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If alpha and beta are the zeroes of p(x)=x2-3x-2 find the quadratic polynomial whose zeroes are - 2alpha 2beta

Posted by Vanshika Sharma 2 years ago

1 answers

Taniya . 2 years ago

Given that α & β are zero of polynomial f(x)=x2−3x−2 therefore α+β=3 αβ=−2 Now, the zero of the required quadratic polynomial are, 2α+β1 & 2β+α1 Sum of the roots- 2α+β1+2β+α1=(2α+β)(2β+α)2β+α+2α+β=4αβ+2α2+2β2+αβ3(α+β) =4×(−2)+2[(α+β)2−2αβ]+(−2)3×3 =−10+2[9+2×2]9 =−10+269 =169 Products of roots:- 2α+β1×2β+α1=4αβ+2[(α+β)2−2αβ]+αβ1=161 Now Req eq. x2−(sum of roots)x+ Product of roots=0 =x2−169x+161=0 =16x2−9x+16=0.

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If the given figure,AB=BC =10 . If AC=7, then the length of BP is

Posted by Suhani Prasad 2 years ago

CBSE > Class 10 > Mathematics

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A tangent pq at a point p of a circleof radius 5 cm meets a line through the centre o at a point q so that oq=12 cm .find the length pq

Posted by Shalu Dubey 2 years ago

CBSE > Class 10 > Mathematics

1 answers

_Jass_ Mahey_ 1 year, 11 months ago

After reading this chapter, three students drew different conclusion. Whi

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5 pencils and 7 pens together cost * 50, whereas 7 pencils and 5 pens together cost 46. Find the cost

Posted by Khushal Goel 2 years ago

CBSE > Class 10 > Mathematics

3 answers

Shalu Dubey 2 years ago

A tangent pq at a point p of a circle of radius 5 cm meets a line through

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Alok Jha 2 years ago

The cost of each pencil is ₹3 and cost of pen is ₹5

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Kavi Kavi 2 years ago

X be cost of pencil and y be cost of pen. 5x+7y=50;7x+5y=46 solve by elimination method. x=3.y =5

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Find the LCM and HCF of 336 and 54 and verify that LCM×HCF= product of two numbers

Posted by Ananth Kodali 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Jiya Ray 2 years ago

First we will take out prime factors of both numbers that is 336 and 54 .. 336=2⁴×3×7 , 54=2×3³ now we know that HCF= product of common terms with lowest power so we multiply 2×3=6 and now LCM = product of prime factors with highest power so we multiply 2⁴×3³×7=3024. And now We will verify so LCM×HCF=product of two numbers 3024×6=336×54 18144=18144.

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X/10+y/5=1,x/8+y/6=15

Posted by Dhruv Garg 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Alok Jha 2 years ago

The value of x is 36 and y is 13

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4u²+ 8u

Posted by Katikala Lalitha 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Anonymous 2 years ago

This is ncert question

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(x-2) (x+1)=(x-1)(x+3)

Posted by Shreehari Lute 2 years ago

CBSE > Class 10 > Mathematics

1 answers

_Jass_ Mahey_ 2 years ago

x²+x-2x-2=x²+3-x-3 x²+x-2x-2-x² -3x +x +3 x-2x-3x+x-2+3 -x-2x-3x+x-2+3 -x-2x+1=0 -3x+1=0 Hence, given equation is not quadratic equation

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2x²-x+5

Posted by Padma Priya 2 years ago

CBSE > Class 10 > Mathematics

3 answers

Mukundhan S 2 years ago

Because negative can't be squre rooted

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Mukundhan S 2 years ago

No it is not possible

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_Jass_ Mahey_ 2 years ago

Using formula b²-√4ac/2

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Division of 2(+2)

Posted by Sandhya Choudhary 2 years ago

CBSE > Class 10 > Mathematics

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Use euclid's division algorithm to find the HCF of 184,230 and 276

Posted by Anwesh Mohapatra 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Mo. Danish 2 years ago

Hcf=138

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Find zeros of polynomial 4x²=32x

Posted by Yug Patel 2 years ago

CBSE > Class 10 > Mathematics

2 answers

Ankit Class 2 years ago

Tum kis class mein ho

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Ankit Class 2 years ago

x^2= 8. x=2√2 and -2√2.

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20+p ×5p is equal to

Posted by Simran Kumari 2 years ago

CBSE > Class 10 > Mathematics

3 answers

Ankit Class 2 years ago

5p^2+20

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Khushi Kushwaha 2 years ago

√4

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Khushi Kushwaha 2 years ago

20 + 5p^2 , by taking common factor = 5(4+p^2)

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Can I know how to solve first exercise of trigonometry

Posted by Siya Singh 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Class 2 years ago

Using trigonometric ratio like sinA = p/ h , cosA= b/ h etc

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Igucg

Posted by Azad Thakur 2 years ago

CBSE > Class 10 > Mathematics

0 answers

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Ex 3.4

Posted by Aashish Sharma 2 years ago

CBSE > Class 10 > Mathematics

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0.4x + 0.3y = 1.7, 0.7x-0.2y = 0.8

Posted by Ranveer Raj 2 years ago

CBSE > Class 10 > Mathematics

3 answers

Ansh Singh Rajput 2 years ago

Why are you take so much interest in solving all the questions Khushi...?

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Ansh Singh Rajput 2 years ago

Are you the topper of your class...!

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Khushi Kushwaha 2 years ago

4x + 3y = 17 { decimals will be removed 4/10x + 3/10y = 17/10 ( here, all the 10 will be cancel out) } ----(i) Similarly: 7x - 2y = 8 will be form by removing decimals in the same manner .----(ii) From equation --(i) ------> X = 17-3y/4 Putting value of x in 7x - 2y = 8 7(17-3y/4) - 2y = 8 119 - 21y/4 - 2y = 8 (by solving brackets) 119 - 21y - 8y /4 =8 (by taking LCM.) 119 - 29y /4 = 8 119 - 29y = 32 ( by multiplying 4 on the left hand side) - 29y = 32 - 119 -29y = - 87 ( subtract sign will be cancled ) y = 87/29 y = 3 Now finding value of x X = 17 - 3y /4 X = 17 - 3(3)/4 X = 17 -9 /4 X = 8 /4 X= 2

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(a+b)² formula

Posted by Alan Rizo 2 years ago

CBSE > Class 10 > Mathematics

5 answers

Palak Singh 2 years ago

a²+2ab+b²

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Mukundhan S 2 years ago

A²+B²+2AB

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Shashank Yadav 2 years ago

a² + b² + 2ab

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Lakshya Agrawal 2 years ago

a^2+b^2+2ab

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Arpita Mishra 2 years ago

a2+ b2+2ab

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Find hcf and lcm of 75 and 243

Posted by Loose Rs 2 years ago

CBSE > Class 10 > Mathematics

3 answers

Fahad Siddiqui 2 years ago

LCM=3 ki power 5 and 5 ki power 2

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Ankit Class 2 years ago

HCF = 3 , LCM = 6075

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Shreesh Singh 2 years ago

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How to calculate are of uneven object?

Posted by Test Account 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Class 2 years ago

Using integretion

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Find the value of m, when (m+1) x=3ky+15=0 and 5x+k y+5=0 are coincident.

Posted by Jyoti Singh 2 years ago

CBSE > Class 10 > Mathematics

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If a and b are two odd positive integers such that a>b then prove that one of the two numbers is odd and other even

Posted by Silla Ranjeet 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Rudra Pratap Singh 2 years ago

We have a and b are two odd positive integers such that a & b but we know that odd numbers are in the form of 2n+1 and 2n+3 where n is integer. so, a=2n+3, b=2n+1, n∈1 Given ⇒ a>b now, According to given question Case I: 2 a+b = 2 2n+3+2n+1 = 2 4n+4 =2n+2=2(n+1) put let m=2n+1 then, 2 a+b =2m ⇒ even number. Case II: 2 a−b = 2 2n+3−2n−1 2 2 =1 ⇒ odd number. Hence we can see that, one is odd and other is even.

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Akhila goes to a fair with₹29 and want to have rides on the gaint wheel and play Hoopla. Represent this situation algebrically and graphically . On Comparing a¹/a² , b¹/b² and c¹/c², find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident : (1) 5x-4y+8=0 7x+6y-9=0 (2) 6x-3y+10=0 2x-y+9=0 (3) 9x+3y+12=0 18x+6y+24=0

Posted by _Jass_ Mahey_ 2 years ago

CBSE > Class 10 > Mathematics

1 answers

Mohit Soni 2 years ago

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Using theorem 6.1A, B, and C are points on OP, OQ and QR respectively such that AB||PQ and AC||PR.show that BC||QR.

Posted by _Jass_ Mahey_ 2 years ago

CBSE > Class 10 > Mathematics

0 answers

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x(x+1)

Posted by Aman Kumar 2 years ago

CBSE > Class 10 > Mathematics

5 answers

Maya Shukla 2 years ago

x²+x

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_Jass_ Mahey_ 2 years ago

x²+1x=2x³

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Abhinav Upadhyay 2 years ago

x(x+1) = x*x+x*1=x^2+x

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Ankit Class 2 years ago

x(x+1) = x*x+ x*1=x^2+x.

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𝕶𝖆𝖑𝖚𝖗𝖆𝖒 𝕾𝖎𝖘𝖔𝖉𝖎𝖞𝖆 2 years ago

Yes

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If the sum of the zeroes of the polynomial P(x) = 3x^2+(2k+1)x - k+5 is equal to the product of zeroes then find the value of k

Posted by Tanishka Khandelwal 2 years ago

CBSE > Class 10 > Mathematics

0 answers

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In what form of decimals can irrational number be presented

Posted by Sangharsh Sawant 2 years ago

CBSE > Class 10 > Mathematics

2 answers

Maya Shukla 2 years ago

Non terminating non repeating

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Ankit Class 2 years ago

Non terminating non repeating

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If p(x) = ax^2+bx+c and a+b+c=0 then find one zerors of p(x)

Posted by Rayan Kt 2 years ago

CBSE > Class 10 > Mathematics

4 answers

Ankit Class 2 years ago

Typing karne mein haalat khrab ho gya 🤣🤣🤣

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Ankit Class 2 years ago

f( x)=ax^2+bx+c. a+b+c=0 . c=-a-b. Let zeroes are k and l. K+ l= -b/ a. Kl= c/a. Kl= -a-b/ a. Kl= b. (K- l )^2= (k+l)^2-4 kl. (K-l)^2= b^2/a^2 - 4b. K- l= √b^2 - 4a^2b/ a. k =( √b^2-4a^2b -b )/2 a.

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Ankit Class 2 years ago

Exam khatam toh kya question kare🤣🤣🤣

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B.S Chauhan 2 years ago

Good morning

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Determine the ratio in which the line 2x+y-4=0 divdes the line segment joining the points A(2,-2) and B (3, 7)

Posted by _Jass_ Mahey_ 2 years ago

CBSE > Class 10 > Mathematics

2 answers

_Jass_ Mahey_ 2 years ago

Excuse me the ratio is given or not we assuming the ratio or given ratio

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Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 2 years ago

in the ratio m₁: m₂ is given by the Section Formula. P (x, y) = [(mx₂ + nx₁) / (m + n) , (my₂ + ny₁) / (m + n)] Let the given line 2x + y - 4 = 0 divide the line segment joining the points A(2, - 2) and B(3, 7) in a ratio k: 1 at point C. Coordinates of the point of divison C (x, y) = [(3k + 2) / (k + 1), (7k - 2) / (k + 1)] Hence, x = (3k + 2) / (k + 1), y = (7k - 2) / (k + 1) This point C also lies on 2x + y - 4 = 0 .....(1) By substituting the values of C(x, y) in Equation(1), 2[(3k + 2) / (k + 1)] + [(7k - 2) / (k + 1)] - 4 = 0 [6k + 4 + 7k - 2 - 4k - 4] / (k + 1) = 0 (By Cross multiplying & Transposing) 9k - 2 = 0 k = 2/9 Therefore, the ratio in which the line 2x + y - 4 = 0 divides the line segment joining the points A (2, 2) and B (3, 7) is 2:9 internally.

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The angles of elevation of the top of a tower from two points at a distance of 4m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m

Posted by _Jass_ Mahey_ 2 years ago

CBSE > Class 10 > Mathematics

2 answers

Shubham Kumar Kumar 2 years ago

Thanks

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Muhammad Amaan Rahman 𝔸𝕄𝔸𝔸ℕ 𝕄𝕌ℍ𝔸𝕄𝕄𝔸𝔻 2 years ago

Let AB be the height of tower and x be the one of the complementry angle. So, (90-x) be the another complementary angle. C and D be the two points with distance 4 m and 9 m from the base respectively. As per question, In right ΔABC, ⇒tan x=AB/BC ⇒tan x=AB/4 ⇒AB=4 tan x...(i) Also, In right ΔABD, tan (90∘−x)=AB/BD ⇒ cot x=AB/9 ⇒AB=9 cot x...(ii) Multiplying equation (i) and (ii) AB²=9 cot x×4 tan x ⇒AB²=36 ⇒AB= ±6 Height cannot be negative. Therefore, the height of the tower is 6m.

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