......

Mohit Kapoor 6 years, 11 months ago

6.34
  • 2 answers

Mounisha Reddy 6 years, 11 months ago

This is so easy yar

Shivam Singh 6 years, 11 months ago

Let if possible it is assumed that 7-√5 is rational no. 7- √5 = p/q. where p nd q are integers and q. qis not equal to 0 √5 = p/q - 7 Since p and q are integers so, p/q - 7 is rational and so √5 is rational But this contradicts the fact that √5 is irrational This is bcoz of our wrong assumption So we conclude that 7 - √5 is irrational
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  • 0 answers
  • 2 answers

Asia Reyaz 6 years, 11 months ago

Hey ram thanks a lot

Ram Kushwah 6 years, 11 months ago

nth term =a+nb

n+1th term =a+(n+1)b

n+2th term =a+(n+2)b

Here we see that all these terms are in AP AND common difference is b

 

  • 2 answers

Anushka Jugran ? 6 years, 11 months ago

U should practice full ncert but some extra book too

Yaar 6 years, 11 months ago

Yes, but you to analyse it completely.
  • 1 answers

Neelam Nayak 6 years, 11 months ago

Hiiiiii
  • 2 answers

Vidhi Lalwani? 6 years, 11 months ago

Thnk u sooo much.....for d ans

Ram Kushwah 6 years, 11 months ago

R= 7m

LSA = 551-1=550m2

LSA=πRl=πR√h2+R​​​​​​2=22/7×7√h2+49=550

√h2+49=25

h​​​​​​2​​​+49=625

h=√625-49=√576=24 m

Space in tent floor=πr​​​​​2=22/7×7×7=154 m​​​​​​2

area for each boy=

154/4=3=38.5 m​​​​​​2 Ans

 

  • 1 answers

Yogita Ingle 6 years, 11 months ago

Let the given vertices be A (1,7), B (4,2), C (-1,-1), D (-4,4)
AB = √ (4-1)2 + (2 -7)2 = √ 9 + 25 = √  34
BC = √ (-1-4)2 + (-1-2)2 = √ 25 + 9 = √ 34
CD = √ (-4+1)2 + (4 +1)2 = √  9 + 25 = √ 34
AD = √ (1 +4)2 + (7 -4)2 = √ 25 + 9 = √ 34
AC = √ (-1-1)2 + (-1-7)2 = √ 4 + 64 = √ 68
BD = √ (-4-4)2 + (4 - 2)2 = √  64 + 4 = √ 68
Clearly, AB = BC = CD = DA and AC = BD
Hence, given points are the vertices of a square

  • 1 answers

Ram Kushwah 6 years, 11 months ago

x-√2and X+√2 are factors

So x^2-2 is factor

On dividing 2x^4-7x^3-19x^2+14x+30 by

x^2-2 we get

2x^2-7x-15=0

(x-5)(2x+3)=0

other two zeros are 5,-3/2

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