Solve p^2x^2+(p^2-q^2)x-q^2
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Posted by Sahil Ghuge 4 years, 7 months ago
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Ram Kushwah 4 years, 7 months ago
p^2x^2+(p^2-q^2)x-q^2=0
p^2x^2+p^2x-q^2x-q^2=0
p^2x(x+1)-q^2(x+1)=0
(x+1)(p^2x-q^2)=0
x+1=0 so x=-1
p^2x-q^2=0
or x=q^2/p^2
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