Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by National Gamers 6 years, 5 months ago
- 1 answers
Posted by Elyas Nasir Khan 6 years, 5 months ago
- 0 answers
Posted by Ashraful Hassan 6 years, 5 months ago
- 1 answers
Sia ? 6 years, 5 months ago
f(x) =4x2- 8kx + 8x - 9
= 4x2+ (8- 8k)x - 9
Let one zero = {tex}\alpha{/tex}
{tex}\therefore{/tex}other zero = -{tex}\alpha{/tex}[A.T.Q.]
Now Sum of zeroes ={tex}\frac { - b } { a }{/tex}
{tex}\Rightarrow \quad \alpha + ( - \alpha ) = \frac { - ( 8 - 8 k ) } { 4 }{/tex}{tex}\Rightarrow 0 = \frac { - 8 + 8 k } { 4 }{/tex}
{tex}\Rightarrow{/tex}-8 + 8k = 0 {tex}\Rightarrow{/tex}k = 1
Polynomial p(x) = kx2 + 3kx + 2
becomes p(x) ={tex}1 \times x ^ { 2 } + 3 \times x + 2{/tex} [Using k = 1]
= x2 + 3x + 2
For zeroes of p(x),x2 + 3x + 2 = 0
{tex}\Rightarrow{/tex} (x + 2)(x + 1) = 0
{tex}\Rightarrow{/tex} x = - 2,x = - 1
Posted by Ashraful Hassan 6 years, 5 months ago
- 4 answers
Tec Om 6 years, 5 months ago
Tec Om 6 years, 5 months ago
Posted by Jasmeen Aulakh 6 years, 5 months ago
- 2 answers
Posted by Kavya Khurana 6 years, 5 months ago
- 0 answers
Posted by Anshika Bharti 6 years, 5 months ago
- 1 answers
Mohammad Amaan 6 years, 5 months ago
Posted by Anmol Randhawa 6 years, 5 months ago
- 1 answers
Rajan Kumar Pasi 6 years, 5 months ago
Didn't you study well, very easy question? looks like you are not trying to make it by yourself first.
Question: Find the value of positive values of m for which the distance between the points A(5,-3)B(13,m)is 10 unit?
Solution: Here it is given that the distance between AB is 10, then using the distance formula.
{tex}\large AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}{/tex}
{tex}\large 10=\sqrt{(13-5)^2+(m-(-3))^2}{/tex}
{tex}\large 100={64+(m+3)^2}{/tex}
{tex}\large 100-64=36=(m+3)^2{/tex}
{tex}\large \pm6=m+3{/tex}
{tex}\large Now,m=6-3\space\space\space\space or\space\space\space\space m=-6-3{/tex}
{tex}\large Now,\boxed {m=3}\space\space\space\space or\space\space\space\space\boxed {m=-9}{/tex}
Posted by Digvijay Patil 6 years, 5 months ago
- 3 answers
Posted by Digvijay Patil 6 years, 5 months ago
- 3 answers
Posted by Madhav Meena 6 years, 5 months ago
- 1 answers
Mohammad Amaan 6 years, 5 months ago
Posted by Nitin Yadav 6 years, 5 months ago
- 2 answers
?? D ?? 6 years, 5 months ago
Posted by Shivam Kumar 6 years, 5 months ago
- 1 answers
Posted by Sumit Grewal 6 years, 5 months ago
- 1 answers
Rajan Kumar Pasi 6 years, 5 months ago
Very easy question
i think we can do it like this,
(X-A)(X-B)(X-C)....(X-Y)(X-Z)
= (X-A)(X-B)(X-C)(X-D)....(X-W)(X-X)(X-Y)(X-Z)
= (X-A)(X-B)(X-C)(X-D)....(X-W)(0)(X-Y)(X-Z) (since X-X = 0)
= 0 [Product of any term multiplied with zero always results in zero].
Hence the answer is 0.
Posted by Shivangi Singh 6 years, 5 months ago
- 1 answers
Posted by Ilma Mashkoor 6 years, 5 months ago
- 1 answers
Rajan Kumar Pasi 6 years, 5 months ago
Try to imagine the question in a different way.
Solution:
{tex}\huge\implies \alpha-1+\beta-1\\ \huge\implies\alpha+\beta-1-1\\ \huge\implies(\alpha+\beta)-2{/tex}
{tex}\huge\implies Since,\alpha+\beta=-\frac ba\\ \huge\implies (given)\space\space a=1,b=-3\\ \huge\implies Thus,(\alpha+\beta)-2\implies-\frac{-3}{1}-2\\ \huge\implies 3-2\implies\boxed1{/tex}
Posted by Shruti Aggarwal 6 years, 5 months ago
- 1 answers
Gaurav Seth 6 years, 5 months ago
Question: If 0.3528 is expressed on the form p/2m 5n, find the smallest value of n,m and p .
Explanation:
Posted by Bharat Malik 6 years, 5 months ago
- 2 answers
Posted by Bharat Malik 6 years, 5 months ago
- 2 answers
Posted by Rishab Sharma 6 years, 5 months ago
- 1 answers
Sia ? 6 years, 5 months ago
Let the costs of the full fare be Rs x and that of the reservation charge be Rs. y. Then,
{tex}x + y = 216{/tex} ...(i) [given]
And, {tex}(x + y) + \left( {\frac{1}{2}x + y} \right) = 327{/tex} [given]
{tex}x + y + \frac{1}{2}x + y = 327{/tex}
{tex}\Rightarrow x + \frac{1}{2}x + 2y = 327{/tex}
{tex}\Rightarrow \frac{{3x}}{2} + 2y = 327{/tex}
{tex}\Rightarrow{/tex} {tex}3x + 4y = 654{/tex} ...(ii)
Multiplying equation (i) by 4, we get
{tex}4x + 4y = 864{/tex} ....(iii)
Subtracting equation (ii) from equation (iii), we get
{tex}4x - 3x = 864 - 654{/tex}
{tex}\Rightarrow{/tex} {tex}x = 210{/tex}
Putting {tex}x = 210{/tex} in equation (i), we get
{tex}210 + y = 216{/tex}
{tex}\Rightarrow{/tex} {tex}y = 216 - 210 = 6{/tex}
Hence, the cost of the full fare ={tex} Rs. 210{/tex} and, the cost of the reservation charge = {tex}Rs. 6{/tex}.
Posted by K.R. Rohith 6 years, 5 months ago
- 1 answers
Sia ? 6 years, 5 months ago
Let a = bq + r : b = 2
0 {tex} \leqslant {/tex} r < 2 i.e., r = 0, 1
a = 2q + 0, 2q + 1,
If a = 2q (which is even)
If a = 2q + 1 (which is odd)
So, every positive even integer is of the form 2q and odd integer is of the form 2q + 1.
Posted by Ananya Mehta 6 years, 5 months ago
- 1 answers
Sia ? 6 years, 5 months ago
2032 = 1651 {tex} \times{/tex} 1 + 381 .
1651 = 381 {tex} \times{/tex} 4 + 127
381 = 127 {tex} \times{/tex} 3 + 0.
Since the remainder becomes 0 here, so HCF of 1651 and 2032 is 127.
{tex} \therefore{/tex} HCF (1651, 2032) = 127.
Now,
{tex} 1651 = 381 \times 4 + 127{/tex}
{tex} \Rightarrow \quad 127 = 1651 - 381 \times 4{/tex}
{tex} \Rightarrow \quad 127 = 1651 - ( 2032 - 1651 \times 1 ) \times 4{/tex} [from 2032 = 1651 {tex} \times{/tex} 1 + 381]
{tex} \Rightarrow \quad 127 = 1651 - 2032 \times 4 + 1651 \times 4{/tex}
{tex} \Rightarrow \quad 127 = 1651 \times 5 + 2032 \times ( - 4 ){/tex}
Hence, m = 5, n = -4.
Posted by Vansh Saharawat 6 years, 5 months ago
- 1 answers
Rajan Kumar Pasi 6 years, 5 months ago
try to solve this problem using examples given just before Exercise-10.2
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Masum Ansari 6 years, 5 months ago
0Thank You