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    • Posted by Vanshika Sharma 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Taniya . 1 year, 7 months ago

    Given that α & β are zero of polynomial f(x)=x2−3x−2 therefore α+β=3 αβ=−2 Now, the zero of the required quadratic polynomial are, 2α+β1​ & 2β+α1​ Sum of the roots- 2α+β1​+2β+α1​=(2α+β)(2β+α)2β+α+2α+β​=4αβ+2α2+2β2+αβ3(α+β)​ =4×(−2)+2[(α+β)2−2αβ]+(−2)3×3​ =−10+2[9+2×2]9​ =−10+269​ =169​ Products of roots:- 2α+β1​×2β+α1​=4αβ+2[(α+β)2−2αβ]+αβ1​=161​ Now Req eq. x2−(sum of roots)x+ Product of roots=0 =x2−169​x+161​=0 =16x2−9x+16=0.

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    • Posted by Suhani Prasad 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Shalu Dubey 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    _Jass_ Mahey_ 1 year, 7 months ago

    After reading this chapter, three students drew different conclusion. Whi

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    • Posted by Khushal Goel 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Shalu Dubey 1 year, 7 months ago

    A tangent pq at a point p of a circle of radius 5 cm meets a line through

    0Thank You

    Alok Jha 1 year, 7 months ago

    The cost of each pencil is ₹3 and cost of pen is ₹5

    1Thank You

    Kavi Kavi 1 year, 7 months ago

    X be cost of pencil and y be cost of pen. 5x+7y=50;7x+5y=46 solve by elimination method. x=3.y =5

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    • Posted by Ananth Kodali 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Jiya Ray 1 year, 7 months ago

    First we will take out prime factors of both numbers that is 336 and 54 .. 336=2⁴×3×7 , 54=2×3³ now we know that HCF= product of common terms with lowest power so we multiply 2×3=6 and now LCM = product of prime factors with highest power so we multiply 2⁴×3³×7=3024. And now We will verify so LCM×HCF=product of two numbers 3024×6=336×54 18144=18144.

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    • Posted by Dhruv Garg 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Alok Jha 1 year, 7 months ago

    The value of x is 36 and y is 13

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    • Posted by Katikala Lalitha 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Anonymous 1 year, 7 months ago

    This is ncert question

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    • Posted by Shreehari Lute 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    _Jass_ Mahey_ 1 year, 7 months ago

    x²+x-2x-2=x²+3-x-3 x²+x-2x-2-x² -3x +x +3 x-2x-3x+x-2+3 -x-2x-3x+x-2+3 -x-2x+1=0 -3x+1=0 Hence, given equation is not quadratic equation

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    • Posted by Padma Priya 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Mukundhan S 1 year, 7 months ago

    Because negative can't be squre rooted

    0Thank You

    Mukundhan S 1 year, 7 months ago

    No it is not possible

    0Thank You

    _Jass_ Mahey_ 1 year, 7 months ago

    Using formula b²-√4ac/2

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    • Posted by Sandhya Choudhary 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Anwesh Mohapatra 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Mo. Danish 1 year, 7 months ago

    Hcf=138

    1Thank You

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    • Posted by Yug Patel 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Ankit Class 1 year, 7 months ago

    Tum kis class mein ho

    0Thank You

    Ankit Class 1 year, 7 months ago

    x^2= 8. x=2√2 and -2√2.

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    • Posted by Simran Kumari 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Ankit Class 1 year, 7 months ago

    5p^2+20

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    Khushi Kushwaha 1 year, 7 months ago

    √4

    0Thank You

    Khushi Kushwaha 1 year, 7 months ago

    20 + 5p^2 , by taking common factor = 5(4+p^2)

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    • Posted by Siya Singh 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Ankit Class 1 year, 7 months ago

    Using trigonometric ratio like sinA = p/ h , cosA= b/ h etc

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    • Posted by Azad Thakur 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Aashish Sharma 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Ranveer Raj 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Ansh Singh Rajput 1 year, 7 months ago

    Why are you take so much interest in solving all the questions Khushi...?

    0Thank You

    Ansh Singh Rajput 1 year, 7 months ago

    Are you the topper of your class...!

    0Thank You

    Khushi Kushwaha 1 year, 7 months ago

    4x + 3y = 17 { decimals will be removed 4/10x + 3/10y = 17/10 ( here, all the 10 will be cancel out) } ----(i) Similarly: 7x - 2y = 8 will be form by removing decimals in the same manner .----(ii) From equation --(i) ------> X = 17-3y/4 Putting value of x in 7x - 2y = 8 7(17-3y/4) - 2y = 8 119 - 21y/4 - 2y = 8 (by solving brackets) 119 - 21y - 8y /4 =8 (by taking LCM.) 119 - 29y /4 = 8 119 - 29y = 32 ( by multiplying 4 on the left hand side) - 29y = 32 - 119 -29y = - 87 ( subtract sign will be cancled ) y = 87/29 y = 3 Now finding value of x X = 17 - 3y /4 X = 17 - 3(3)/4 X = 17 -9 /4 X = 8 /4 X= 2

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    • Posted by Alan Rizo 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Palak Singh 1 year, 7 months ago

    a²+2ab+b²

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    Mukundhan S 1 year, 7 months ago

    A²+B²+2AB

    0Thank You

    Shashank Yadav 1 year, 7 months ago

    a² + b² + 2ab

    1Thank You

    Lakshya Agrawal 1 year, 7 months ago

    a^2+b^2+2ab

    1Thank You

    Arpita Mishra 1 year, 7 months ago

    a2+ b2+2ab

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    • Posted by Loose Rs 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Fahad Siddiqui 1 year, 7 months ago

    LCM=3 ki power 5 and 5 ki power 2

    0Thank You

    Ankit Class 1 year, 7 months ago

    HCF = 3 , LCM = 6075

    0Thank You

    Shreesh Singh 1 year, 7 months ago

    U

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    • Posted by Test Account 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Ankit Class 1 year, 7 months ago

    Using integretion

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    • Posted by Jyoti Singh 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Silla Ranjeet 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Rudra Pratap Singh 1 year, 7 months ago

    We have a and b are two odd positive integers such that a & b but we know that odd numbers are in the form of 2n+1 and 2n+3 where n is integer. so, a=2n+3, b=2n+1, n∈1 Given ⇒ a>b now, According to given question Case I: 2 a+b ​ = 2 2n+3+2n+1 ​ = 2 4n+4 ​ =2n+2=2(n+1) put let m=2n+1 then, 2 a+b ​ =2m ⇒ even number. Case II: 2 a−b ​ = 2 2n+3−2n−1 ​ 2 2 ​ =1 ⇒ odd number. Hence we can see that, one is odd and other is even.

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    • Posted by _Jass_ Mahey_ 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Mohit Soni 1 year, 7 months ago

    26

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    • Posted by _Jass_ Mahey_ 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Aman Kumar 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Maya Shukla 1 year, 7 months ago

    x²+x

    1Thank You

    _Jass_ Mahey_ 1 year, 7 months ago

    x²+1x=2x³

    1Thank You

    Abhinav Upadhyay 1 year, 7 months ago

    x(x+1) = x*x+x*1=x^2+x

    0Thank You

    Ankit Class 1 year, 7 months ago

    x(x+1) = x*x+ x*1=x^2+x.

    0Thank You

    𝕶𝖆𝖑𝖚𝖗𝖆𝖒 𝕾𝖎𝖘𝖔𝖉𝖎𝖞𝖆 1 year, 7 months ago

    Yes

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    • Posted by Tanishka Khandelwal 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Sangharsh Sawant 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Maya Shukla 1 year, 7 months ago

    Non terminating non repeating

    1Thank You

    Ankit Class 1 year, 7 months ago

    Non terminating non repeating

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    • Posted by Rayan Kt 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Ankit Class 1 year, 7 months ago

    Typing karne mein haalat khrab ho gya 🤣🤣🤣

    0Thank You

    Ankit Class 1 year, 7 months ago

    f( x)=ax^2+bx+c. a+b+c=0 . c=-a-b. Let zeroes are k and l. K+ l= -b/ a. Kl= c/a. Kl= -a-b/ a. Kl= b. (K- l )^2= (k+l)^2-4 kl. (K-l)^2= b^2/a^2 - 4b. K- l= √b^2 - 4a^2b/ a. k =( √b^2-4a^2b -b )/2 a.

    0Thank You

    Ankit Class 1 year, 7 months ago

    Exam khatam toh kya question kare🤣🤣🤣

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    B.S Chauhan 1 year, 7 months ago

    Good morning

    2Thank You

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    • Posted by _Jass_ Mahey_ 1 year, 7 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    _Jass_ Mahey_ 1 year, 7 months ago

    Excuse me the ratio is given or not we assuming the ratio or given ratio

    0Thank You

    Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 1 year, 7 months ago

    in the ratio m₁: m₂ is given by the Section Formula. P (x, y) = [(mx₂ + nx₁) / (m + n) , (my₂ + ny₁) / (m + n)] Let the given line 2x + y - 4 = 0 divide the line segment joining the points A(2, - 2) and B(3, 7) in a ratio k: 1 at point C. Coordinates of the point of divison C (x, y) = [(3k + 2) / (k + 1), (7k - 2) / (k + 1)] Hence, x = (3k + 2) / (k + 1), y = (7k - 2) / (k + 1) This point C also lies on 2x + y - 4 = 0 .....(1) By substituting the values of C(x, y) in Equation(1), 2[(3k + 2) / (k + 1)] + [(7k - 2) / (k + 1)] - 4 = 0 [6k + 4 + 7k - 2 - 4k - 4] / (k + 1) = 0 (By Cross multiplying & Transposing) 9k - 2 = 0 k = 2/9 Therefore, the ratio in which the line 2x + y - 4 = 0 divides the line segment joining the points A (2, 2) and B (3, 7) is 2:9 internally.

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    • Posted by _Jass_ Mahey_ 1 year, 8 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Shubham Kumar Kumar 1 year, 7 months ago

    Thanks

    1Thank You

    Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 1 year, 8 months ago

    Let AB be the height of tower and x be the one of the complementry angle. So, (90-x) be the another complementary angle. C and D be the two points with distance 4 m and 9 m from the base respectively. As per question, In right ΔABC, ⇒tan x=AB/BC ⇒tan x=AB/4 ⇒AB=4 tan x...(i) Also, In right ΔABD, tan (90∘−x)=AB/BD ⇒ cot x=AB/9 ⇒AB=9 cot x...(ii) Multiplying equation (i) and (ii) AB²=9 cot x×4 tan x ⇒AB²=36 ⇒AB= ±6 Height cannot be negative. Therefore, the height of the tower is 6m.

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