Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Abhishek Maurya 6 years, 10 months ago
- 3 answers
Simran Phogat 6 years, 10 months ago
Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago
Posted by Deepu Done 6 years, 10 months ago
- 1 answers
Simran Phogat 6 years, 10 months ago
Posted by Reeta Panwar 6 years, 10 months ago
- 3 answers
Posted by Harjashan Singh 6 years, 10 months ago
- 3 answers
Posted by Dipanshu Khatana 6 years, 10 months ago
- 6 answers
Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago
Posted by Dipanshu Khatana 6 years, 10 months ago
- 5 answers
Khushnuda?Khushi ??? 6 years, 10 months ago
Posted by Shriram Tiwari 6 years, 10 months ago
- 3 answers
Posted by Soumojit Sarkar 6 years, 10 months ago
- 0 answers
Posted by Satys Singh 6 years, 10 months ago
- 2 answers
Simran Phogat 6 years, 10 months ago
Honey ??? 6 years, 10 months ago
Posted by Vibhav Jha 6 years, 10 months ago
- 3 answers
Rishab Jain 6 years, 10 months ago
Posted by Ankit Jaat 6 years, 10 months ago
- 6 answers
Posted by Sushant Chaubey 6 years, 10 months ago
- 5 answers
Sushant Chaubey 6 years, 10 months ago
Posted by Shashwat Singh 6 years, 10 months ago
- 4 answers
Vishakha Singh? 6 years, 10 months ago
Posted by Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago
- 0 answers
Posted by Vanshika Mehta 6 years, 10 months ago
- 4 answers
Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago
Posted by Gautav Barman 6 years, 10 months ago
- 2 answers
Posted by Utkarsh Patel 6 years, 10 months ago
- 2 answers
Yogita Ingle 6 years, 10 months ago
x2 - 2x - 8
= x2 - 4x + 2x - 8
= x(x - 4) + 2 ( x - 4)
= ( x + 2) (x - 4)
Posted by Abhishek Kumar 6 years, 10 months ago
- 1 answers
Rita Gokani 6 years, 10 months ago
Posted by Shreenidhi Karkun 6 years, 10 months ago
- 3 answers
Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago
Rita Gokani 6 years, 10 months ago
S N Mahato 6 years, 10 months ago
Posted by Tkdf Ghjg 6 years, 10 months ago
- 1 answers
Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago
Posted by Soumya Agrawal 6 years, 10 months ago
- 2 answers
Maisha Singh 6 years, 10 months ago
Posted by Super Singh 6 years, 10 months ago
- 0 answers
Posted by Aysha Shayan 6 years, 10 months ago
- 0 answers
Posted by Prashant Parihar 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
Let S1 be the sum of the first n even natural numbers.
Then, S1 = 2 + 4 + 6 + ....+ 2n
{tex}\Rightarrow{/tex} S1 = {tex}\frac{n}{2}{/tex}[2 {tex}\times{/tex} 2 + (n - 1)2]
{tex}\Rightarrow{/tex} S1 = {tex}\frac{n}{2}{/tex}[4 + 2n - 2] = n(n + 1) ........(i)
Let the S2 be the sum of the first n odd natural numbers.
Then, S2 = {tex}\frac{n}{2}{/tex}[2 {tex}\times{/tex} 1 + (n - 1)2] = n2
From (i),we have, {tex}{/tex} {tex}{/tex}{tex}S_1=n^2(1+\frac{1}{n})=(1+\frac{1}{n})n^2=(1+\frac{1}{n})S_2{/tex}
Therefore, the sum of first n even natural numbers is equal to (1 + {tex}\frac{1}{n}{/tex}) times the sum of the first n odd natural numbers {tex}=(1+\frac{1}{n})S_2{/tex}
Posted by Sreedeep Dev K 6 years, 10 months ago
- 1 answers
Puja Sahoo? 6 years, 10 months ago
Posted by Shallu Jaiswal 6 years, 10 months ago
- 3 answers
Anshika / U Can Call Me Alien ???? 6 years, 10 months ago
Posted by Guru Kiran Kr 6 years, 10 months ago
- 1 answers
Posted by Preet Kotiya 6 years, 10 months ago
- 1 answers
Posted by Niya Sharma 6 years, 10 months ago
- 1 answers
Madhur Dubey ??? 6 years, 10 months ago

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Miss Angel 6 years, 10 months ago
0Thank You