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Yogita Ingle 6 years, 10 months ago
Here 225 > 135 we always divide greater number with smaller one.
Divide 225 by 135 we get 1 quotient and 90 as remainder so that
225= 135*1 + 90
Divide 135 by 90 we get 1 quotient and 45 as remainder so that
135= 90*1 + 45
Divide 90 by 45 we get 2 quotient and no remainder so we can write it as
90 = 2*45+ 0
As there are no remainder so deviser 45 is our HCF
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Gaurav Seth 6 years, 10 months ago
Let 2x + 3y = 8 be eq(i) and 4x + 6y = 7 be eq(ii).
Now, From eq(i),
2x + 3y = 8
2x = 8 - 3y
x = (8 - 3y)/2
Putting the Value of x in eq(ii),
4x + 6y = 7
4(8 - 3y)/2 + 6y = 7
2(8 - 3y) + 6y = 7
16 - 6y + 6y = 7
16 = 7
16 - 7 = 0
9 = 0
That is not true.
From the Calculations, We can see that the Equations has no solution.
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Raj Pandey 6 years, 10 months ago
0Thank You