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  • 1 answers

Saloni Kalra 6 years, 10 months ago

And Oswal nahi h mere pas...
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  • 0 answers
  • 1 answers

Anushka Jugran ? 6 years, 10 months ago

Question sahi to hai na... Khair iska answer to 11/5 aa rha hai shayad
  • 2 answers

Sw Kkk 6 years, 10 months ago

Marathi ka paper

Sw Kkk 6 years, 10 months ago

5 ko hai bhai
  • 1 answers

Jiya Arora????? 6 years, 10 months ago

First convert cotA + cosecA -1/cotA-cosecA+1 in sinA, cosA and 1 Then rationalise it u will get the answer
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  • 1 answers

Shweta Singh 6 years, 10 months ago

if 4,x1,x2,x3,28 are in AP then x3=?
  • 1 answers

Shivam Tripathi 6 years, 10 months ago

Queation me given rahta hai like rut 2 is irrational and question of 4 / 5 marks then pruf rut is irrational other wise don't pruf
  • 2 answers

Khushi Agrawal 6 years, 10 months ago

=[CosA—SinA +1/CosA+Sin—1]×[CosA +SinA +1/CosA +SinA +1] =[Cos²A+CosA.SinA+CosA—CosA.SinA—Sin²A—SinA+CosA+SinA+1]/(CosA+SinA)²—(1)² =[Cos²A+2CosA+1—Sin²A]/[Cos²A+Sin²A+2SinACosA—1]---- [:CosA.SinA—CosA.SinA=0, SinA—SinA=0] ----=[2Cos²A+2CosA]/[1—1+2SinA.CosA]---- [:1—Sin²A=Cos²A and Cos²A+Sin²A=1] =[2CosA(CosA+1)/[2SinA.CosA] =CosA+1/SinA---- ----[2CosA/2CosA=1] =CosA/SinA+1/SinA =CotA+CosecA, Hence Prooved

Deepanshi Mittal 6 years, 10 months ago

It's N.C.E.R.T ques
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  • 1 answers

Sw Kkk 6 years, 10 months ago

What english???
  • 3 answers

Deepanshi Mittal 6 years, 10 months ago

BPT ,converse of BPT , Pythagoras , Area theorems Ex 6.5 13,14,15,16 sums

Puja Sahoo? 6 years, 10 months ago

All theorem specially, bpt and pythagoras

Aditya Kishore 6 years, 10 months ago

All theorems are important and related to their questions
  • 3 answers

Deepanshi Mittal 6 years, 10 months ago

Please send the solution

Nidhi Chaudhary 6 years, 10 months ago

a=1 nd b=0

Puja Sahoo? 6 years, 10 months ago

Use, ar. of triangle =0.... and then yu will find value of b put it in given eq. yu will get the answer
  • 2 answers

Rita Gokani 6 years, 10 months ago

am=1/n, an=1/m a + (m-1)d = 1/n a + (n-1)d = 1/m By solving we get d=1/mn Also a=1/mn Then, S(mn)=mn/2[2(1/mn)+(mn-1)1/mn] =mn/2[2/mn +1 - 1/mn] =mn/2[2/mn-1/mn+1] =mn/2(1/mn+1) by multiplying =mn/2×1/mn+mn/2+1 LCM =1/2 +mn+2/2 =mn+2/2 =1/2mn +1 Hope u understood

Nanu Parjapat 6 years, 10 months ago

Yd7373uh3
  • 2 answers

Adiii Agrawal 6 years, 10 months ago

How

H@Rdik K@Shy@P. Csk Is Best 6 years, 10 months ago

X^2_ 10x+13
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Harshita Srivastava 6 years, 10 months ago

p=1/2 and q=-3/2 Verify- px2+3x+2q =1/2x2+3x+2.-3/2 =x2+6x-6 Sum of zeroes=-b/a=-6 Product of zeroes=c/a=-6

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