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Ask QuestionPosted by Anant Mandal 6 years, 9 months ago
- 1 answers
Posted by Biswa Ranjan Bagarty 6 years, 9 months ago
- 0 answers
Posted by Niharika Pandey 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
a ÷ (b + c) = 12 ÷ [(–4) + 2] = 12 ÷ (–2) = –6
(a ÷ b) + (a ÷ c) = 12 ÷ (–4) + (12 ÷ 2) = –3 + 6 = 3
So, a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
Posted by Debu Biswas 6 years, 9 months ago
- 2 answers
Posted by Pratyush Padhy 6 years, 9 months ago
- 1 answers
Yogita Ingle 6 years, 9 months ago
By Euclid's Division Algorithm,
237 = 81(2) + (75)
81 = 75(1) + (6)
75 = 6(12) + (3)
6 = 3(2) + (0)
Hcf = 3
Posted by Dimple Chordia 6 years, 9 months ago
- 0 answers
Posted by Soubhagya Kumar Sahoo 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
{tex}3x+2y=11{/tex}........(i)
{tex}2x+3y=4{/tex}.......(ii)
Multiplying (i) by 3 and (ii) by 2, we get
{tex}9x+6y=33{/tex}........(iii)
{tex}4x+6y=8{/tex}........(iv)
Subtracting (iv) from (iii), we ge
{tex}5x=25\Rightarrow x=5{/tex}
Substituing x = 5 equation in (i), we get
{tex}3(5)+2y=11\Rightarrow15+2y=11\Rightarrow 2y=-4 \Rightarrow y=-2{/tex}
Hence, the solution of the given system of equations is x = 5, y = -2
Posted by Jp Chaturvedi 6 years, 9 months ago
- 1 answers
Posted by Marshmallow Sharma 6 years, 9 months ago
- 2 answers
Posted by Krishu Bawankar 6 years, 9 months ago
- 1 answers
Ram Kushwah 6 years, 9 months ago
S1=n/2(10+(n-1)*2)
S2=n/2(10+(n-1)*4)
S3=n/2(10+(n-1)*6)
S1+S3=n/2[20+(n-1)(2+6)]
=n/2(2*10+(n-1)*2*4)
=2*n/2(10+(n-1)*4)
=2*S2
S1+S3=2S2
Posted by Aniket Kashyap 6 years, 9 months ago
- 0 answers
Posted by Karthigaijothi S 6 years, 9 months ago
- 1 answers
Ram Kushwah 6 years, 9 months ago
Let the no. are x,y
so xy=56
x2+y2+x+y=128
(x+y)2-2xy+x+y=128
Ley x+y=m
m2-2*56+m=128
m2+m-240=0
m2+16m-15m-240=0
m(m+16)-15(m+16)=0
(m+16)(m-15)=0
m=15 or -16
x+y=15 or -16
xy=56
If x+y=15 Then x=8,y=7
Also
sum of no+sum squares=128
x+x/56+x2+x2/562=128
57x/56+x2+x2/3136=128
Multiply by 3136
56*57x+3136x2+x2=128*3136
3192x + 3137x2-
Posted by Aniket Kashyap 6 years, 9 months ago
- 0 answers
Posted by Aniket Kashyap 6 years, 9 months ago
- 2 answers
Gungun Lalwani ? 6 years, 9 months ago
Posted by Akanksha Verma 6 years, 9 months ago
- 0 answers
Posted by Aarmaan Bedil 6 years, 9 months ago
- 1 answers
Posted by Ajay Sangwan 6 years, 9 months ago
- 1 answers
Shabnam Star 6 years, 9 months ago
Posted by Maddala Jatin 6 years, 9 months ago
- 1 answers
Ram Kushwah 6 years, 9 months ago
Let the point on x axis is A (x,0) Let Bis (-11,8)
AB^2=(x+11)^2+(0-8)^2
172=x2+22x+121+64
x2+22x+185-172=0
x2+22x-104=0
x2+26x-4x-104=0
x(x+26)-4(x+26)=0
(x+26)(x-4)=0
x=-26 or 4
So Coordinates of the said two pints are
(-26,0) and (4,0)
Posted by Unnati Kestwal 6 years, 9 months ago
- 2 answers
Sudha Sudha 6 years, 9 months ago
Posted by Garima Kakati 6 years, 9 months ago
- 1 answers
Ram Kushwah 6 years, 9 months ago
√49/√147
=7/√49x3
=7/7√3
=1/√3
=√3/3 is a irrational( as √3 is irrational)
Posted by Anup Lonare 6 years, 9 months ago
- 1 answers
Posted by Heart ? Hacker 6 years, 9 months ago
- 1 answers
Ram Kushwah 6 years, 9 months ago
Very nice question
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All the best.
Posted by Ashutosh Kumar 6 years, 9 months ago
- 1 answers
Vineeta 123456789 6 years, 9 months ago
Posted by Vivek Sharma 6 years, 9 months ago
- 0 answers
Posted by Syed Ali 6 years, 9 months ago
- 1 answers
Posted by Science S 6 years, 9 months ago
- 1 answers
Posted by Sudha Sudha 6 years, 9 months ago
- 1 answers
Yogita Ingle 6 years, 9 months ago
first term=a=8
nth term=l=33
Sum to first n terms = Sn = 123
Sn = [n(a + l)]2
123 = n(41)/2
n = 6
l = a + [n - 1]d
33 = 8 + 5d
d=5
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Sia ? 6 years, 4 months ago
Let a number of humans be x and deer be y.
then, {tex}x + y = 39{/tex} ....(i)
and {tex}2x + 4y = 132{/tex}
{tex}x + 2y = 66{/tex} .....(ii)
On solving (i) and (ii), we get
{tex}-y = - 27{/tex}
{tex}\Rightarrow{/tex} y = 27, x = 12
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