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Gaurav Seth 6 years, 10 months ago
A(7,-2), B(5,1), C(3,2K)
Δ = 1/2[(x₁y₂+x₂y₃+x₃y₁)-(x₂y₁+x₃y₂+x₁y₃)
Δ = 1/2[(7+10K-6)-(-10+3+14K)] = 1/2[1+10K+7-14K] = 1/2[8-4K] = 4-2K
GIVEN THE POINTS ARE COLLINEAR
Δ = 0
4-2K = 0
2K = 4
K = 2
Anushka K 6 years, 10 months ago
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Posted by Vivek Sharma 6 years, 10 months ago
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Gaurav Seth 6 years, 10 months ago
Let V be the volume of the frustum of cone. Then,
V = Volume of cone V AB
– Volume of cone VA ‘B’

Thus, the volume of the frustum of the cone is given by


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