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  • 1 answers

Kamboj Ji 6 years, 10 months ago

In a cyclic quad we know that sum of opp angle=180 So, 3y-5+(-7x+5)=180,(eq..1) 4y+20+(-4x)=180,(eq..2) Now from eq 1, 3y-5-7x+5=180, 3y-7x=180, From eq 2, 4y-4x=160, X-y=40, Using any method we will get x=-15 and y=25, substitute the value and result will come
  • 1 answers

Sia ? 6 years, 4 months ago

Let the speed of the train be x km/h and the time taken by train to travel the given distance be t hours and the distance to travel be d km.
Since, Speed = {tex}\frac{{{\text{Distance travelled}}}}{{{\text{Time taken to travel that distance}}}}{/tex} {tex} \Rightarrow x = \frac{d}{t} \Rightarrow{/tex} d = xt ....(1)
According to the question,
x + 10 = {tex}\frac{d}{{t - 2}} \Rightarrow{/tex} (x + 10)(t - 2) = d
{tex}\Rightarrow{/tex} xt + 10t - 2x - 20 = d
{tex}\Rightarrow{/tex} -2x + 10t = 20 .....(2) [Using eq. (1)]
Again, x - 10 = {tex}\frac{d}{{t + 3}} \Rightarrow{/tex} (x - 10)(t + 3) = d
{tex}\Rightarrow{/tex} xt - 10t + 3x - 30 = d
{tex}\Rightarrow{/tex} 3x - 10t = 30 .....(3) [Using eq. (1)]
Adding equations (2) and (3), we obtain:
x = 50
Substituting the value of x in equation (2), we obtain:
(-2) {tex}\times{/tex} (50) + 10t = 20 {tex}\Rightarrow{/tex}-100 + 10t = 20
{tex}\Rightarrow{/tex}10t = 120
t = 12
From equation (1), we obtain:
d = xt = 50 {tex}\times{/tex} 12 = 600
Thus, the distance covered by the train is 600 km.

  • 1 answers
Take x=2+√3 and 2-√3 , then shift rhs to lhs and multiply both equaton to get a other eqn. then divide the poly. by this poly. and factorise the quotient
  • 1 answers

Puja Sahoo? 6 years, 10 months ago

a=1, b= +_ root 2
  • 1 answers

Sia ? 6 years, 4 months ago

Since {tex}\left(1,\frac p3\right){/tex}, is the mid point of the line segment joining the points (2,0) and {tex}\left( 0 , \frac { 2 } { 9 } \right){/tex}.
{tex}\therefore \quad \quad \frac { p } { 3 } = \frac { 0 + \frac { 2 } { 9 } } { 2 }{/tex}
{tex} \frac { 2 p } { 3 } = \frac { 2 } { 9 }{/tex}
{tex}p = \frac { 1 } { 3 }{/tex}
Now the given points are (-1, 3p). Let x = -1 , y = 3p
Hence, y = 3 {tex}\times{/tex} {tex}\frac13{/tex} = 1
The equation to prove is: 5x + 3y + 2 = 0
L.H.S. 
= 5x + 3y + 2
Put the values of x & y,
= 5(-1) + 3(1) + 2 = -5 + 3 + 2 = -2 + 2 = 0 = R.H.S.
Hence, the line 5x + 3y + 2 = 0 passes through the point (–1, 1) as 5(–1) + 3(1) + 2 = 0.

  • 3 answers
Infinity-1=oo ,oo+2=oo ,oo-7=oo so common diff. Will be 0(zero)

Puja Sahoo? 6 years, 10 months ago

No value of x.....???
X=oo (infinity)
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  • 1 answers

Gaurav Seth 6 years, 10 months ago

<pre>  </pre>

Since cos A + cosA=1 

Now,cosA= 1-cos2A=sin2A

Then  taking L.H.S. sin2A+sin4A

=Sin2A(1+sin2A)

=CosA(1+cosA)

CosA+cos2A=1(given)

L.H.S =1 Hence proved

  • 1 answers

Gaurav Seth 6 years, 10 months ago

Question: Show that n (m2-1 ) = 2m , if sin theta + cos theta = m and sec theta + cosec theta = n

Answer:

  • 2 answers

Somu Sinha 6 years, 10 months ago

Since cos( 90 - thita)= sin thita. Cos(90 - 67)= sin. Therefore, sin 23° -sin23°=0

Affu 😊 6 years, 10 months ago

0
  • 1 answers

Jogendra Nonia 6 years, 10 months ago

Total surface area of remaining solid =CSA of cylinder+area if circle+CSA of cone =2pi rh +pi r^2+ pi rl 2×3.14×8×15 +3.14×8×8 +3.14×8×17 3.14×8(2×15+8+17) 3.14×8×55 314×44= 13816cm^2
  • 1 answers

Sia ? 6 years, 4 months ago

As, volume of hemisphere = 2425{tex}\frac { 1 } { 2 } c m ^ { 3 }{/tex}
{tex}\Rightarrow \frac { 2 } { 3 } \pi r ^ { 3 } = 2425 \frac { 1 } { 2 }{/tex}
{tex}\Rightarrow \frac { 2 } { 3 } \times \frac { 22 } { 7 } r ^ { 3 } = \frac { 4851 } { 2 }{/tex}
{tex}\Rightarrow r ^ { 3 } = \frac { 4851 \times 3 \times 7 } { 2 \times 2 \times 22 }{/tex}
{tex}\Rightarrow r ^ { 3 } = \frac { 441 \times 3 \times 7 } { 2 \times 2 \times 2 }{/tex}
{tex}\Rightarrow r ^ { 3 } = \frac { 21 ^ { 3 } } { 2 ^ { 3 } }{/tex}
{tex}\Rightarrow r = \frac { 21 } { 2 } c m{/tex}
So, the curved surface area of the hemisphere ={tex}2 \pi r ^ { 2 }{/tex}
{tex}= 2 \times \frac { 22 } { 7 } \times \frac { 21 } { 2 } \times \frac { 21 } { 2 } = 693 \mathrm { cm } ^ { 2 }{/tex}

  • 3 answers

Preeti Rahi 6 years, 10 months ago

Thanks

Sneha Singh?????? 6 years, 10 months ago

Undefined

Ajay Papnai 6 years, 10 months ago

Infinity
  • 1 answers

Garima Choudhary 6 years, 10 months ago

In the stastics graf if it has only one slope than we fnd N/2 and mark the point on graf after that join the point to x-axis hence this will the median . In case of less than and more than ogive, the point of their intersection will be joind to x-axis that point on x-axis will be median
  • 1 answers

Lucky? Dangi 6 years, 10 months ago

a5 =0 a + 4d =0 a = -4d a33 = 4(a12) a+ 32d = 4( a+11d) put the value of a -4d + 32d= 4(-4d+11d) 28d= -16d + 44d 28d = 28d H.P.
  • 2 answers

Lucky? Dangi 6 years, 10 months ago

thanks bhai..

Pallavi Verma 6 years, 10 months ago

153= 85 *1 + 68 85 = 68 * 1+17 68 =17 *4 +0 Now the remainder is zero HCF =17 85m - 153 85m-153 =17 85m =153 +17 85m = 170 m = 170/85 m = 2
  • 2 answers

Pallavi Verma 6 years, 10 months ago

No it's (alpha +1)(beta+1)=1-c.. ☺️

Lucky? Dangi 6 years, 10 months ago

i think its( alpha +1) (beta+1)= 1- c+ p
  • 1 answers

Jasline Sandhu????? 6 years, 10 months ago

What is happening
  • 2 answers

Abhishek Rai 6 years, 10 months ago

Area of the corresponding sector-Area of the corresponding triangle

Sw Kkk 6 years, 10 months ago

For minor it is ar.of sector-ar.of triangle For majorar.of circle-ar.of sector
  • 2 answers

Abhay Modi 6 years, 10 months ago

(a+b) ka whole square nikalna hai toh :: (a+b)^2 = a^2+b^2+2ab hoga

Ujjwal Kumar 6 years, 10 months ago

2a+2b

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