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Let us assume that √5 is rational Then √5 = (a and b are co primes, with only 1 common factor and b≠0) ⇒ √5 = (cross multiply) ⇒ a = √5b ⇒ a² = 5b² -------> α ⇒ 5/a² (by theorem if p divides q then p can also divide q²) ⇒ 5/a ----> 1 ⇒ a = 5c (squaring on both sides) ⇒ a² = 25c² ----> β From equations α and β ⇒ 5b² = 25c² ⇒ b² = 5c² ⇒ 5/b² (again by theorem) ⇒ 5/b-------> 2 we know that a and b are co-primes having only 1 common factor but from 1 and 2 we can that it is wrong. This contradiction arises because we assumed that √5 is a rational number ∴ our assumption is wrong ∴ √5 is irrational number

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Prove that :-tan³A/1+tan²A + cot³A/1+cot²A = secA cosecA -2sinAcosA Anyone can answer my question Anyone have power ?✊?✊????????

Posted by Nikita Singh 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Himanshi Sharma 7 years, 3 months ago

L.H.S=tan^3A/(1+tan^2A)+cot^3A/(1+cot^2A) =tan^3A/sec^2A+cot^3A/cosec^2A =(sin^3A/cos^3A)/(1/cos^2A)+(cos^3A/sin^A)/(1/sin^2A) =sin^3A/cosA+cos^3A/sinA =(sin^4A+cos^A)/sinA.cosA =[(sin^2A+cos^2A)^2-2sin^2A.cos^2A]/sinA.cosA =(1-2sin^A.cos^A)/sinA.cosA R.H.S=secA.cosecA-2sinA.cosA =1/cosA.1/sinA-2sinAcosA =(1-sin^2A.cos^2A)/sinA.cosA Hence,L.H.S=R.H.S.......

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Aastha Dangi 7 years, 3 months ago

LHS = Tan^3A / ( 1+ Tan^2A) + Cot^3A / (1 + Cot^2a) = Tan^3A / Sec^2A + Cot^3A / Cosec^2A = (sin^3A/cos^3A) / (1 / Cos^2A) + (Cos^3A/Sin^3A) / (1 / Sin^2A) = Sin^3A/CosA + Cos^3A/SinA = (Sin^4A + Cos^4A) / SinA.CosA = [ (Sin^2A + Cos^2A)^2 - 2Sin^2A.Cos^2A] / SinA.CosA = ( 1- 2Sin^A.Cos^A)/ SinA.CosA RHS = SecA CosecA - 2sinAcosA = 1/CosA . 1/SinA - 2SinACosA = (1 - Sin^2A.Cos^2A) / sinAcosA Hence LHS = RHS (PROVED)

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What is adfected quadratic equation

Posted by Sumant Adky 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Friends my math is weak but my all subjects is good can any one help me to improve my maths

Posted by Mahi Choudhary 7 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Anshika Pal???? 7 years, 3 months ago

1st solve NCERT atleast 2 ya 3 baar than u can easily score 80% above in mathematics

2Thank You

@ Aashu 7 years, 3 months ago

Practise makes a man perfect....??

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@ Aashu 7 years, 3 months ago

Practise n practise

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What are the zeroes of a polynomial?

Posted by Rohit Kumar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Honey ☺☺☺ 7 years, 3 months ago

Solutions of a poly. OR roots of a poly.

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What is adfected quadratic equation . Write the standard of it.

Posted by Sumant Adky 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Saniya Sarfaraz 7 years, 3 months ago

What is adfected

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@ Aashu 7 years, 3 months ago

It is the equation having the highest power 2 .Standard form is ax2 + bx + c

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If the common difference of an ap is -6find a16-a12

Posted by Gaurav Fauzdar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Nakul Sharma 7 years, 3 months ago

-24

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Gautam Bansal 7 years, 3 months ago

-24

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The radii of two concentric circles are 13 cm and 8 cm. AB is a diameter of the bigger circle and BD is a tangent to the smaller circle touching it at the D and intersecting the larger circle at P on producing. find the length of AP.

Posted by Madhavi Sharma 7 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Rupal ???? 7 years, 3 months ago

16 cm

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Nakul Sharma 7 years, 3 months ago

16cm

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Honey ☺☺☺ 7 years, 3 months ago

Sorry its 16cm

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Honey ☺☺☺ 7 years, 3 months ago

2root39 cm

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The zeros of the quadratic polynomial x2+99x+127

Posted by Raj Durai 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 7 years, 3 months ago

X=(-99+-√99×99-4×1×127)/2

=(-99+-√9293)/2

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Divide 15000by 2:3:2

Posted by Sahana Savalagi 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 7 years, 3 months ago

R1+R2+R3=2+3+2=7

1st part=2/7×15000=2142.85×2=4285.7

2nd part=3/7×15000=6428.6

3rd part=4285.7

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K wala ncert ka

Posted by Lakshika Gupta 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

| | | {R J } .....! ! !: ; 7 years, 3 months ago

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If the height and radius of a cone of volume V are doubled, find the volume of the cone

Posted by Isneha Verma 5 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 7 years, 3 months ago

V=1/3πr²h

putting 2r for r and 2h for h

V1=1/3π{2r}^2(2h)

=1/3π(4r^2)(2h)

V1=8V

Hence volume becomes 8times

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In an equilateral traingle of side 24 cm find the length of the altitude

Posted by Apoorva Cholin 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Himanshi Sharma 7 years, 3 months ago

12 root 3

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Yogita Ingle 7 years, 3 months ago

Altitude of the equilateral triangle = √3/2 (side)
= √3/2 (24)
= 24√3/2
= 12√3 cm

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The product of two consecutive integers is divisible by 2. Is this statement true or false ? Give reason

Posted by Monika Mudgal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Honey ☺☺☺ 7 years, 3 months ago

Because any two consecutive integer is either odd -even or. even-odd. and we know that even numbers are divisible by 2 so their product will also be .................

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Himanshi Sharma 7 years, 3 months ago

Yes, this statement is true......

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Which are given below by monika

Posted by Monika Mudgal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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How you can say this give me complete solutions of this 2 questions

Posted by Monika Mudgal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Monika Mudgal 7 years, 3 months ago

Which are given below by monika mudgal

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Rishab Jain 7 years, 3 months ago

Which

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PQ is a tangent at a point C to a circle with centre O.If AB is a diameter and angle CAB=30,find angle PCA

Posted by Manisha Kumari 7 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Shubhangi Bura 7 years, 3 months ago

AO=OC (radii of same circle) .: tri AOC is isocles triangle Angle CAB= ang CAO =30 =ang ACO ( iso triangle theorem) Ang PCO =90(OC Perpendicular PQ) Ang PCA+ang ACO =90 PCA+30=90 PCA=90 –30=60

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Khush Pandya 7 years, 3 months ago

75 degree

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Honey ☺☺☺ 7 years, 3 months ago

60 degrees

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2. Write the number of solution of the following pair of linear equation: x+2y-8=0 , 2y+4y = 16

Posted by Monika Mudgal 7 years, 3 months ago

CBSE > Class 10 > Mathematics