No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question

    • Posted by Noor Wraich 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Urja Patwary 6 years, 5 months ago

    2xcube+2xsquare+xsquare+x-6x-6 2x^2(x+1)+x(x+1)-6(x+1) 2x^2+4x-3x-6(x+1) 2x(x+2)-3(x+6)(x+1) (2x-3)(x+6)(x+1) Therefore the zeros are- (3/2),(-6),(-1).

    1Thank You

    ANSWER

    • Posted by Ankur Tiwari 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Anil Yadav 6 years, 5 months ago

    2x+5x+3y = 7x+ 3y

    1Thank You

    Prachi Yadav?? 6 years, 5 months ago

    7x+3y

    1Thank You

    ANSWER

    • Posted by Tanish Binayke 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anjana Ghosh 6 years, 5 months ago

    divisibility test of 13 is the number in the 13 table is the divisibility test of 13

    0Thank You

    ANSWER

    • Posted by Ravikant Prajapati 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Darshan Darshan 6 years, 5 months ago

    irrational

    0Thank You

    ANSWER

    • Posted by Anand Dwivedi 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    Given points are collinear. Therefore

    [p {tex}\times{/tex} n + m(q - n) + (p - m) q] - [m {tex}\times{/tex} q + (p - m) n + p (q - n)] = 0
    {tex}\Rightarrow{/tex} (pn + qm - mn + pq - mq) - (mq + pn - mn + pq - pn) = 0
    {tex}\Rightarrow{/tex} (pn + p q - mn) - (mq - mn + pq) = 0
    {tex}\Rightarrow{/tex} pn - mq = 0
    {tex}\Rightarrow{/tex} pn = qm

    1Thank You

    ANSWER

    • Posted by Ritu Mahajan 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    {tex}\frac{1}{{64}}{/tex}

    0Thank You

    ANSWER

    • Posted by Lõvêrbôy Vîshãl 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    Let n = 4q + 1 (an odd integer)
    {tex}\therefore \quad n ^ { 2 } - 1 = ( 4 q + 1 ) ^ { 2 } - 1{/tex}
    {tex}= 16 q ^ { 2 } + 1 + 8 q - 1 \quad \text { Using Identity } ( a + b ) ^ { 2 } = a ^ { 2 } + 2 a b + b ^ { 2 }{/tex}
    {tex}= 16{q^2} + 8q{/tex}
    {tex}= 8 \left( 2 q ^ { 2 } + q \right){/tex}
    = 8m, which is divisible by 8.

    0Thank You

    ANSWER

    • Posted by Dibyaranjan Nayak 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Rajnandini Jaiswal 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sandeep Dubey 6 years, 5 months ago

    This is not time of geometric construction Its is time of Ap real no polynomial

    0Thank You

    ANSWER

    • Posted by Guna Sekaran 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Resham Verma 6 years, 5 months ago

    5×7×11×13

    0Thank You

    Harshita Vatyani 6 years, 5 months ago

    5×7×11×13

    0Thank You

    Sohil M 6 years, 5 months ago

    5×7×11×13

    2Thank You

    Ayush Sahu 6 years, 5 months ago

    5 . 7. 11. 13

    1Thank You

    ANSWER

    • Posted by Raman Virk 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Raman Virk 6 years, 5 months ago

    It is incorrect

    0Thank You

    Babul Singh 6 years, 5 months ago

    12h+24h=36h??

    0Thank You

    ANSWER

    • Posted by Divya Angnani 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Yogita Ingle 6 years, 5 months ago

    2x2 + kx - 3 = 0
    Comparing equation with ax2 + bx + c = 0, we get
    a = 2, b = k and c = -3
    Discriminant = b2 - 4ac

    = (k)2 - 4(2) (-3)
    = k2 + 24
    For equal roots,
    Discriminant = 0
    k2 + 24 = 0
    k2 = - 24
    k = -√24 = -2√6

     

    0Thank You

    ANSWER

    • Posted by Kalpit Goyal 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Dibyaranjan Nayak 6 years, 5 months ago

    x+5x=24 =>6x=24 =>x=24/6 =>x=4 x=4,5x=5×4 =20

    0Thank You

    ANSWER

    • Posted by Aman Beniwal 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Nm ???? 6 years, 5 months ago

    Then do it by long divison method then we can find the hcf

    7Thank You

    Nm ???? 6 years, 5 months ago

    Firstly take the biggest no. As a dividend and the smallest no. As a divisor then divide simply

    0Thank You

    ANSWER

    • Posted by Yashashvi Jaiswal 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Nm ???? 6 years, 5 months ago

    Phle root2 ko irrational prove kro uske bad root 3 ko irrational prove kro use bad hm dekh skte h ki dono irrational prove ho gye use bad hm write krege irrational +irrational =irrational fr ik irrational k nitche root2 write krege +dsre irratinal k nitche root 3 write krege =irrational then we see that both prove irrational

    0Thank You

    Hardik Singh 6 years, 5 months ago

    By contradiction method

    0Thank You

    ANSWER

    • Posted by Ananthrama Bhimanna 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sanket Arjun 6 years, 5 months ago

    80 and 40

    0Thank You

    ANSWER

    • Posted by Tushar Kakran 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Sagar Av 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Jashan Singh 6 years, 5 months ago

    65

    1Thank You

    ANSWER

    • Posted by Sagar Av 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    {tex}\because{/tex} x = {tex}\frac{2}{3}{/tex} is a root of {tex}ax^2 + 7x + b = 0{/tex}
    {tex}\therefore{/tex} a({tex}\frac{2}{3}{/tex})2 + 7{tex}\times{/tex}{tex}\frac{2}{3}{/tex} + b = 0
    {tex}\Rightarrow{/tex}{tex}\frac{4a + 42 + 9b}{9}{/tex} = 0 {tex}\Rightarrow{/tex} {tex}4a + 9b + 42 = 0{/tex} ...(i)
    Also x = 3 is a root
    {tex}\therefore{/tex} {tex}a(3)^2 + 7\times3 + b = 0{/tex}
    {tex}\Rightarrow{/tex}{tex}9a + b + 21 = 0{/tex}
    {tex}\Rightarrow{/tex}{tex}9(9a + b + 21) = 9\times0{/tex}
    {tex}\Rightarrow{/tex}{tex}81a + 9b + 189 = 0 {/tex}...(ii)
    (ii) and (i), we get

    {tex}\Rightarrow{/tex} 77a = -147 {tex}\Rightarrow{/tex} a = {tex}\frac{-147}{77}{/tex} = {tex}\frac{-21}{11}{/tex}
    When a = {tex}\frac{-21}{11}{/tex}, eq.(i) becomes
    -4{tex}\times{/tex}{tex}\frac{21}{11}{/tex} + 9b + 42 = 0
    {tex}\Rightarrow{/tex}{tex}\frac { - 84 + 99 b + 462 } { 11 }{/tex} = 0
    {tex}\Rightarrow{/tex}99b + 378 = 0 b = {tex}\frac{-378}{99}{/tex} = {tex}\frac{-42}{11}{/tex}
    {tex}\therefore{/tex} a = {tex}\frac{-21}{11}{/tex}, b = {tex}\frac{-42}{11}{/tex}.

    1Thank You

    ANSWER

    • Posted by Nandini Rathod 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Mukesh Mire 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Vibha Kumari Pehu 6 years, 5 months ago

    For any positive integers a and b where A greater than B than there exist Q and R such that a = bq +r

    0Thank You

    Kartikeya Kotkar 6 years, 5 months ago

    a =bq + r

    1Thank You

    ANSWER

    • Posted by Abhishek Patel 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Aaryan Gole 6 years, 5 months ago

    1.414 (approx.)

    0Thank You

    P. Nitish Kumar 6 years, 5 months ago

    1.414

    0Thank You

    ANSWER

    • Posted by Shubham Yadav 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    S1 = 1 + 2 + 3 + ....n
    S2 = 1 + 3 + 5 + ...upto n terms
    S3 = 1 + 4 + 7 + ...upto n terms
    {tex}S _ { n} = \frac { n } { 2 } [ 2a + ( n - 1 ) d ]{/tex}
    {tex}S _ { 1} = \frac { n } { 2} [ 2 (1) + ( n - 1 ) 1 ]{/tex}
    {tex}S _ { 1} = \frac { n } { 2} [ 2 + n - 1 ]{/tex}
    or, {tex}S _ { 1 } = \frac { n ( n + 1 ) } { 2 }{/tex}
    Also, {tex}S _ { 2 } = \frac { n } { 2 } [ 2 \times 1 + ( n - 1 ) 2 ]{/tex}
    {tex}S _ { 2 } = \frac { n } { 2 } [ 2 + 2n - 2 ]{/tex}
    {tex}= \frac { n } { 2 } [ 2 n ] = n ^ { 2 }{/tex}
    and {tex}S _ { 3 } = \frac { n } { 2 } [ 2 \times 1 + ( n - 1 ) 3 ]{/tex}
    {tex}S _ { 3 } = \frac { n } { 2 } [ 2 + 3n - 3 ]{/tex}
    {tex}= \frac { n ( 3 n - 1 ) } { 2 }{/tex}
    Now, {tex}S _ { 1 } + S _ { 3 } = \frac { n ( n + 1 ) } { 2 } + \frac { n ( 3 n - 1 ) } { 2 }{/tex}
    {tex}= \frac { n [ n + 1 + 3 n - 1 ] } { 2 }{/tex}
    {tex}= \frac { n [ 4 n ] } { 2 }{/tex}
    = 2n2 = 2S2
    Hence Proved. 

    0Thank You

    ANSWER

    • Posted by Neetu Gupta 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by K Preethi 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Sejal Chhikara 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Ramya Gowda 6 years, 5 months ago

    3,9,15,..........99

    0Thank You

    Sanket Arjun 6 years, 5 months ago

    2401

    0Thank You

    ANSWER

    • Posted by Vjlaxmi Saini 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Tanushree Mathur 6 years, 5 months ago

    If u want board papers of previous years then u can take from this app also

    0Thank You

    ANSWER

    • Posted by Simran Sharma 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Roshan Patel 6 years, 5 months ago

    10 की gaide

    0Thank You

    ANSWER

    • Posted by Ashnoor Kaur 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anuj Srivastav 6 years, 5 months ago

    The sky appear blue because the white light of the sun which when enters through our Atmostphere,then blue light cannot pass it due to its low wavelength and gets spread over the atmosphere.

    0Thank You

    ANSWER

    • Posted by Vaibhav Jai 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sagar Av 6 years, 5 months ago

    Width is x Length is x+4 Perimeter of a rectangle is 2(l+b) 1/2 the perimeter 1/2*2(x+4+x)=36 2(2x+4)=72 4x+8=72 4x=64x X=16m which is the width Lenght is x+4 16+4 20m

    0Thank You

    ANSWER

    myCBSEguide App

    myCBSEguide

    Trusted by 1 Crore+ Students

    Install Now

    Test Generator

    Test Generator

    Create papers online. It's FREE.

    Try Now

    CUET Mock Tests

    CUET Mock Tests

    75,000+ questions to practice only on myCBSEguide app

    Install Now
    Google Play

    Download myCBSEguide App

    All Courses

    Other Websites

    CBSE Courses

    Resources

    Corporate

    NCERT Solutions

    CBSE Sample Papers

    All Content and Intellectual Property is under Copyright Protection | myCBSEguide.com ©2007-2025