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  • 1 answers

#Miss_Raagini ???? 6 years, 9 months ago

let the time taken by the 1 pipe be x hours and let the time taken by the 2 pipe be y hours. & the in 1 hour the 1 pipe can fill it=1/x the in 1 hour the 2 pipe can fill it=1/y 1/x +1/y = 1/12           -1 4/x = 9/9 =1/2             -2 let 1/x be a and 1/y be b. a+b= 1/12             -3 4a + 9b = 1/2         -4 multiply 3 by 4 and then subtract 5 and 6. 4a +4b=1/3       -5 4a + 9b = 1/2     -6 we get, b=1/30 y=30. sustituting the value of y in eq. 3 a+1/30=1/12 x=20. Hence the 1 pipe would take 20hours and the 2 pipe would take 30 hours.
  • 3 answers

#Miss_Raagini ???? 6 years, 9 months ago

5/4 dear.

Akshay Agarwal 6 years, 9 months ago

Ans is 5/4

Harsimran Singh ? 6 years, 9 months ago

5/4
  • 2 answers

Diksha Kharwal 6 years, 9 months ago

15.6 cm2 is the answer

Puja Sahoo? 6 years, 9 months ago

15.6 cm^2
  • 1 answers

Ankit Raj 6 years, 9 months ago

And where's the second number.
  • 0 answers
  • 0 answers
  • 1 answers

Noor Mehta 6 years, 9 months ago

Ncert example no. 13 page no.148. Pls check
  • 1 answers

Ramesh Singh 6 years, 9 months ago

Both r same
  • 0 answers
  • 3 answers

Gungun ? 6 years, 9 months ago

No....but if yu attempt in serial wise manner..then it will b easy for d examiner 2 check yur sheet...so better 2 do in series

Siddhartha Jain 6 years, 9 months ago

Actually if we do answer in series to checker ko acha lagta h au unhe copy check ke rs bhi milte hn to wo chahte hn ki jyada se jyada copy check kren aur series m krne se sir thodi loose checking bhi krte hn.

Diksha Kharwal 6 years, 9 months ago

Noo
  • 3 answers

Siddhartha Jain 6 years, 9 months ago

Ya vaibhav- diksha is right

Diksha Kharwal 6 years, 9 months ago

Eg-1, 5,7,11and so on

Diksha Kharwal 6 years, 9 months ago

Two natural numbers are called co prime numbers if there hcf is one not necessarily prime
  • 3 answers

Diksha Kharwal 6 years, 9 months ago

Yes Siddharth is saying right

Siddhartha Jain 6 years, 9 months ago

Actually es ques. M bs diagram banana thoda sa complicated h baaki simple h

Diksha Kharwal 6 years, 9 months ago

Its too easy aap previous year paper k solutions m jao vhaa apko mil jayega
  • 3 answers

Diksha Kharwal 6 years, 9 months ago

Thanks manisha

Usha ❤❤❤ 6 years, 9 months ago

Its correcy diksha

Diksha Kharwal 6 years, 9 months ago

Because 12 has not 2 and 5 its prime factor so 12n can't end with digit 0 and 5
  • 1 answers

Diksha Kharwal 6 years, 9 months ago

What is the figure???
  • 1 answers

Sia ? 6 years, 4 months ago

Given points are collinear. Therefore

[p {tex}\times{/tex} n + m(q - n) + (p - m) q] - [m {tex}\times{/tex} q + (p - m) n + p (q - n)] = 0
{tex}\Rightarrow{/tex} (pn + qm - mn + pq - mq) - (mq + pn - mn + pq - pn) = 0
{tex}\Rightarrow{/tex} (pn + p q - mn) - (mq - mn + pq) = 0
{tex}\Rightarrow{/tex} pn - mq = 0
{tex}\Rightarrow{/tex} pn = qm

  • 1 answers

Diksha Kharwal 6 years, 9 months ago

Yess
  • 3 answers

Diksha Kharwal 6 years, 9 months ago

Put a=12 ,d=4 and an=248

Rohit Mandal 6 years, 9 months ago

A.p series 12,16,20.............248

Diksha Kharwal 6 years, 9 months ago

60
  • 1 answers

Sahil Rajput 6 years, 9 months ago

Ye to 12.2 ka hy ncert
  • 2 answers

Samyukta ... 6 years, 9 months ago

Page number 208 aur 209

Samyukta ... 6 years, 9 months ago

Ismai theorem 10.1 prove krna hai
  • 3 answers

Khushi Modi 6 years, 9 months ago

Then give the answer

Khushi Modi 6 years, 9 months ago

So please tell how to solve this question

Anikait Garg 6 years, 9 months ago

So easy
  • 1 answers

Sia ? 6 years, 4 months ago

Given: Right triangles {tex}\triangle ABC{/tex} and {tex}\triangle DBC{/tex} are drawn on the same hypotenuse BC on the same side of BC.
Also, AC and BD intersect at P.
To Prove: {tex}A P \times P C = B P \times P D{/tex}
Proof: In {tex}\triangle BAP{/tex} and {tex}\triangle CDP{/tex}, we have
{tex}\angle B A P = \angle C D P = 90 ^ { \circ }{/tex}
{tex}\angle B P A = \angle C P D{/tex} (vertically opposite angles)
{tex}\therefore \quad \triangle B A P \sim \triangle C D P{/tex} [by AA-similarity]
{tex}\therefore \quad \frac { A P } { D P } = \frac { B P } { C P }{/tex}
{tex}\Rightarrow A P \times C P = B P \times D P{/tex}
{tex}\Rightarrow A P \times P C = B P \times P D{/tex}
Hence, {tex}A P \times P C = B P \times P D{/tex}.

  • 4 answers

Honey ??? 6 years, 9 months ago

Mid no. Of all integers

Samyukta ... 6 years, 9 months ago

Natural number

Samyukta ... 6 years, 9 months ago

Integer

Samyukta ... 6 years, 9 months ago

Whole number

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