CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Distace between the points (x, y) and (a+b, b-a) & (a-b, a+b) is equal

⇒ √{[x - (a + b)]² + [y - (b -a)]²} = √{x - (a - b)]² + [y - (a + b)]²}

⇒ x² + (a + b)² - 2x(a + b) + y² + (b - a)² - 2y(b - a) = x² + (a - b)² - 2x(a - b) + y² + (a + b)² - 2y(a + b)

⇒ -2ax - 2bx - 2by + 2ay = - 2ax + 2bx - 2ay - 2by
⇒ ay - bx = bx - ay
⇒ 2ay = 2bx
⇒ bx = ay

Hence proved.

1Thank You

ANSWER

difference between tan p and tan r

Posted by Rahul Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Archana☺ Singh 6 years, 10 months ago

Figure bhi hoga

1Thank You

ANSWER

What is the formula for area of sector and segment

Posted by Divya Gautam 5 years, 8 months ago

CBSE > Class 10 > Mathematics

5 answers

Puja Sahoo? 6 years, 10 months ago

Formula of segment.....??

1Thank You

Puja Sahoo? 6 years, 10 months ago

Pie r^2theta/360-[1/2r^2sinTheta]

1Thank You

Priyan?? ? 6 years, 10 months ago

I think it will help you a lot

1Thank You

Priyan?? ? 6 years, 10 months ago

Area of Segment = θ − sin(θ)2 × r2 (when θ is in radians) Area of Segment = ( θ × π360 − sin(θ)2 ) × r2

1Thank You

Priyan?? ? 6 years, 10 months ago

Area of Sector = θ × π360 × r2 (when θ is in degrees)

1Thank You

ANSWER

If cos+sin=√2cos then prove that cos-sin=√2sin ?

Posted by Kirti Dhillon 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 6 years, 10 months ago

Let θ = x

cos x + sin x = √2 cos x

squaring on both side, we get......

cos2x + sin2x + 2cosxsinx = 2cos2x

2sinxcosx = 2cos2x - cos2x - sin2x

2sinxcosx = cos2x - sin2x

2sinxcosx = (cosx+sinx) (cosx - sinx)

2sinxcosx = (root2 cosx) (cosx - sinx)

2sinxcosx/root2 cosx = cosx - sinx

√2 sinx = cosx - sinx

1Thank You

Puja Sahoo? 6 years, 10 months ago

Hey, scroll down ek aisa hi question ka answer dia hai maine

1Thank You

ANSWER

Maths NCERT of class 7 of chapter perimeter and area

Posted by John Abraham 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Sejal Barge 6 years, 10 months ago

Jao

1Thank You

Sejal Barge 6 years, 10 months ago

Class 7 mai jau

1Thank You

Puja Sahoo? 6 years, 10 months ago

Class 7.... nhi ye class 10 hai???

1Thank You

ANSWER

If x=y^z , y=z^x , z=x^y then find xyz

Posted by Gagan Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Ram Kushwah 6 years, 10 months ago

{tex}\begin{array}{l}\mathrm x=\mathrm y^{\mathrm z},\mathrm y=\mathrm z^{\mathrm x},\mathrm z=\mathrm x^{\mathrm y}\\\mathrm{xyz}=\mathrm x^{\mathrm y}\mathrm y^{\mathrm z}\mathrm z^{\mathrm x}\\\mathrm{xyz}=\mathrm{xyz}(\mathrm x^{\mathrm y-1}\mathrm y^{\mathrm z-1}\mathrm z^{\mathrm x-1})\\\mathrm{or}\;\mathrm x^{\mathrm y-1}\mathrm y^{\mathrm z-1}\mathrm z^{\mathrm x-1}=1\\\frac{\mathrm x^{\mathrm y}\mathrm y^{\mathrm z}\mathrm z^{\mathrm x}}{\mathrm{xyz}}=1\\\mathrm{So}\;\;\mathrm{xyz}=\mathrm x^{\mathrm y}\mathrm y^{\mathrm z}\mathrm z^{\mathrm x}\end{array}{/tex}

1Thank You

Gagan Singh 6 years, 10 months ago

Kya

2Thank You

Sejal Barge 6 years, 10 months ago

Tujya i chi bhook

1Thank You

ANSWER

Two water taps together can fill a tank in 6 hours the tap of larger diameter takes 9 hours less than the smaller one to fill the tank separately .find the time in which each tap can separately fill the tanm.

Posted by Mahendra Pal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Swetanshu Kumar 6 years, 10 months ago

letr time taken by smaller tap be x time taken by larger tap= x-9 1/x+1/x-9=1/6 x-9+x/x^2-9x =1/6 2x-9/x^2-9x = 1/6 6(2x-9)= x^2-9x 12x-54 = x^2-9x x^2-9x-12x+54 = 0 x^2-21x+54=0 x^2-18x-3x+54=0 x(x-18)-3(x-18)=0 (x-18)(x-3)=0 x=18 or 3 x=18 time taken by smaller tap =18 hrs. time taken by larger tap= 9 hrs.

0Thank You

ANSWER

Two tangents TP and tq are drawn to a circle with centre o from an external point t prove that angle PTQ = 2angleOPQ

Posted by Mayank Meel 6 years, 10 months ago

CBSE > Class 10 > Mathematics