CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Large scale participation of women was an important feature of the Civil Disobedience Movement. During the Salt March, thousands of women came out of their homes to listen to the speeches of Gandhi. women participated in protest marches, manufactured salt, and picketed foreign cloth and liquor shops. Many went to jail. While women of high caste families participated from urban areas, in rural areas they came from rich peasant households.
But this did not bring about any radical changes in the positin of women. For a long time the Congress was reluctant to allow women to hold any position of authority within the organisation.

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Which chapter is main for final examination

Posted by Neer Beniwal 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Find the gcd by Euclid method ( 44 , 233)

Posted by Ansh Virvadiya 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Prashant Thakur 6 years, 5 months ago

H. C. F is 2

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Give 5 5 equation of subsitution method and elimination methos

Posted by Dj Productions 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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What will be the number of real zeroes of the polynomial x^+1

Posted by Pragya Narayan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Solve x^2+x^6-x^7 & Higher Degree

Posted by Arsh Kumar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Find the quadratic polynomial whose zero are (5+2√3) and(5-2√3)

Posted by Pragya Narayan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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N Pranav Tej 6 years, 5 months ago

x^2-10x+13

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Solve the pair of linear equation by the substitution method 3x_y=3;9x_3y=9

Posted by Wilson Rahul 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Pradhyumna Rajput 6 years, 5 months ago

From the equation (1), y=(3x-3) Substituting this value of y in (2), 9x-3(3x-3)=9 9x-9x+9=9 9=9

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3 x square minus x minus 2 is equal to zero solve this by using the method of completing the square

Posted by Sagar Khan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sanket Arjun 6 years, 5 months ago

3x^2-x-2=0 Dividing the equation by 3 X^2-x/3 -2/3=0 X^2-x/3+1/36=2/3+1/36 {adding 1/36 on both side} (X-1/6)^2=25/36 X-1/6=5/6 X=5/6+1/6 X=1

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Solve each of the following equation by using the method of completing the square 3 x square minus x minus 2 is equal to zero

Posted by Sagar Khan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Raghu Chaubey 6 years, 5 months ago

3x square- x-2=0 3×sqare-x=2 Xsqare-x/3=2/3 Xsquare×-x/6whole square=2/3× x/6whole square X-x/6 ka whole square=2/3×x square/36 X-x/6= underroot2/3×x/6 Now put the values x=x/6 and x=-x/6

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In an A.P., if a=15,d=-3 and a n =0,then find the value of n

Posted by Sakshi Sakshi 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Arsh Kumar 6 years, 5 months ago

n=6

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The numbers 525 and 3000 are both divisible only by 3,5,15,25 and 75. What is HCF(525,3000)? Justify your andwer.

Posted by Anna Shivani 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Nm ???? 6 years, 5 months ago

If it comes in 1 marks than u will directly write 75 becoz hcf is the highest commomn factor and there is given that 525and 3000 both r divisible by 3,5,1525,75 ,here highest factor is 75 and when it is come in 3 marks then solve by euclid divission lemma

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find A is a tan 2A= cot (A-24)

Posted by Vishnu Prakasan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Nm ???? 6 years, 5 months ago

Tan 2A= cot(A_24) Cot(90-2A)= cot(A-24) Cot se cot cut jayga then next step 90-2A=A-24 90+24=A+2A 144=3A 144÷3=A 38=A

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How to prove rational numbet

Posted by Angelin Grace 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Write the discriminant of the quadratic (x+5)2=2(5x-3)

Posted by Ankit Kumar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Gaurav Seth 6 years, 5 months ago

Given a quadratic equation :

x² + bx + c = 0

The discriminant is given by:

d = b² - 4ac

Where a , b and c are constants.

From the question we have :

(x + 5)² = 2(5x - 3)

x² + 10x + 25 = 10x - 6

Collecting the like terms together we have :

x² + 10x + 25 - 10x + 6 = 0

x² + 31 = 0

In our case :

b = o

c = 31

a = 1

Doing the substitution we have :

d = - 4 × 1 × 31 = -124

= -124

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A number consists of two digits . When the number is divided by the sum of its digits , quotient is 7. If 27 is subtracted from the number , the digits interchange. What is the number?

Posted by Manoj Kumar Pandey 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 5 months ago

Let unit digit=x
tens digit=y
number=10y+x
(10y+x)/x+y =7 (1)
10y+x-27=10x+y
9y-9x-27=0
y-x-3=0
from (1) 10y+x=7x+7y
3y=6x
y=2x
2x-x-3=0
x=3,y=6
number=63

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draw a circle of radius 3 centimetre take two points P and Q on our with their accident on both sides Each Other deserves are the opposite sides of its Centre draw tangent from list two points

Posted by Gowri Shankar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 5 months ago

Question: Draw a circle of radius 3 cm. Take two points P and Q on one of its extended diameter each at a distance of 7 cm from its centre. Draw tangents to the circle from these two points P and Q.

Explanation:

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Find x if -4 +(-1) +2 +........+x =437

Posted by Mitra Suresh 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sia ? 6 years, 5 months ago

(-4) + (-1) + 2 + 5 + ---- + x = 437.
Now,
-1 - (-4) = -1 + 4 = 3
2 - (-1) = 2 + 1 = 3
5 - 2 = 3
Thus, this forms an A.P. with a = -4, d = 3,l = x
Let their be n terms in this A.P.
Then,
S_n = {tex}\frac { n } { 2 } [ 2 a + ( n - 1 ) d ] {/tex}
{tex}\Rightarrow 437 = \frac { n } { 2 } [ 2 \times ( - 4 ) + ( n - 1 ) \times 3 ]{/tex}
{tex}\Rightarrow{/tex} 874 = n[-8 + 3n - 3]
{tex}\Rightarrow{/tex}874 = n[3n - 11]
{tex}\Rightarrow{/tex}874 = 3n² - 11n
{tex}\Rightarrow{/tex}3n² - 11n - 874 = 0
{tex}\Rightarrow{/tex}3n² - 57n + 46n - 874 = 0
{tex}\Rightarrow{/tex}3n(n - 19) + 46(n - 19) = 0
{tex}\Rightarrow{/tex}3n + 46 = 0 or n = 19
{tex}\Rightarrow n = - \frac { 46 } { 3 }{/tex} or n = 19
Numbers of terms cannot be negative or fraction.
{tex}\Rightarrow{/tex} n = 19
Now, S_n = {tex}\frac { n } { 2 } [ a + l ]{/tex}
{tex}\Rightarrow 437 = \frac { 19 } { 2 } [ - 4 + x ]{/tex}
{tex}\Rightarrow - 4 + x = \frac { 437 \times 2 } { 19 }{/tex}
{tex}\Rightarrow - 4 + x = 46{/tex}
{tex}\Rightarrow x = 50{/tex}

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How many terms of the A.P -15, -11, -7, ....... are needed to make the sum 744 ?

Posted by Mitra Suresh 6 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Mohammad Amaan 6 years, 5 months ago

a=-15, d=-11+15=4 , Sn=744 Sn=n/2{2a+(n-1)d} , n/2{-30+(n-1)4}=744 , n/2(-30+4n-4)=744 , n(-34+4n)=1488 , 4n^2-34n-1488=0 , 2n^2-17n-744=0 , 2n^2-48n+31n-744=0 , 2n(n-24)+31(n-24)=0 , (n-24)(2n+31)=0. , n=24 or n=-31/2(which is not possible). Hence,n=24

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Mohammad Amaan 6 years, 5 months ago

24 terms.

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Check graphically whether the pair of equations 3x - 2y + 2=0 and 3/2 x - y + 3=0 is consistent. Also, find the coordinates of the points, where the graphs of equations meet the y-axis

Posted by Ritik Raj 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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An A.P consists of 60 terms. If the first and last term is 7 and 125 respectively. Find 32 term

Posted by [email protected] Arora 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sakshi Moon 6 years, 5 months ago

we have, a=7 an=125 and n=60 d=? And a32=? Solution an=a+(n-1)d 125=7+(60-1)d 125=7+59d 125-7=59d 118=59d ;d=2 a32 =a+31d a32=7+31.2 a32= 69

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Sin ©

Posted by Abdul Kadir 6 years, 5 months ago

CBSE > Class 10 > Mathematics

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Paramesh Parameshwari 6 years, 5 months ago

Sin by cos

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If alpha and beta are zeros of quadratic polynomial X square + X - 2 find the value of one upon Alpha minus one upon beta

Posted by Ishita Sharma 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Since, {tex}α{/tex} and {tex}β{/tex} are the zeroes of the quadratic polynomial.
We have,
f(x) = x² + x - 2
{tex}\Rightarrow{/tex}x² + x - 2 = 0
{tex}\Rightarrow{/tex}x² + 2x - x - 2 = 0
{tex}\Rightarrow{/tex}x(x +2) -1(x + 2) = 0

{tex}\Rightarrow (x-1)(x+2)=0{/tex}

{tex}\Rightarrow x-1=0 \ and \ x+2=0{/tex}
{tex}\Rightarrow{/tex}x = 1 and x = -2
{tex}\therefore \alpha = -2, \beta = 1{/tex}
So,
{tex}\frac{1}{\alpha } - \frac{1}{\beta }{/tex}
{tex}= \frac{{\beta - \alpha }}{{\alpha \beta }}{/tex}
= {tex}\frac{{1 + 2}}{{2(- 1)}} = - \frac{3}{2}{/tex}

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x-7y-7=0 3x-3y-15=0

Posted by Akash Gc 6 years, 5 months ago

CBSE > Class 10 > Mathematics