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Let the present age of father be X years and the present age of sum of two children be Y years. X=3y ...(1) X+5=2(y+10) X-2y=15 ....(2) On solving (1) and (2) we get: X=45 years. Hence the present age of father is 45 years.

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Answer

Posted by Deepak Ray 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

? Queen ? 6 years, 3 months ago

Where is question???

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Deepak Ray 6 years, 3 months ago

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Given that sin(A+B)=sinA cosB+coAsinB ,find the value of sin 75°.

Posted by Aqsa Rangrez 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

According to question we have sin (A+B) = sin A cos B + cos A sin B, we need to find the value of {tex}\sin 75 ^ { \circ }{/tex}.

Putting {tex}A = 45 ^ { \circ }{/tex} and {tex}B = 30 ^ { \circ }{/tex} in sin (A+B) = sin A cos B + cos A sin B,
we get
{tex}\sin \left( 45 ^ { \circ } + 30 ^ { \circ } \right){/tex}
{tex}= \sin 45 ^ { \circ } \cos 30 ^ { \circ } + \cos 45 ^ { \circ } \sin 30 ^ { \circ }{/tex}
{tex}\Rightarrow \sin 75 ^ { \circ }{/tex} {tex}= \frac { 1 } { \sqrt { 2 } } \times \frac { \sqrt { 3 } } { 2 } + \frac { 1 } { \sqrt { 2 } } \times \frac { 1 } { 2 }{/tex}
{tex}= \frac { \sqrt { 3 } } { 2 \sqrt { 2 } } + \frac { 1 } { 2 \sqrt { 2 } }{/tex}
{tex}= \frac { \sqrt { 3 } + 1 } { 2 \sqrt { 2 } }{/tex}

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If sin A =9/41,comput3 cos A and tan A

Posted by Jayasree Ammu 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Prince Kumar 6 years, 3 months ago

SinA=1/cos =41/9

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Sia ? 6 years, 3 months ago

Given, {tex}\angle{/tex}B = 90°.
Let BC = 9 and AC = 41

sin A{tex}= \frac { \text { Perpendicular } } { \text { Hypotenuse } } = \frac { \mathrm { BC } } { \mathrm { AC } } = \frac { 9 } { 41 }{/tex}
By Pythagoras' theorem, we have
AC² = AB²+ BC²
{tex}\Rightarrow{/tex}AB²= AC² - BC²
= 41² - 9² = 1681 - 81 = 1600
{tex}\Rightarrow AB = 40{/tex}
{tex}\cos A = \frac { \text { Base } } { \text { Hypotenuse } } = \frac { A B } { A C } = \frac { 40 } { 41 }{/tex}
{tex}\tan A = \frac { \text { Perpendicular } } { \text { Base } } = \frac { B C } { A B } = \frac { 9 } { 40 }{/tex}

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If 2,6,10,14,18......form an A.P. 5hen its nth term is

Posted by Naresh Kumar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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If the sum of a1+a2=50 for an A.P. Find the value of a1+a2+..... +a10?

Posted by Vijay Maurya 6 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Ncert chapter 6 ka example 7 of class 10th

Posted by Gourav 123 6 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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R.s aggarwal class10th exercise 4B ka question no: 14 solve

Posted by Sangita Prajapati 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gourav 123 6 years, 3 months ago

In rs aggarwal hint box the solution is given

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Sec+tan=p prove that sin=[(p)2-1][(p)2+1]

Posted by Madhav Pathak 6 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the area of the triangle formed by joining the mid points of the sides of the triangle whose vertices are (0,-1) ,(2,3) and (0,3). Find the ratio of this area to the area of given triangle.

Posted by Aarsh Jain 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Ravi Joshi 6 years, 3 months ago

See in 7.3 Q.3

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Give me a centroid formula i ch 7

Posted by Ravi Dubey 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Vijay Maurya 6 years, 3 months ago

{(x1+x2+x3)÷3, (y1+y2+y3)÷3}

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Ravi Joshi 6 years, 3 months ago

(x1+x2+x3)÷3

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Ravi Joshi 6 years, 3 months ago

x1+x2+X3

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The sum of n terms of an AP is (5n²—3n).find the Ap and hence its 10th trem

Posted by Ansh Shekhawat 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Ramesh Reddy K 6 years, 3 months ago

S1=5(1)^2-3(1)=2=a1=a S2=5(2)^2-3(2)=14=a1+a2 a2=14-2=12 d=12-2=10 A.P is 2, 12, 22....... a10=2+9(10)=92

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Sin theta ×sin theta /cosec theta

Posted by Nehagarg 9457389070 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Madhav Pathak 6 years, 3 months ago

Sin×Sin=sin square= 1-cos square/cosec. Cosec=1/sin hence sin(1-cos square) apply identity a2-b2

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Madhav Pathak 6 years, 3 months ago

Sin(1+cos)(1-cos)

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Khushi Agarwal 6 years, 3 months ago

I think answer is cosec theta as Sin=1/cosec and vice versa ATQ Sin theta × sin/cosec => Sin theta × cosec theta / sin theta => Sin theta wil be cancelled => Cosec theta Hence the answer is cosec theta

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A two digit number is 3 more then 4 times the sum of its digit.if 18 is added to the number the digit are reversed.find the number?

Posted by Dilip Rana 6 years, 3 months ago

CBSE > Class 10 > Mathematics