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  • 3 answers

Aditya Choudhary 6 years, 9 months ago

Check this question in this app for more information. In mathematics column exercise 2.4 question no. 4 ya 5 hoga

Puja Sahoo 6 years, 9 months ago

Ncert book bhi khol lo

Honey ??? 6 years, 9 months ago

X ^2 -(sum of 0s)x +(product of 0s)
  • 0 answers
  • 2 answers

Ashish Agrawal 6 years, 9 months ago

To prove - 22/7 is a rational number. So first recall the definition of a rational number that is- " A rational number can be represented in the form of p/q where p and q are integers and q#0". Also- "Decimal expansion of rational no . is either terminatinating or repeating" . So here in this case 22 and 7 are integers . 7#0 And also - Decimal expansion of 22/7 is 3.14285714 that is nothing but terminating . Hence , by both the ways 22/7 is a rational number.

Happy Sin 6 years, 9 months ago

hemce proved
  • 3 answers

Manav Kakkar 6 years, 9 months ago

123

Kaira Chauhan 6 years, 9 months ago

123....

Yasmine ♥️ 6 years, 9 months ago

123
  • 1 answers

Sia ? 6 years, 4 months ago

Let the present ages of B and A be x years and y years respectively.
Then,
B's age 5 years ago = {tex}(x - 5) years{/tex}
and A's age 5 years ago = {tex}(y - 5) years.{/tex}
{tex}\therefore{/tex} {tex}(y - 5) = 3(x - 5){/tex} {tex}\Rightarrow{/tex}{tex}3x  -y = 10{/tex} .... (i)
B's age 10 years hence = {tex}(x +10) years{/tex}.
A's age 10 years hence = {tex}(y +10) years{/tex}.
{tex}\therefore{/tex} {tex}(y + 10) = 2(x + 10){/tex} {tex}\Rightarrow{/tex} {tex}2x - y = - 10{/tex} ..... (ii)
On subtracting (ii) from (i), we get x = 20.
Putting x = 20 in (i), we get
(3{tex}\times{/tex}20) - y = 10 {tex}\Rightarrow{/tex}y = 60 -10 = 50.
{tex}\therefore{/tex} x = 20 and y = 50.
{tex}\text{Hence, B's present age = 20 years}{/tex}
{tex}\text{and A's present age = 50 years.}{/tex}

  • 1 answers

Shalbi Kumari 6 years, 9 months ago

K=7.5 and m=9 Since we know that sum of zeros is equal to -(co- efficient of x)/ co- efficient of x sq. And product of zeros is equal to constant term(c)/co efficient of x sq.
  • 2 answers
Aree newcomer hoga

Isha Kapoor 6 years, 9 months ago

Mathematics exam is over
  • 3 answers

Aarmaan Bedil 6 years, 9 months ago

Ya.......

Isha Kapoor 6 years, 9 months ago

Are you there

Isha Kapoor 6 years, 9 months ago

Whatttttt......
  • 0 answers
  • 2 answers

Nikhil 6 years, 9 months ago

-b/a = a + b............. c/a = ab........................... a = alpha and b= beta

Piyush Raghuwanshi 6 years, 9 months ago

-b by a = alpha and c by a = beta ,aata toh hai nhi kuch
  • 4 answers

Pushpraj Pandey 6 years, 9 months ago

Mehar Danish Mallick thank you for telling me the answer

Mehar Danish Mallick 6 years, 9 months ago

x² + 5x + 4 has zeroes α and β then, value of = {1/α + 1/β - 2 • αβ} Solution:- {x² +5x + 4} α+β = -b/a (sum of the zeroes) α+β = -5/1 [α+β = -5]............(i) α•β = c/a (product of the zeroes) αβ = 4/1 [αβ = 4]................(ii) Now taking , = 1/α + 1/β - 2 • αβ = β+α/αβ - 2 • αβ (taking LCM) = α+β/αβ - 2 • αβ = (-5)/(4) - 2 • (4) (from i and ii) = -5/4 - 8 = -5 -32 / 4 (taking LCM) = -37/4 = -9.25 [Ans] Hence , the required value is {-37/4 OR -9.25}

Nitin Kumar ✨✨?????✨✨ 6 years, 9 months ago

Soryy

Nitin Kumar ✨✨?????✨✨ 6 years, 9 months ago

Bs ab tension krne ki baat nahi hai
  • 1 answers

Yasmine ♥️ 6 years, 9 months ago

Google it
  • 1 answers

Ram Kushwah 6 years, 9 months ago

cosec2A=Cot2A+1

sin2A=1/(Cot2A+1)----------(1)

sec2A=1+tan2A=1+1/cot2A

tanA=1/cotA

  • 3 answers

Nitin Kumar ✨✨?????✨✨ 6 years, 9 months ago

RD

Aarmaan Bedil 6 years, 9 months ago

Rd.............

Aadrika Srivastava 6 years, 9 months ago

Tell me also
  • 4 answers

Tejaswini Chhetri 6 years, 9 months ago

Ya happy holi and may god bless us with flying colors in our upcoming boards

Puja Sahoo? 6 years, 9 months ago

Same 2 u

Priyanshi Khandelwal 6 years, 9 months ago

Same to you sanjana ji

Nitin Kumar ✨✨?????✨✨ 6 years, 9 months ago

Same 2 u
  • 2 answers

Isha Kapoor 6 years, 9 months ago

What

Aarmaan Bedil 6 years, 9 months ago

You also ask a question..... ??
  • 5 answers

Puja Sahoo? 6 years, 9 months ago

Yep....

Ruchi ?? 6 years, 9 months ago

Hlo..Isha ji

Isha Kapoor 6 years, 9 months ago

Hello

Rose? (Kannu?) 6 years, 9 months ago

Hello isha

Nitin Kumar ✨✨?????✨✨ 6 years, 9 months ago

Yah!
  • 1 answers

Sia ? 6 years, 4 months ago

Given equations, 
{tex}2 x - y - 2 = 0{/tex}
{tex}4x + 3y - 24 = 0{/tex}
{tex}y + 4 = 0{/tex}

We have, {tex}2x - y - 2 = 0{/tex} or {tex}x = {{y+2}\over2} {/tex}
When y = 0, we have {tex}x = {{0+2}\over2} = 1{/tex}
When x = 0, we have y = -2.
Thus, we obtain the following table giving coordinates of two point on the line represented by the equation {tex}2x - y - 2 = 0{/tex} and its graph is shown below.

x 1 0
y 0 -2

Now we have, {tex}\begin{array}{l}4x+3y-24=0\Rightarrow y=\frac{24-4x}3\\\end{array}{/tex}
When y = 0, we have x = 6
When x = 0, we have y = 8
Thus, we obtain the following table giving coordinates of two points on the line represented by the equation {tex}4x + 3y - 24 = 0{/tex} and its graph is shown below.

x 6 0
y 0 8

Also we have {tex}y + 4 = 0{/tex}
Clearly, y = - 4 for every value of x.
So, let E(2, -4) and F(0, -4) be two points on the line represented by y + 4 = 0. Plotting these points on the same graph and drawing a line passing through them, we obtain the graph of the line represented by the equation y + 4 = 0 as shown in Figure.



From Fig. we have {tex}\begin{array}{l}\bigtriangleup PQR\\\end{array}{/tex} having vertices P(3,4), Q(-1,-4) and R(9, -4). 

Also, PM = 8 and QR = 10.
{tex}\therefore \quad \text { Area of } \triangle P Q R = \frac { 1 } { 2 } ( \text { Base } \times \text { Height } ){/tex}
{tex}\Rightarrow \quad \text { Area of } \triangle P Q R = \frac { 1 } { 2 } ( Q R \times P M ) = \frac { 1 } { 2 } ( 10 \times 8 )sq.\ units{/tex}
{tex}\Rightarrow \quad \text { Area of } \triangle P Q R = 40 \mathrm { sq } .units.{/tex}

  • 2 answers

Kaira Chauhan 6 years, 9 months ago

Itna bhi nhi aata kyaa Nursery nhi padhi Bura mt manna meri baato ka agar bura lga ho toh sorry??

Chaithanya Sreedharan 6 years, 9 months ago

0
  • 3 answers

Nikhil 6 years, 9 months ago

Exam ho gaya?????????

Anup Lonare 6 years, 9 months ago

12 std ki maths me dekho

No One Cares ???About Me 6 years, 9 months ago

Not in syllabus
  • 1 answers

Chaithanya Sreedharan 6 years, 9 months ago

Take the ratio k:1 and find k in both x and y if the values of k is same that means they are collinear

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