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Ask QuestionPosted by Sahitya Pandey 6 years, 4 months ago
- 2 answers
Posted by Shiksha P 6 years, 4 months ago
- 1 answers
Gaurav Seth 6 years, 4 months ago
Full question: Find the value of: (3 tan 41/cot 49)^2 - (sin35sec55/tan10tan20tan60tan70tan80)^2
Answer:
26/3
Step-by-step explanation:
Given find the value of:
(3 tan 41/cot 49)^2 - (sin35 sec55 / tan10 tan20 tan60 tan70 tan80)^2
(3 tan 41 / cot (90 - 41) - sin 35 sec(90 - 35) / tan 10. tan 20. tan 60 . tan(90 - 20) tan(90 - 10)
(3 tan 41 / tan 41)^2 - (sin 35 sec(90 - 35) / tan 10 tan 20 tan 60 tan(90 - 20)tan(90 - 10))^2
(3 x 1)^2 - (sin 35 cosec 35 / tan 10. cot 10. tan 20. cot 20. tan 60)^2
9 - (1 / 1 x 1 x √3)^2 (because cosec 35 = 1/sin35)
9 - 1 / 3
27 - 1 / 3
26 / 3
Posted by Priya Sathiyan 6 years, 4 months ago
- 2 answers
Posted by Archana Kumari 6 years, 4 months ago
- 2 answers
Navneet Raj 6 years, 4 months ago
Posted by Sujal Aaron 6 years, 4 months ago
- 3 answers
Posted by Shreyank Dutta 6 years, 4 months ago
- 1 answers
Ram Kushwah 6 years, 4 months ago
Let hcf=x
then as per given lcm=9x
sum=x+9x=500
10x=500
x=50
So HCF=50
Posted by Ap The Legend 6 years, 4 months ago
- 3 answers
Posted by Saksham Yadav 6 years, 4 months ago
- 6 answers
Archana Kumari 6 years, 4 months ago
Posted by Sahil Ghuge 6 years, 4 months ago
- 1 answers
Ram Kushwah 6 years, 4 months ago
p^2x^2+(p^2-q^2)x-q^2=0
p^2x^2+p^2x-q^2x-q^2=0
p^2x(x+1)-q^2(x+1)=0
(x+1)(p^2x-q^2)=0
x+1=0 so x=-1
p^2x-q^2=0
or x=q^2/p^2
Posted by Jayesh Jadhav 6 years, 4 months ago
- 3 answers
Khushi Khatri 6 years, 4 months ago
Sahil Ghuge 6 years, 4 months ago
Posted by Nikita Smile 6 years, 4 months ago
- 2 answers
Rani Mishra ??? 6 years, 4 months ago
Posted by Anjali Sehrawat 6 years, 4 months ago
- 5 answers
Mayank Sharma 6 years, 4 months ago
Posted by Rajwin Rajaprabu 6 years, 4 months ago
- 1 answers
Posted by Prerana Savvasere 6 years, 4 months ago
- 1 answers
Nikhil Chauhan 6 years, 4 months ago
Posted by Sonam Tiwari 6 years, 4 months ago
- 8 answers
Posted by Shuba Harini 6 years, 4 months ago
- 8 answers
Bhavya Bhandari 6 years, 4 months ago
Gungun ?? 6 years, 4 months ago
Posted by Prem Chauhan 6 years, 4 months ago
- 3 answers
Posted by Devesh Dewangan 6 years, 4 months ago
- 2 answers
Tannu ? 6 years, 4 months ago
Yogita Ingle 6 years, 4 months ago
Substitute 5 in place of n
Given An
an= 3n -5
By substitution, We get
a5 = 3(5) - 5
= 15 - 5
= 10
Therefore 5th term of a.p is 10.
Posted by Shadab Mansoori 6 years, 4 months ago
- 8 answers
Posted by Shirin Belsare 6 years, 4 months ago
- 1 answers
Ram Kushwah 6 years, 4 months ago
Let f(x)=x2-3x+2=
=x2-2x-x+2
=x(x-2)-(x-2)
=(x-1)(x-2)
Now let g(x)=x2-4x+3=(x-1)(x-3)
We find that x-1 is common factor of f(x) and g(x)
HCF=x-1
Posted by Dasdeep Bhullar 6 years, 4 months ago
- 0 answers
Posted by Rohit Kumar 6 years, 4 months ago
- 0 answers
Posted by Nikita Goswami 6 years, 4 months ago
- 0 answers
Posted by Nikita Goswami 6 years, 4 months ago
- 0 answers
Posted by Nikita Goswami 6 years, 4 months ago
- 1 answers
Ram Kushwah 6 years, 4 months ago
equations are
x-4y+p=0------------------(1)
and 2x+y-q=0.-------------(2)
Putting x=3 and y=1 in(1)
3+4*1+p=0
p=-3-4=-7
putting x=3 and y=1 in (2)
2*3+3-q=0
q=6+3=9

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Gaurav Seth 6 years, 4 months ago
Question: X+1/x-2 +x-2/x+2=4-2x+3/x-2
Answer:
x =
Step-by-step explanation:
Compare above equation with
ax²+bx+c=0, we get
a = 5, b = 19, c = -30
Discreminant (D)=b²-4ac
= (19)²-4×19×(-30)
= 361+600
= 961
By Quadratic Formula:
x = [-b±√D]/(2a)
=
=
Now,
x=
Or x =
x =
x =
3Thank You