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In chapter 14 how do we come to know that which method of mean we have to use if it is not given

Posted by Rohan Sachdeva 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Divya Garg 6 years, 10 months ago

when the frequency and the class intervals are small then the direct mean method is used.......if the class intervals are large and the height of class interval is same then the step deviation is used......and if the class intervals are large but height of the class interval is different then the assumed mean method is used where no height is required.......and if we have to find the value of 'x or y' then always use direct method......HOPE IT WILL HELP YOU!!

Gungun_ U Can Wish Me On 3 Feb? 6 years, 10 months ago

U cn use any..if it is not given

ANSWER

If length is increased by 60% then what %the breath have to reduce to maintain same area.it is rectangle

Posted by Ashish Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

The length of a rectangle is increased by 60% By what percent would the breath have to be decreased to maintain the same area?
Solution:
let X = the decimal equiv decrease of the width
:
Write an area equation
Original area = new area

L * W = 1.6L * XW
Divide both sides by LW
1 = 1.6 * X
divide both sides by 1.6
= X
x = .625,
new width = .625*old width, therefore
1 - .625 = .375 * 100 = 37.5 decrease in the width to have the same area

3Thank You

ANSWER

If the difference between the circumference and radius of a circle is 37cm,then find the circumference of circle

Posted by Nikhil Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

Let r be the radius of circle.
Difference between circumference and radius of circle = 37 cm
Circumference of circle = 2r
                                      = 2 x 22/7 x r = 44/7 x r
Now,
Difference between circumference and radius of circle = 2r - r
37 = 44/7 x r - r
37 = r(44/7-1)
37 = r(44 - 7)/7
37 = 37 / 7 x r
37 x 7/37 = r
r = 7 cm
Now , Circumference of circle = 44/7 x r
                                                 = 44/7 x 7
                                                 = 44 cm .
∴ Circumference of circle = 44 cm

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One years ago , a man was 8 times as old as his son . At present , his age is equal to the square of his son's age in years . Find their present age .

Posted by Uzzwal Upadhyay 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Saurabh Rajput 6 years, 10 months ago

Let the present age of man be x Let " " " " " of son be y Case 1 Present age =x=y2........1 Case 2 One year ago = x-1=8(y-1). ......2 When, we put the value of x in eq' no 2 Y2-1=8y-8 Y2-8y+7=0 Y2-7y-y+7=0 Y(y-7)-1(y-7)=0 (Y-1) (y-7)=0 The age of be 7 Then ,In eq no ..1 X=(7)2 X=49 Here the age of man is 49 Y=7,x=49

Gaurav Seth 6 years, 10 months ago

Let the age of the son one year ago be x years.
Age of the father one year ago = 8x years.

Present age of the father = 8x+1
Present age of the son = x+1
Given that (8x+1) = (x+1)²
(8x+1) = (x² + 2x + 1)
x² - 6x = 0
x(x - 6) = 0
x = 0 or x = 6

Son's age cannot be zero.

So, the present age of son is (x+1) i.e. 7 years.
Present age of the father = (8x+1) i.e. 49 years.

ANSWER

Every even number is a whole number

Posted by Sunny Brar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Khushi Thakur 6 years, 10 months ago

No... For example 3 is a whole number but it is not a even number

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Quickly answereded 1/sec-tan-1/cot =

Posted by Mr Manish Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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1/sec-tan-1/cot =

Posted by Mr Manish Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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If the total marks is 400 and marks secured is 359 then calculate the percentage?

Posted by Satyajeet Parida 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Bhavishya Kumar 6 years, 10 months ago

%age will be 89.75%

Hitesh Rajpurohit 6 years, 10 months ago

89.75

3Thank You

Harshita Srivastava 6 years, 10 months ago

The percentage will be 89.75%.

6Thank You

ANSWER

Find the lent of the longest roof that can be fit in a room of 10m.10m.5m dimensions

Posted by Gyas Alam 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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If equation is x2_6x+a it's zeroes is alpha and bita given 3a(alpha)+2b(bita)=20 find the value of a

Posted by Jatin Jatin Rankumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Krishna Kireeti 6 years, 10 months ago

For convenience, iam using a for alpha and b for beta. According to the question, 3a+2b=20 This can also be written as 2a+2b+a=20 So, 2(a+b)+a=20. Since a+b=6, 2(a+b)+a=12+a=20, a=8 Upon solving, b=-2 Therefore alpha=8 and Beta = -2 Here our assumption of a for alpha and b for beta ends. Now ALPHA×BETA=c/a 8×-2=a Therefore, a=-16

ANSWER

Roots of fraction alpha beeta product

Posted by Kratika Jhala 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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सिद्ध कीजिए √5 एक अपरिमेय संख्या हैं।यहाँँ से दशाईए कि 3√5-8 भी एक अपरिमेय संख्या है।

Posted by Deepak Soni 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Bpt theorem from chapter 6

Posted by Kunal Kunal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Avinash Saigal 6 years, 10 months ago

PROOF OF BPT Given: In ΔABC, DE is parallel to BC Line DE intersects sides AB and PQ in points D and E, such that we get triangles A-D-E and A-E-C. To Prove: ADBD=AECE Construction: Join segments DC and BE Proof: In ΔADE and ΔBDE, A(ΔADE)A(ΔBDE)=ADBD (triangles with equal heights) In ΔADE and ΔCDE, A(ΔADE)A(ΔCDE)=AECE (triangles with equal heights) Since ΔBDE and ΔCDE have a common base DE and have the same height we can say that, A(ΔBDE)=A(ΔCDE) Therefore, A(ΔADE)A(ΔBDE)=A(ΔADE)A(ΔCDE) Therefore, ADBD=AECE Hence Proved. This is base proportionality theorem. ??

Kratika Jhala 6 years, 10 months ago

If in triangli one line intersect each sides theh this triangle are divide in ratio whic are proptional to eaxh other

ANSWER

The sum of square of two consecutive multiples of 7 is 637. Find the multiple.

Posted by Arpit Jindal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Gouri Krishnan 6 years, 10 months ago

(7x) square +(7(x+1)) square= 637
49x^2 + 49(x+1)^2 =637
Taking 49 common
49( x^2 + x^2 +2x +1) = 637
2x^2 + 2x +1 = 637 / 49
= 13
2x^2 + 2x = 13 - 1
= 12
x^2 + x = 6
x (x + 1) =6
2 *3 6
So multiple s are 7x ie 7*2=14
And 21

Avinash Saigal 6 years, 10 months ago

we have given that sum of the squares of two consecutive multiples of 7 is 637. we have to find the numbers are ?? solution:- let the number multiple of. 7 = 7x then consecutive multiples of 7 = 7(x+1) now according to question (7x)² + {7 (x+1)}² = 637 = 49 x² + 49 (x+1)² = 637 = 49 x² + 49( x² +1+2x) = 98x² +98 x +49 = 637 = 98x² +98x = 637-49 = 588 => x² +x= 6. or = x² + x -6 =0 => x² +3x -2 x -6 = 0 => x(x+3) -2 (x+3) = 0 => x-2 =0. and x+3 = 0 => x= 2 and -3 answer hence (1) if x = 2 the number multiple of 7 is 7×2 =14 it's consecutive number multiple of 7 is = 7×(2+1) = 7×3 = 21 (2) if x =-3 the number multiple of 7 is 7×(-3) = -21 it's consecutive number multiple of 7 is = 7×(-3 +1) = 7× (-2) = -14 Thank you??

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Prove areas theorem

Posted by Rishabh Jain 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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In a square abcd 2 quadrants are drawn taking bc as radius find the areaof shaded region

Posted by Kanishka Vaishnav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Maximum ek dim me kitne hr padhna chahiye abhi?science ar maths dono

Posted by Aisha Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajneesh Baliyan 6 years, 10 months ago

15 hour

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7 time 7th term is equal to11 time 11th term find 18th term

Posted by Basat Ajay 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Kanishka Vaishnav 6 years, 10 months ago

7(a7)=11(a11).....7(a+6d)=11(a+10d).....7a+42d=11a+110d.......a-17d=0.......a18=0

3Thank You

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Introduction of trignometry all formulae

Posted by Harleen Kaur 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Avinash Saigal 6 years, 10 months ago

SinA = P / H CosA = B / H TanA = P / B CotA = B / P CosecA = H / P SecA = H/B Sin2A + Cos2A = 1 Tan2A + 1 = Sec2A Cot2A + 1 = Cosec2A In order to find a relationship between various trigonometric identities, there are some important formulas: 1. TanA = SinA / CosA 2. CotA = CosA / SinA 3. CosecA = 1 / SinA 4. SecA = 1 / CosA Thank you??

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State and prove thales theorem.

Posted by Aryan??? ??? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Dikshaa Chaudhary 6 years, 10 months ago

Thales theorem is BPT..and....it was given in textbook i.e N.C.E.R.T on pg no.124

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2 2 2 Sol: x- 4ax +4a - b = 0

Posted by Rahul Yadav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Which book is best for prActice

Posted by Aisha Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Poornima Singh 6 years, 10 months ago

NCERT

Nimesh Mandore 6 years, 10 months ago

Oswaal books

ANSWER

What is the hcf of smallest prime number and the smallest composit number

Posted by Mandeep Kaur 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Honey ??? 6 years, 10 months ago

Pratik Merani 6 years, 10 months ago

2 = 2 * 1 4 = 2 *2 Hcf = 2

Puja Sahoo? 6 years, 10 months ago

Lucifer ? Morningstar? 5 years, 8 months ago

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Anyone please tell me the time schedule.only one month is left for boards.i dont understand how i prepare

Posted by Aisha Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Puja Sahoo? 6 years, 10 months ago

Concentrate on studies, bt don't take stress

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Trigonometry samjha do

Posted by Rahul Yadav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Nimesh Mandore 6 years, 10 months ago

It is logical chapter .sin cos....are just names of different creatures . Practice chapter 8(8.4) and u will understand

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Two circle touch externally the sum of the area is 130πcm^2 and distance between there center is 14cm. Find radius of the circle.

Posted by Simran ????? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashish Chaudhary 6 years, 10 months ago

The radius of smaller circle & big circle is 3&11cm

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If the (m)th term of ap be 1/n and (n)th term be 1/m .then show that its (mn)th term is 1

Posted by Zeeshan Younis 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashish Chaudhary 6 years, 10 months ago

a+(m-1)d=1/n (i) & a+(n-1)d=1/m (ii) sub eq (ii) from (i) we get (m-n)d=1/n-1/m therefore ,d=1/mn put d value in (i) we get , a=1/mn ,see how,a+(m-1)1/mn=1/n , a+1/n-1/mn=1/n , a=1/mn , now, 1/mn+(mn-1)1/mn=1 , proved,?