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  • 1 answers

Taniya . 1 year, 11 months ago

Given that ฮฑ & ฮฒ are zero of polynomial f(x)=x2โˆ’3xโˆ’2 therefore ฮฑ+ฮฒ=3 ฮฑฮฒ=โˆ’2 Now, the zero of the required quadratic polynomial are, 2ฮฑ+ฮฒ1โ€‹ & 2ฮฒ+ฮฑ1โ€‹ Sum of the roots- 2ฮฑ+ฮฒ1โ€‹+2ฮฒ+ฮฑ1โ€‹=(2ฮฑ+ฮฒ)(2ฮฒ+ฮฑ)2ฮฒ+ฮฑ+2ฮฑ+ฮฒโ€‹=4ฮฑฮฒ+2ฮฑ2+2ฮฒ2+ฮฑฮฒ3(ฮฑ+ฮฒ)โ€‹ =4ร—(โˆ’2)+2[(ฮฑ+ฮฒ)2โˆ’2ฮฑฮฒ]+(โˆ’2)3ร—3โ€‹ =โˆ’10+2[9+2ร—2]9โ€‹ =โˆ’10+269โ€‹ =169โ€‹ Products of roots:- 2ฮฑ+ฮฒ1โ€‹ร—2ฮฒ+ฮฑ1โ€‹=4ฮฑฮฒ+2[(ฮฑ+ฮฒ)2โˆ’2ฮฑฮฒ]+ฮฑฮฒ1โ€‹=161โ€‹ Now Req eq. x2โˆ’(sum of roots)x+ Product of roots=0 =x2โˆ’169โ€‹x+161โ€‹=0 =16x2โˆ’9x+16=0.
  • 1 answers

_Jass_ Mahey_ 1 year, 11 months ago

After reading this chapter, three students drew different conclusion. Whi
  • 3 answers

Shalu Dubey 1 year, 11 months ago

A tangent pq at a point p of a circle of radius 5 cm meets a line through

Alok Jha 1 year, 11 months ago

The cost of each pencil is โ‚น3 and cost of pen is โ‚น5

Kavi Kavi 1 year, 11 months ago

X be cost of pencil and y be cost of pen. 5x+7y=50;7x+5y=46 solve by elimination method. x=3.y =5
  • 1 answers

Jiya Ray 1 year, 11 months ago

First we will take out prime factors of both numbers that is 336 and 54 .. 336=2โดร—3ร—7 , 54=2ร—3ยณ now we know that HCF= product of common terms with lowest power so we multiply 2ร—3=6 and now LCM = product of prime factors with highest power so we multiply 2โดร—3ยณร—7=3024. And now We will verify so LCMร—HCF=product of two numbers 3024ร—6=336ร—54 18144=18144.
  • 1 answers

Alok Jha 1 year, 11 months ago

The value of x is 36 and y is 13
  • 1 answers

Anonymous 1 year, 11 months ago

This is ncert question
  • 1 answers

_Jass_ Mahey_ 1 year, 11 months ago

xยฒ+x-2x-2=xยฒ+3-x-3 xยฒ+x-2x-2-xยฒ -3x +x +3 x-2x-3x+x-2+3 -x-2x-3x+x-2+3 -x-2x+1=0 -3x+1=0 Hence, given equation is not quadratic equation
  • 3 answers

Mukundhan S 1 year, 11 months ago

Because negative can't be squre rooted

Mukundhan S 1 year, 11 months ago

No it is not possible

_Jass_ Mahey_ 1 year, 11 months ago

Using formula bยฒ-โˆš4ac/2
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  • 2 answers

Ankit Class 2 years ago

Tum kis class mein ho

Ankit Class 2 years ago

x^2= 8. x=2โˆš2 and -2โˆš2.
  • 3 answers

Ankit Class 2 years ago

5p^2+20

Khushi Kushwaha 2 years ago

โˆš4

Khushi Kushwaha 2 years ago

20 + 5p^2 , by taking common factor = 5(4+p^2)
  • 1 answers

Ankit Class 2 years ago

Using trigonometric ratio like sinA = p/ h , cosA= b/ h etc
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  • 0 answers
  • 3 answers
Why are you take so much interest in solving all the questions Khushi...?
Are you the topper of your class...!

Khushi Kushwaha 2 years ago

4x + 3y = 17 { decimals will be removed 4/10x + 3/10y = 17/10 ( here, all the 10 will be cancel out) } ----(i) Similarly: 7x - 2y = 8 will be form by removing decimals in the same manner .----(ii) From equation --(i) ------> X = 17-3y/4 Putting value of x in 7x - 2y = 8 7(17-3y/4) - 2y = 8 119 - 21y/4 - 2y = 8 (by solving brackets) 119 - 21y - 8y /4 =8 (by taking LCM.) 119 - 29y /4 = 8 119 - 29y = 32 ( by multiplying 4 on the left hand side) - 29y = 32 - 119 -29y = - 87 ( subtract sign will be cancled ) y = 87/29 y = 3 Now finding value of x X = 17 - 3y /4 X = 17 - 3(3)/4 X = 17 -9 /4 X = 8 /4 X= 2
  • 5 answers

Palak Singh 1 year, 11 months ago

aยฒ+2ab+bยฒ

Mukundhan S 1 year, 11 months ago

Aยฒ+Bยฒ+2AB

Shashank Yadav 2 years ago

aยฒ + bยฒ + 2ab

Lakshya Agrawal 2 years ago

a^2+b^2+2ab

Arpita Mishra 2 years ago

a2+ b2+2ab
  • 3 answers

Fahad Siddiqui 2 years ago

LCM=3 ki power 5 and 5 ki power 2

Ankit Class 2 years ago

HCF = 3 , LCM = 6075

Shreesh Singh 2 years ago

U
  • 1 answers

Ankit Class 2 years ago

Using integretion
  • 1 answers
We have a and b are two odd positive integers such that a & b but we know that odd numbers are in the form of 2n+1 and 2n+3 where n is integer. so, a=2n+3, b=2n+1, nโˆˆ1 Given โ‡’ a>b now, According to given question Case I: 2 a+b โ€‹ = 2 2n+3+2n+1 โ€‹ = 2 4n+4 โ€‹ =2n+2=2(n+1) put let m=2n+1 then, 2 a+b โ€‹ =2m โ‡’ even number. Case II: 2 aโˆ’b โ€‹ = 2 2n+3โˆ’2nโˆ’1 โ€‹ 2 2 โ€‹ =1 โ‡’ odd number. Hence we can see that, one is odd and other is even.
  • 2 answers

Maya Shukla 2 years ago

Non terminating non repeating

Ankit Class 2 years ago

Non terminating non repeating
  • 4 answers

Ankit Class 2 years ago

Typing karne mein haalat khrab ho gya ๐Ÿคฃ๐Ÿคฃ๐Ÿคฃ

Ankit Class 2 years ago

f( x)=ax^2+bx+c. a+b+c=0 . c=-a-b. Let zeroes are k and l. K+ l= -b/ a. Kl= c/a. Kl= -a-b/ a. Kl= b. (K- l )^2= (k+l)^2-4 kl. (K-l)^2= b^2/a^2 - 4b. K- l= โˆšb^2 - 4a^2b/ a. k =( โˆšb^2-4a^2b -b )/2 a.

Ankit Class 2 years ago

Exam khatam toh kya question kare๐Ÿคฃ๐Ÿคฃ๐Ÿคฃ

B.S Chauhan 2 years ago

Good morning
  • 2 answers

_Jass_ Mahey_ 1 year, 11 months ago

Excuse me the ratio is given or not we assuming the ratio or given ratio
in the ratio mโ‚: mโ‚‚ is given by the Section Formula. P (x, y) = [(mxโ‚‚ + nxโ‚) / (m + n) , (myโ‚‚ + nyโ‚) / (m + n)] Let the given line 2x + y - 4 = 0 divide the line segment joining the points A(2, - 2) and B(3, 7) in a ratio k: 1 at point C. Coordinates of the point of divison C (x, y) = [(3k + 2) / (k + 1), (7k - 2) / (k + 1)] Hence, x = (3k + 2) / (k + 1), y = (7k - 2) / (k + 1) This point C also lies on 2x + y - 4 = 0 .....(1) By substituting the values of C(x, y) in Equation(1), 2[(3k + 2) / (k + 1)] + [(7k - 2) / (k + 1)] - 4 = 0 [6k + 4 + 7k - 2 - 4k - 4] / (k + 1) = 0 (By Cross multiplying & Transposing) 9k - 2 = 0 k = 2/9 Therefore, the ratio in which the line 2x + y - 4 = 0 divides the line segment joining the points A (2, 2) and B (3, 7) is 2:9 internally.
  • 2 answers
Thanks
Let AB be the height of tower and x be the one of the complementry angle. So, (90-x) be the another complementary angle. C and D be the two points with distance 4 m and 9 m from the base respectively. As per question, In right ฮ”ABC, โ‡’tan x=AB/BC โ‡’tan x=AB/4 โ‡’AB=4 tan x...(i) Also, In right ฮ”ABD, tan (90โˆ˜โˆ’x)=AB/BD โ‡’ cot x=AB/9 โ‡’AB=9 cot x...(ii) Multiplying equation (i) and (ii) ABยฒ=9 cot xร—4 tan x โ‡’ABยฒ=36 โ‡’AB= ยฑ6 Height cannot be negative. Therefore, the height of the tower is 6m.

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