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  • 3 answers

Priya Mahajan 2 years, 4 months ago

On contrary, let's assume √3 is rational So we can write it as of p/q where q is not equal to zero. Suppose p and q have a common factor other than 1, so on dividing it by that factor we get √3 = a/b , where a and b are coprime. So a = √3b -----(I) Squaring both sides, we get, a^2= 3b^2 So a^2 is divisible by 3 => a is divisible by 3 => a =3c Substitute in (i), we get, 3c=√3b => 9c^2= 3b^2 => 3c^2= b^2 => b^2 is divisible by 3 So b is divisible by 3 So, a and b have at least 3 as common factor But this contradicts that a and b are coprime So our assumption is wrong So √3 is irrational.

Saraswati Kumari 2 years, 4 months ago

Yes it is irrational

Simran Singh 2 years, 4 months ago

Yes it's a irrational number
  • 2 answers

Naresh Yadav 2 years, 4 months ago

Plumbum

Omya Aryan 2 years, 4 months ago

N/2[2a+(n-1)d] OR N/2(a+l)
  • 1 answers

Priya Mahajan 2 years, 4 months ago

-3√3/2 + 13/3
  • 4 answers

Saraswati Kumari 2 years, 4 months ago

Cot theta

Muthu Siva Pradeeban 2 years, 4 months ago

Cot theta

Omya Aryan 2 years, 4 months ago

1

Sushila Thakur 2 years, 4 months ago

Tantheta
  • 1 answers

Priya Mahajan 2 years, 4 months ago

x is 14/5 and y is 5/7
  • 1 answers

Preeti Dabral 2 years, 4 months ago

Let the required point on the x-axis be P(x, 0). Then,
PA = 5 PA2 =25
 (x - 5)2 + (0 + 3)2 = 25
 x2-10x + 25 + 9 =25 x2 - 10x + 9 =0
 x2 - x - 9x + 9 = 0  x(x -1) -9(x - 1)=0
(x - 1) (x -9) =0  x - 1 =0 or x - 9 =0
 x = 1 or x = 9.

  • 1 answers

Rajat Singh 2 years, 4 months ago

Hello dost We can do this by using contradiction We will prove that it is not rational then it will be irrational Let it be rational 1/√2 = p/q √2 = q/p Since b and a are integers, b/a is a rational number and so, √2 is rational. But we know that √2 is irrational. So, our assumption was wrong. Therefore, 1/√2 is an irrational number.
  • 1 answers

Maira Khanna 2 years, 5 months ago

xtan45 0 .cot60 0 =sin30 0 .csc60 0 ⇒x.1. 3 ​ 1 ​ = 2 1 ​ × 3 ​ 2 ​ ⇒x=1 Hence, the answer is 1.
  • 3 answers

Bhoomi Mandoliya 2 years, 4 months ago

Sn=n/2(2a+(n-1)d here a=5 d 2 so = 60/2( 2x5+60-1) 2=30(10+118) = 30x 128=3840

Vivek Prajapati 2 years, 4 months ago

Pahale d check Karo sahi hai ki nahi

Ashish Sparsh 2 years, 5 months ago

As Sn=n/2(2a+(n-1)d) Here, a=5 d=7-5=2 So, S⁶⁰=60/2(2×5+(60-1)2) =30(10+118) =30×128 =3840
  • 3 answers

Bhoomi Mandoliya 2 years, 4 months ago

2x2x3x7x5

Yashasvi Shringi 2 years, 4 months ago

2×2×3×7×5

Sristi Singh 2 years, 5 months ago

2 x 2 x 3 x 7 x 5
  • 2 answers

Sandeep Tiwari 2 years, 5 months ago

Area of triangle 1/2×bc×ab-1/2πrsquare

Sandeep Tiwari 2 years, 5 months ago

Area of triangle 1/2×bc×ab
  • 4 answers

Phur Lhamu Sherpa 2 years, 4 months ago

Upper limit+lower limit 2

Mohd Atif Idrisi 2 years, 5 months ago

X2 + X1/2 & Y2 + Y1/2

Vivek Prajapati 2 years, 5 months ago

x2 + X1 divided by 2

Gaurav Kumar 2 years, 5 months ago

1+2
  • 3 answers

Bhoomi Mandoliya 2 years, 4 months ago

,0.141

Lucky Keshari 2 years, 5 months ago

O.141

Vivek Prajapati 2 years, 5 months ago

0.141
  • 4 answers

Shlok Patel 2 years, 5 months ago

Hii

Juber Pathan 2 years, 5 months ago

1 quiction help

Deepanshu Baisla 2 years, 5 months ago

Hlo

Suswant Kumar 2 years, 5 months ago

Hlo
  • 1 answers

Geetdarshan Kashyap 2 years, 5 months ago

d=1/2 and three more terms are 4,9/2,5.
  • 2 answers

Vicky Ronghang 2 years, 5 months ago

Mention three results of swadeshi movement

Vivek Prajapati 2 years, 5 months ago

Write complete question
  • 0 answers
  • 0 answers
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  • 1 answers

Vibha .. 2 years, 5 months ago

Cosec¤+cot¤=3x +3/x ---(i) Cosec¤-cot¤=3x+3/x ---(ii) Multiply corresponding sides of (i)and( ii) Cosec^2-cot^2=3×3(x^2 -1/x^2) 1/3= 3(x^2-1/x^2)

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