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Sia ? 6 years, 6 months ago
Let f(x) = 2x2- 5x - 3
Let the zeroes of polynomial be {tex}\alpha{/tex} and {tex}\beta{/tex}, then
Sum of zeroes = {tex}\alpha + \beta = \frac { 5 } { 2 }{/tex}
Product of zeroes = {tex}{/tex}{tex}\alpha \beta = - \frac { 3 } { 2 }{/tex}
According to the question, zeroes of x2+ px + q are {tex}2 \alpha \text { and } 2 \beta{/tex}.
{tex}\therefore\ {/tex} Sum of zeroes = {tex}{/tex}{tex}- \frac { \text { Coeff. of } x } { \text { Coeff of } x ^ { 2 } } = \frac { - p } { 1 }{/tex}
{tex}\Rightarrow{/tex} -p = {tex}2 \alpha + 2 \beta = 2 ( \alpha + \beta ){/tex}
{tex}{/tex}{tex}\Rightarrow\ {/tex} -p= {tex}2 \times \frac { 5 } { 2 } = 5{/tex} or p = -5
Now ,Product of zeroes = {tex}\frac { \text { Constant term } } { \text { Coeff of } x ^ { 2 } } = \frac { q } { 1 }{/tex}
{tex}\Rightarrow{/tex} q = {tex}2 \alpha \times 2 \beta = 4 \alpha \beta{/tex}
{tex}\Rightarrow{/tex} q = {tex}4 \left( - \frac { 3 } { 2 } \right){/tex} = -6
{tex}\therefore{/tex} p = -5 and q = -6
Posted by Xyz Abc 6 years, 10 months ago
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Amrish Chaubey 6 years, 10 months ago
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Ram Kushwah 6 years, 10 months ago
Download from:
https://www.vedantu.com/previous-year-question-paper/cbse-maths-class-10-year-2015
Posted by Rishi Sanganeria 6 years, 10 months ago
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Ram Kushwah 6 years, 10 months ago
{tex}\begin{array}{l}let\;\alpha,\beta,\gamma\;are\;zeros\\hen\;\alpha+\beta+\gamma=-\frac{-3}1=3\\or\;a-b+a+a+b=3\\3a=3\;so\;\;a=1\\\alpha\beta\gamma=-\frac11=-1\\so\;a(a-b)(a+b)=-1\\a(a^2-b^2)=-1\\1(1-b^2)=-1\\b^2=2\\b=\pm\sqrt2,a=1\end{array}{/tex}
Posted by Xyz Abc 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
The polynomial with all the coefficients as zeros is called a zero polynomial.
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Anushka Jugran_? 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
When 3 unbaised coins are tossed, the total number of events = 8
They are {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
At most two heads
That is no head or one head or 2 heads
Probability of getting at most two heads = 7/8
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