Incorrect URL accessed!!!!

ANSWER

Degree of p(x) = x + root of(x^2 +1)

Posted by Sabitha D 6 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Sandeep Yadav 6 years, 4 months ago

Maya Devi 6 years, 4 months ago

Maya Devi 6 years, 4 months ago

-1/2

ANSWER

If angle of elevation of 50 metre high building from a point on the groung is 30

Posted by Rkshivam Gupta 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Aditya Anand 6 years, 4 months ago

Please complete the question.

ANSWER

Prove that Root 5 irrational

Posted by Rajendar Ray 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Prince Raj 6 years, 4 months ago

If possible,Let √5 be rational √5=a/b where a and b are integers and co-prime. On squaring both sides, (√5)²=(a/b)² 5=a²/b² a²=5b²_(¹) Clearly,5 is a factor of a² Then 5 is also a factor of a. a=5m On squaring both sides, a²=(5m)² a²=25m² 5b²=25m²[From eq(¹)] b²=5m² Clearly,5 is a factor of b² 5 is a factor of b. Here,a and b are integers where 5 is a factor of both the integers. So,there is a contradiction arisened 5 is not a co-prime no. Hence,√5 is irrational (By contradiction method)

ANSWER

E and F are the points on the side PQ and PR respectively of a triangle PQR state whether EF is parallel QR. PE=3.9cm, EQ=3cm, PF=3.6cm and FR=2.4cm.

Posted by Radha Mankuskar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Pk . 6 years, 4 months ago

No, because it will not support bpt theorem

ANSWER

Question number 8 of Exercise 4.3

Posted by I.A.S Ashutosh Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shruti Aggarwal 6 years, 4 months ago

D=360 km Original speed =x km /h If speed=x+5 km/h ATQ Speed=distance÷time SO, Original time=360 ÷x And New time=360÷x+5 Now as per ques Original time - 1=new time Or Original time - new time =1 So, (360÷x) - (360÷x+5) =1

4Thank You

ANSWER

For which value of k, the following pair of linear equation has no solution 2x+3y=1 (k-1)x+(2x+1)y=k-1

Posted by Shrishti Upadhyay 6 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Sirsti Sngm 6 years, 4 months ago

Plz write question properly

Shruti Aggarwal 6 years, 4 months ago

Shruti Aggarwal 6 years, 4 months ago

Is this ques correct??? According to me here it must be 2k+1 in the bracket instead of 2x+1 and 2x+3y=1 and ( k-1)x +(2x+1)y=k-1 are two different eq not a single one

4Thank You

ANSWER

Solve the eq using factorisation : X2 -4ax +4a2-b2 =0

Posted by 루너 .. 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Baran 6 years, 4 months ago

X^2-4ax +4a^2=b^2 X2-2ax-2ax+4a2=b2 X(x-2a)-2a(x-2a)=b2 (x-2a)(x-2a)=b2 (X-2a)(x-2a-b2) Hence,these are the factors

ANSWER

1/x-1/1-2 one upon x minus one upon x minus 2 is equal to 3 X is not equal to zero two

Posted by Usha Sharma 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

4×2

Posted by Pk . 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Write down the decimal expansion 16/3125 without actual division.

Posted by Ezhil Jose Prasanna 6 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

?Niharika Sharma ? 6 years, 4 months ago

Sorry that emoji is ? * not?

3Thank You

?Niharika Sharma ? 6 years, 4 months ago

3125=5^5 Prime factorisation of 3125 is in the form of 2^n×5^m Therefore, 16/3125 has terminating decimal expansion?

Unknown J1711 6 years, 4 months ago

2^4 ÷ 5^5

ANSWER

Any five sum related to surface areas

Posted by Sujal Sharma 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

4q-72q-45q-20q=-15+63

Posted by Annu Kumari 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Pk . 6 years, 4 months ago

48/133

ANSWER

If the points a(x,2) b(-3,-4)c(7,-5) are collinear then find the value of x

Posted by Kannan Vami 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Since the points are collinear, then,
Area of triangle = 0
{tex}\frac { 1 } { 2 } \left[ x _ { 1 } \left( y _ { 2 } - y _ { 3 } \right) + x _ { 2 } \left( y _ { 3 } - y _ { 1 } \right) + x _ { 3 } \left( y _ { 1 } - y _ { 2 } \right) \right] = 0{/tex}
{tex}\frac { 1 } { 2 } [ x ( - 4 + 5 ) + ( - 3 ) ( - 5 - 2 ) + 7 ( 2 + 4 ) ] = 0{/tex}
x + 21 + 42 = 0
x = -63

ANSWER

Given d=5,s9=75 find a and an

Posted by Mrudula Kundalwal 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 4 months ago

d=5 S9=75

So 75=9/2(2a+8*5)

150=18a+360

18a=150-360

18a=-210

a=-210/18=-11.67

an=-11.67+(n-1)*5

=-11.67+5n-5

an=5n-16.67

ANSWER

Find the area of quadrilateral ABCD the co-ordinate of whose vertices are A (-3,2) B (5,4) C ( 7,6) and D ( -5,-4)

Posted by Kavi Kanmani 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

ar({tex}\Delta{/tex}ABD) = {tex}\frac12{/tex}|-3(8) + 5(-6) + -5(2 - 4)|
= 22 sq units.
ar({tex}\Delta{/tex}BCD) = {tex}\frac12{/tex}|5(-2) + 7(-8) -5(10)|
= 58 sq units
ar({tex}\Delta{/tex}ABD) + ar({tex}\Delta{/tex}BCD)
= 22 sq units + 58 sq units
= 80 sq units
{tex}\therefore{/tex} ar( Quad ABCD) = 80 sq units.

ANSWER

If -5 is a root of the quadratic equation 2x^2+px-15=0 and QE p(x^2+x)+k+x=0has equal roots ,find the value of k

Posted by Komal Rawat 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given that -5 is the root of {tex}2 x^{2}+p x-15=0{/tex}
Put x = -5 in {tex}2 x^{2}+p x-15=0{/tex}
{tex}\Rightarrow{/tex} {tex}2(-5)^{2}+p(-5)-15=0{/tex}
{tex}\Rightarrow{/tex} {tex}50-5 p-15=0{/tex}
{tex}\Rightarrow{/tex} {tex}35 - 5p = 0 {/tex}
{tex}\Rightarrow{/tex} {tex}5p = 35 {/tex}
{tex}\therefore{/tex} {tex}p = 7{/tex}
Hence the quadratic equation p {tex}(x^2 + x) + k = 0{/tex} becomes, {tex}7\left(x^{2}+x\right)+k=0{/tex}
{tex}7 x^{2}+7 x+k=0{/tex}
Here {tex}a = 7,\ b = 7\ and\ c = k{/tex} Given that this quadratic equation has equal roots
{tex}\therefore{/tex} {tex}b^{2}-4 a c=0{/tex}
{tex}\Rightarrow{/tex} {tex}7^{2}-4(7)(\mathrm{k})=0{/tex}
{tex}\Rightarrow{/tex} {tex}49 - 28k = 0 {/tex}
{tex}\Rightarrow{/tex} {tex}49 = 28k {/tex}
{tex}\therefore{/tex} k = {tex}\frac{49} {28}{/tex} = {tex}\frac{7} {4}{/tex}

ANSWER

how to do calculation fast in finding mean of ungrouped data

Posted by Gurwinder Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Janu Likki 6 years, 4 months ago

Use formula sigma.fi×xi/sigma.fi

ANSWER

Distance between the point (0,5 )and (- 5,0)

Posted by Aadit Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Janu Likki 6 years, 4 months ago

(X^2-x^1)+(y^2-y^1) (-5-0)^2+(5,0)^2 (5)^2+(5)^2 25+25 50

Janu Likki 6 years, 4 months ago

Answer is 50

Ashish Divakar 6 years, 4 months ago

ANSWER

7x square+30+8

Posted by Akki Akki 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Janu Likki 6 years, 4 months ago

87 is the answer

Naman Devwani 6 years, 4 months ago

The answer is simple You have square the number seven and add with thirty and eight (7×7)+30+8 49+38 87

ANSWER

Write the conditions are set the pair of linear equation has no solution

Posted by Gourav Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gurwinder Singh 6 years, 4 months ago

a1/a2=b1/b2 but not equal to c1 by c2

ANSWER

What is sino

Posted by Suman Kesarwani 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

ANSWER

Express the trigonometry ratioes sin a,tan a,in terms of cot a

Posted by Richhpal Mahala 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have to express the trigonometric ratios sin A, sec A and tan A in terms of cot A.

For sin A,

By using identity {tex}cosec ^ { 2 } A - \cot ^ { 2 } A = 1{/tex}

{tex}\Rightarrow cosec ^ { 2 } A = 1 + \cot ^ { 2 } A{/tex}

{tex}\Rightarrow \frac { 1 } { \sin ^ { 2 } A } = 1 + \cot ^ { 2 } A{/tex}

{tex}\Rightarrow \sin ^ { 2 } A = \frac { 1 } { 1 + \cot ^ { 2 } A }{/tex}

{tex} \Rightarrow \quad \sin A = \frac { 1 } { \sqrt { 1 + \cot ^ { 2 } A } }{/tex}

For tan A,

{tex} \tan A = \frac { 1 } { \cot A }{/tex}

ANSWER

Who likes maths like me comment here

Posted by Kunal Nawariya 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Richhpal Mahala 6 years, 4 months ago

Me tooooo

?Niharika Sharma ? 6 years, 4 months ago

Me too?

ANSWER

Write a rationsl and irrational number between root 2 and root 3

Posted by Ayush Shrivastava 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Surjit Singh Kondal 6 years, 4 months ago

1.5 --rational 1.50550555055550..... irrational

ANSWER

If -5 is a root of the quadratic equation 2xsquare + px -15=0 and the quadratic equation P(xsquare+x)+k=0 has equal roots, find the value of k

Posted by Murugaiyan Murugaiyan 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

ANSWER

2^x+3^y=17and 2^x+2-3^y+1=5 then find the value of x and y

Posted by Danish Raza 6 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Amit Kumar 6 years, 4 months ago

Here; 2^x+3^y=17 (i) 2^x+2-3^y+1=5 2^x-3^y+3=5 2^x-3^y=5-3 2^x-3^y=2 (ii) Adding (i) and (ii) to get : 2^x+3^y+2^x-3^y = 17+2 4^x=19 x=19/4 Putting x=19/4 in (i) : 2×19/4 +3^y=17 19/2+3^y=17 3^y=17-19/2 3^y=15/2 y=5/2

Pk . 6 years, 4 months ago

Sorry, but you have to wait tonight i will answer you tommorow at 1 pm

Danish Raza 6 years, 4 months ago

Give me amswer