CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

By subsitution method 2x= 8-3y x =8-3y/2 Put the value of x in second eqn. x -2y+3.... 8-3y/2 -2y+3=0 8-3y-4y+6/2=0 8-7y+6=0 -7y=-14 Y =2 Put he value of y in first eqn. 2x+3y=8... 2x+3(2)=8 2x+6=8 2x=8-6 2x=2 X=1

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Jot Virk?♠ 6 years, 11 months ago

Y=2, X=1

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Honey ??? 6 years, 11 months ago

X=1 and y=2

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What are the important theorem for pre board

Posted by Someshwaran Rameshkumar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

5 answers

Ankita ?? Arpita☺️ 6 years, 11 months ago

Book ki sare theorem important he

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Yati ? 6 years, 11 months ago

Pythagorus,theles theorem

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Sarthak Paliwal 6 years, 11 months ago

Pythagorus,theles and theorem 10.2

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D.J Alok 6 years, 11 months ago

Pythagoras theorem and Thales theorem....

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Chhaya Patel 6 years, 11 months ago

Pythagoras theorem

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A part of monthly expenses of a family is constant and the remaining varies with the price of rice.When the cost of rice is ₹250 per quintal,the monthly expenditure of the family is ₹1000 and when the cost of rice is ₹240per quintal the monthly expenditure is ₹980.Find the monthly expenditure of the family when the cost of rice is ₹300 per quintal.

Posted by Kamakshi Gupta 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Honey ??? 6 years, 11 months ago

May be 1150 ,but the monthly expenses is not constant.

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Lab activities

Posted by Shreya Agrawal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Sunidhi??? Chauhan 6 years, 11 months ago

It must be clear for examination because it was of 8 Marks in exam

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Find the value of k for which one root of the quadratic equation kx_14x+8=o is 2

Posted by Paban Debbarma 6 years, 11 months ago

CBSE > Class 10 > Mathematics

4 answers

Ankita ?? Arpita☺️ 6 years, 11 months ago

Shayad k=10

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Sarthak Paliwal 6 years, 11 months ago

Put 2 in the place of x because 2 is a root.

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Divyanshu Arya 6 years, 11 months ago

Use Euclid 's division Algorithm to find tha HCF of : 135 and 225

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Honey ??? 6 years, 11 months ago

Equation mein sq. shayad reh gya hain but k =5

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2x+3y=8 4x+6y=16

Posted by King ... 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

King ... 6 years, 11 months ago

By multiplying equation number 1 by 2 Then we will get equation number 2

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If one zero of a polynomial is given then how we an find others three

Posted by Himanshu Chadhal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Rishi Kabir 6 years, 11 months ago

Divide the given polynomial by taking one zero

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If a sum of a no. And it's resiprocal is 26 /5 . Find number.

Posted by Divya Chavada 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Umaid Shafi 6 years, 11 months ago

Let the no be x So its reciprocal is 1/x According to question x+1/x=26/5 5(Xsq+1)=26x 5Xsq-5-26x=0 5Xsq-26x+5=0 5Xsq-26x+x+5=0 5x(x-5)-1(x-5)=0 x=1/5 & x=5

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Sumedh Dabir 6 years, 11 months ago

x + 1/x = 26/5 represents the given statement. Solve for x. since x cannot be zero (which has no reciprocal), you can multiply all terms by x to get x2 +1 = (26/5) x. You have to solve for x. It's a quadratic equation: multiply by 5 to get: 5x2 -26x +5 = 0.

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find the condition that zeroes of polynomial p(x)=ax2+bx +c are reciprocal of each other

Posted by Shalu Singh 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Music_ Lover?? 6 years, 11 months ago

Take one zero as alpha..and other as one upon alpha

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ANSWER

Solve for x and y : 2x+ 3y =7 ,, (a+b+1)x +(a+2b+2)y =4 (a+b)+1

Posted by Saransh Jaiswal 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

If infinite number of solutions,
{tex}\frac{{{a_1}}}{{{a_2}}} = \frac{{{b_1}}}{{{b_2}}} = \frac{{{c_1}}}{{{c_2}}}{/tex}
or {tex}\frac{2}{{a + b + 1}} = \frac{3}{{a + 2b + 2}} = \frac{7}{{4a + 4b + 1}}{/tex}
If {tex}\frac{2}{{a + b + 1}} = \frac{3}{{a + 2b + 2}}{/tex}
{tex}\Rightarrow{/tex} a - b = 1
and if {tex}\frac{3}{{a + 2b + 2}} = \frac{7}{{4a + 4b + 1}}{/tex}
{tex}\Rightarrow{/tex} 5a - 2b = 11
On solving we get,
a = 3 and b = 2

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Solve for x and y: 2x+3y=7 (a+b+1)x+(a+2b+2)y=4 (a+b)+1

Posted by Saransh Jaiswal 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

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Can we have any natural number 'n' for which 6^n ends with the digit '0'?justify you answer.

Posted by Saransh Jaiswal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Tripathi 6 years, 11 months ago

Let 6^n ends with 0 so its prime factor is 2^n×5^m But as v know Prime factor of 6^n is 2^n ×3^n Not 2^n×5^m so No any natural number for which 6^n ends with 0

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What are the possible outcomes if we tossed three differe nt coins simultunously

Posted by Divanshu Rawat 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajkamal Jaiswal 6 years, 11 months ago

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ANSWER

,hindi me maths

Posted by Dhananjay Tiwari 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Shashank Thakur 6 years, 11 months ago

गणित

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Find thw value of k so that the following system of equation has no sollution: 3x-y-5=0; 6x-2y-k=0

Posted by Ruhma Ruhma 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Aryan Khare 6 years, 11 months ago

3x-y-5=0 6x-2y-k=0 a1/a2=b1/b2 is not equal c1/c2 (no solution) 3=1 is not equal 5 6 2 k K is not equal to 10 ( cross multiply)

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What is the relation between mass and radius of sphere?

Posted by Ansh Rohilla 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

density = mass / volume
And then find the radius from the volume
volume = 4πr³/3

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ANSWER

In triangle ABC right angle at A and un triangle PQR right angle at P and cosB=cos theta

Posted by Sita. Devi 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Pythagorus theorem

Posted by Mohan Vats 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Anushka Jugran ? 6 years, 11 months ago

Given in ncert...

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Prove that root 3 is rational number

Posted by Suca Suca 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Sumedh Dabir 6 years, 11 months ago

This is of root 2 Assume $\sqrt{2}$ is rational, i.e. it can be expressed as a rational fraction of the form $\frac{b}{a}$, where $a$ and $b$ are two relatively prime integers. Now, since $\sqrt{2}=\frac{b}{a}$, we have $2=\frac{b^2}{a^2}$, or $b^2=2a^2$. Since $2a^2$ is even, $b^2$ must be even, and since $b^2$ is even, so is $b$. Let $b=2c$. We have $4c^2=2a^2$ and thus $a^2=2c^2$. Since $2c^2$ is even, $a^2$ is even, and since $a^2$ is even, so is a. However, two even numbers cannot be relatively prime, so $\sqrt{2}$ cannot be expressed as a rational fraction; hence $\sqrt{2}$ is irrational. $\blacksquare$

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Riya Jain 6 years, 11 months ago

Given in ncert examples

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Fundamental theorum of arithmetic

Posted by Sheela Yadav 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Chetna Pandey 6 years, 11 months ago

theorem, states that every integer greater than either is a prime number itself or can be represented as the product of prime numbers and that, moreover, this representation is unique, up to (except for) the order of the factors.[For example, 1200 = 24 × 31 × 52 = 2 x 2 x 2 x 2 x 3 x 5 x 5 = 5 × 2 × 5 × 2 × 3 × 2 × 2 = ...HOPE IT WILL HELP YoU

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Yogita Ingle 6 years, 11 months ago

Fundamental Theorem of Arithmetic states that every composite number greater than 1 can be expressed or factorised as a unique product of prime numbers except in the order of the prime factors.
The HCF of two numbers is equal to the product of the terms containing the least powers of common prime factors of the two numbers.
The LCM of two numbers is equal to the product of the terms containing the greatest powers of all prime factors of the two numbers.
The product of the given numbers is equal to the product of their HCF and LCM. This result is true for all positive integers and is often used to find the HCF of two given numbers if their LCM is given and vice versa. For any two positive integers a and b, HCF(a , b) x LCM(a , b) = a x b

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Tringle theroms

Posted by Shailendra Singh 6 years, 11 months ago

CBSE > Class 10 > Mathematics