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  • 3 answers

Harsh Pandey 7 years, 3 months ago

Thanks

Gaurav Seth 7 years, 3 months ago

43=7+(n-1)3

36+3=3n

39=3n

n=13

Puja Sahoo? 7 years, 3 months ago

There are 13 terms......
  • 1 answers

Dad'S Angel? 7 years, 3 months ago

Req. ratio is 1:1 and the value of m is 0
  • 5 answers

Gaurav Seth 7 years, 3 months ago

<header data-role="header" data-sticky="true" id="header">

Let us assume that ΔABC is an isosceles triangle having CA and CB of equal lengths, base AB of 8 cm, and AD is the altitude of 4 cm.

</header>

A ΔAB'C' whose sides aretimes of ΔABC can be drawn as follows.

Step 1

Draw a line segment AB of 8 cm. Draw arcs of same radius on both sides of the line segment while taking point A and B as its centre. Let these arcs intersect each other at O and O'. Join OO'. Let OO' intersect AB at D.

Step 2

Taking D as centre, draw an arc of 4 cm radius which cuts the extended line segment OO' at point C. An isosceles ΔABC is formed, having CD (altitude) as 4 cm and AB (base) as 8 cm.

Step 3

Draw a ray AX making an acute angle with line segment AB on the opposite side of vertex C.

Step 4

Locate 3 points (as 3 is greater between 3 and 2) A1, A2, and A3 on AX such that AA1 = A1A2 = A2A3.

Step 5

Join BA2 and draw a line through A3 parallel to BA2 to intersect extended line segment AB at point B'.

Step 6

Draw a line through B' parallel to BC intersecting the extended line segment AC at C'. ΔAB'C' is the required triangle.

Justification

The construction can be justified by proving that

In ΔABC and ΔAB'C',

∠ABC = ∠AB'C' (Corresponding angles)

∠BAC = ∠B'AC' (Common)

∴ ΔABC ∼ ΔAB'C' (AA similarity criterion)

… (1)

In ΔAA2B and ΔAA3B',

∠A2AB = ∠A3AB' (Common)

∠AA2B = ∠AA3B' (Corresponding angles)

∴ ΔAA2B ∼ ΔAA3B' (AA similarity criterion)

On comparing equations (1) and (2), we obtain

This justifies the construction.

Ram Kushwah 7 years, 3 months ago

If base =2x=8

x=4

Side​​​2​​ =x​​​​​​2+h​​​​2=16+16=32

side=4√2=4×1.41=5.64 cm

AB=AC=5.64 Cm BC=8 cm

Puja Sahoo? 7 years, 3 months ago

How to construct here?

Riya ? 7 years, 3 months ago

ya actually bhumika is right.

????? ❤️ 7 years, 3 months ago

Yaha pe construction kaise kare
  • 5 answers

Durga Appa 7 years, 3 months ago

Answer is coming as k=root of -24

Riya ? 7 years, 3 months ago

put the value in formula of discriminant:- D = b^2 - 4ac

Saurabh Singh Harariya 7 years, 3 months ago

Yes aditya is correct

Lionel Messi⚽️ 7 years, 3 months ago

Nothing D you put only a b and c

Lionel Messi⚽️ 7 years, 3 months ago

Find D or discriminant apply D = b2 - 4ac
  • 2 answers

Vansh Sehgal 5 years, 11 months ago

Anyone online

Vansh Sehgal 7 years, 3 months ago

Means?
  • 6 answers

????? ❤️ 7 years, 3 months ago

Ek or question h

????? ❤️ 7 years, 3 months ago

Thnks kabir ji
Sorry first 20 terms are 11,7,3,-1,-5,-9,-13,-17,-21,-25,-29,-33,-37,-41, -45,-49,-53,-57,-61,-65...
Put n=1,2,3 In -4n+15 A1 = -4*1+15 =11 A2. =-4*2+15=7. A3 =-4*3+15 =3. D= A2 - A1 D= 7 -11 =-4 A20. = A1 + 19D = 11+(19*-4) = 11-76 -65....

????? ❤️ 7 years, 3 months ago

Solution pls
-65....
  • 4 answers

Anushka Jugran ? 7 years, 3 months ago

Don't worry jitna jyada questions solve karoge utne hi expert hote jaoge

Vansh Sehgal 7 years, 3 months ago

You can tell if u have problem in any question or any querie

Vansh Sehgal 7 years, 3 months ago

Ya tell the question

Anushka Jugran ? 7 years, 3 months ago

Just try to understand the questions first... Read it atleast two times and then answer it. Also learn all the formulae of this chapter
  • 4 answers

Dad'S Angel? 7 years, 3 months ago

DHAMA bhi gujjar hote hai .... Kabir bro??

Riya ? 7 years, 3 months ago

zeroes are 2 and 2.

Dad'S Angel? 7 years, 3 months ago

Zeroes r 2,2 ☺☺

. . 7 years, 3 months ago

2,2
  • 1 answers

Rishi Shukla 7 years, 3 months ago

2+×=0 so ×=-2
  • 7 answers

Neha Choudhary 7 years, 3 months ago

First NCERT then RD

Anjali Singh 7 years, 3 months ago

Ya you are right Jasline K

Jasline S.? 7 years, 3 months ago

You know mai ncert karti hu but it doesn't help me because paper muskil hi lagta h . So I think sample paper are good for preparation. Mujhe to ncert book rat gayi h revise kr kr k.

Puja Sahoo? 7 years, 3 months ago

Ncert......... first complete it

| | | {R J } .....! ! !: ; 7 years, 3 months ago

NCERT

Anushka Jugran ? 7 years, 3 months ago

I prefer ncert exampler and arihant sample paper is also important.

Jasline S.? 7 years, 3 months ago

I an using " u like "
  • 7 answers

Dad'S Angel? 7 years, 3 months ago

Right answer is 423

Jasline S.? 7 years, 3 months ago

Neha is right

Jasline S.? 7 years, 3 months ago

No no no no 276

Jasline S.? 7 years, 3 months ago

Is 579

Avanish Yadav 7 years, 3 months ago

423

Avanish Yadav 7 years, 3 months ago

galat ans

Neha Choudhary 7 years, 3 months ago

279
  • 0 answers
  • 1 answers

Sia ? 6 years, 9 months ago

The greatest number of cartons is the HCF of 144 and 90
Now the prime factorization of 144 and 90 are
{tex}144=16×9=2^4{/tex} {tex}\times{/tex} 32.{tex}{/tex}
{tex}90=2\times3\times3\times5=2\times3^2\times5{/tex}
HCF (144,90)= 2 {tex}\times{/tex} 32 = 18
{tex}\therefore{/tex} The greatest number of cartons each stack would have= 18.

  • 6 answers

Aradhana Singh 7 years, 3 months ago

Hlw how are yu friends

Anushka Jugran ? 7 years, 3 months ago

Hii

Pihu Saini 7 years, 3 months ago

Kaha s hoo

Yaar 7 years, 3 months ago

Hii bhai

Twinkle Star ( Atul )....... ?? 7 years, 3 months ago

Í

Pihu Saini 7 years, 3 months ago

Hii
  • 3 answers

Puja Sahoo? 7 years, 3 months ago

x square + y square whole root over. As coordinate of origin Q(0,0). Put the distance formula

. . 7 years, 3 months ago

Root xsq.+ysq.

Susmita Mandal 7 years, 3 months ago

√x^2+y^2
  • 2 answers

Lionel Messi⚽️ 7 years, 3 months ago

What is it question man

Puja Sahoo? 7 years, 3 months ago

Complete your question .....
  • 1 answers

Yaar 7 years, 3 months ago

LHS =cosA/(1-tanA)+sinA/(1-cotA) =cos A/(1 - sin A/cos A) + sin A/(1 - cos A/sin A) =cos²A/ (cos A - sin A) + sin²A / (sin A - cos A) =cos²A/ (cos A - sin A) - sin²A / (cos A - sin A) =(cos ² A - sin ² A) / (cos A - sin A) =(cos A - sin A)(cos A + sin A) / (cos A - sin A) =cos A + sin A i.e RHS Read more on Brainly.in - https://brainly.in/question/1346932#readmore
  • 1 answers

Sia ? 6 years, 9 months ago

Given,

AB II PR
{tex}\angle{/tex}B = {tex}\angle{/tex}Q [Alternate interior angles]
{tex}\angle{/tex}B = 70o
{tex}\triangle{/tex}AQB is an Isosceles triangle,
AQ = BQ
So, {tex}\angle{/tex}BQR = {tex}\angle{/tex}BAQ
{tex}\angle{/tex}A = 70o
In {tex}\triangle{/tex}AQB,
{tex}\angle{/tex}QAB+ {tex}\angle{/tex}ABQ + {tex}\angle{/tex}BQA = 180o
{tex}\Rightarrow{/tex} {tex}70° + 70° +{/tex} {tex}\angle{/tex}{tex}Q = 180^o{/tex}
{tex}\Rightarrow{/tex} {tex}\angle{/tex}B{tex}QA = 180^o - 140^o = 40^o{/tex}

  • 2 answers

Gaurav Seth 7 years, 3 months ago

Let a and d be the first term and common difference respectively of the given AP,then

 mth term = a+(m-1)d    ==> a+(m-1)d = 1/n     -----(1)
 

and  nth term=a+(n-1)d    ==> a+(n-1)d = 1/m        -----(2)

 

subtracting (2) from (1), we have

       Let the first term of the A.P be 'a ' and its common difference be 'd '

Now, mth term of the A.P is 1/n

which means, a + (m - 1)d = 1/n --- (i)

Again,

its nth term is 1/m

which means, a + (n - 1)d = 1/m --- (ii)

on substracting eqn. (ii) from (i) we get,

a + (m - 1)d - a - (n - 1)d = 1/n - 1/m

=> d (m - 1 - n + 1) = (m - n)/mn

=> d (m - n) = (m - n) / mn

=> d = 1/mn

so, a = 1/m - (n - 1)(1/mn) = n - n + 1 / mn =1/mn

ie., a = d = 1/mn

Now, Smn = mn/2 [2a + (mn - 1)d]

= mn/2 [2/mn + (mn - 1)1/mn]

= mn/2 [2 + mn - 1]/mn

= (mn + 1)/2

. . 7 years, 3 months ago

mn+1by2
  • 1 answers

Sia ? 6 years, 9 months ago

Radius of well {tex} = \frac{7}{4}m{/tex}
Depth of well = 20m
{tex}\therefore {/tex} Volume of earth taken out {tex} = \frac{{22}}{7} \times \frac{7}{4} \times \frac{7}{4} \times 20c{m^3} = \frac{{385}}{2}{m^3}{/tex}
Area of field {tex} = 20m \times 14m = 280{m^2}{/tex}
Area of field excluding well {tex} = \left( {280 - \frac{{22}}{7} \times \frac{7}{4} \times \frac{7}{4}} \right){m^2} = \frac{{2163}}{8}{m^2}{/tex}
{tex}\therefore {/tex} Level of earth raised {tex} = \frac{{volume\;of\;earth\;taken\;out}}{{Area\;of\;field}}{/tex}
{tex} = \frac{{385}}{2} \times \frac{8}{{2163}}m = 0.7119m{/tex}
= 71.19 cm

  • 6 answers

. . 7 years, 3 months ago

Most most most most most wlcm

Anushka Jugran ? 7 years, 3 months ago

Most wlcm neha

Aa Bisht 7 years, 3 months ago

Thanks to all

Anushka Jugran ? 7 years, 3 months ago

66

Chētnà Pandey✌️ 7 years, 3 months ago

Yes 66 is correct answer ....... Just make equation like a37= a+36d and then solve accordingly but I solved it the answer is 66

. . 7 years, 3 months ago

66
  • 5 answers

Riya ? 7 years, 3 months ago

in a pack of card there is only 2 red queen so the probability of getting a red queen =2/52 =1/26 Ans and probability of getting heart :- total number of heart in a card =13 so, P (heart)= favorable outcomes /total outcomes =13/52 =1/4 Ans

Chētnà Pandey✌️ 7 years, 3 months ago

Your welcome @Neha Bisht

Aa Bisht 7 years, 3 months ago

Thanks chetna

Vishakha Singh? 7 years, 3 months ago

14/52 i.e. 7/26

Chētnà Pandey✌️ 7 years, 3 months ago

There are 4 queens in a pack of cards so probabilty of getting a queen is = 4/52= 1/13
  • 3 answers

Vishakha Singh? 7 years, 3 months ago

Sorry...its not hace used...its have used#myans

Vishakha Singh? 7 years, 3 months ago

Ans is 0 > Sin(39+Q)-cos(51-Q) Cos(90-(39+Q))-cos(51-Q) Cos(90-39-Q)-cos(51-Q) Cos(51-Q)-cos(51-Q) **hace used Q in place theta

Aa Bisht 7 years, 3 months ago

Sorry it's thita instead of that's

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