CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

f(x)= x^2-2x+5 Alpha and beta are the zeros of f(x) alpha+beta = -b/a= -(-2)/1= 2 alpha×beta = c/a= 5/1= 5 Now, new zeros are alpha+beta and 1/alpha+1/beta Sum of new zeros= alpha + beta+1/alpha +1/beta = 2 + (alpha+beta)/apha×beta = 2 + 2/5 = (10+2)/5 = 12/5 Product of new zeros = alpha+beta×1/alpha+1/beta = 2×(alpha+beta)/alpha×beta = 2×2/5 = 4/5 Quadratic polynomial= K[x^2-(sum of zeros)x+ product of zeros] = K[x^2-(12/5)x+4/5] = K[(5x^2-12x+4)/5] K is a constant Therefore, k=5 = 5[(5x^2-12x+4)/5] = 5x^2-12x+4

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Modal test paper number 2 question 14

Posted by Mukesh Kumar 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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Plz answer quick

Posted by Ram ? 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Ram ? 6 years, 1 month ago

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# Princess ????? 6 years, 2 months ago

Question❔❔❔

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2πr+d=perimeter of ___________

Posted by Ram ? 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Secret Girl...? 6 years, 2 months ago

triangle

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The total surface area of given solid figure is

Posted by Ujma Ansari 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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Shailendra Shukla 6 years, 2 months ago

Where is the figure??

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152x-378y =-74 -378x+152y = -604 Solve for x and y by elimination method

Posted by Shreya Lalit 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 2 months ago

The given equations are
{tex}152x - 378y = -74{/tex} ...(i)
{tex}-378x + 152y = -604{/tex}. ... (ii)
Clearly, the coefficients of x and y in one equation are interchanged in the other.
Adding (i) and (ii), we get
{tex}(152-378)x + (-378 +152) y = -(74 + 604){/tex}
{tex}\Rightarrow{/tex} {tex}(-226)x + (-226)y = -678{/tex}
{tex}\Rightarrow{/tex} {tex}(-226)(x + y) = -678{/tex}
{tex}\Rightarrow \quad ( x + y ) = \frac { - 678 } { - 226 } \Rightarrow x + y = 3{/tex}. ...(iii)
Subtracting (ii) from (i), we get
{tex}(152 + 378) x + (-378 - 152)y = (-74 + 604){/tex}
{tex}\Rightarrow{/tex}530x - 530y = 530
{tex}\Rightarrow{/tex} 530(x - y) = 530 {tex}\Rightarrow{/tex} x - y = 1. ... (iv)
Adding (iii) and (iv), we get 2x = 4 {tex}\Rightarrow{/tex} x = 2.
Subtracting (iv) from (iii), we get
2y = 2 {tex}\Rightarrow{/tex} y = 1.
Hence, x = 2 and y = 1

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What is exam pattern of 2019-20?

Posted by Gaurav Dhayal 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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Secret Girl...? 6 years, 2 months ago

Check Sample papers..

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O is the center of a circle and pt is the tangent drawn from the point p to the circle Secant pab passes thro ugh the centre o of the circle if pt=5cm and pa=3cm find the radius of the circle

Posted by Lucky Kumar 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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hello im abhinav help me in mathematics question we will discuss it on skype my skype id live:abhinavatal007 copy it and we will discuss on skype

Posted by Abhinav Atal Dimri 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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If sinA +cosA = root2cosA then find value of tanA

Posted by Suman Godara 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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Aadya Singh ? 6 years, 2 months ago

Tan A = √2 - 1

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Smaple paper.

Posted by Prince Mishra 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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Amar and Ashok are two friends standing at a corner of a rectangular garden. They wanted to drink water. Amar goes due north at a speed of 50m/min and Ashok due west at a speed of 60m/min. They travel for 534 X – Maths minutes. Amar reaches the tap and drink water. How far (minimum distance) is Ashok from the tap now.

Posted by Deepu Abraham 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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Deepika... ☺? 6 years, 2 months ago

What a coincidence

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Deepika... ☺? 6 years, 2 months ago

Hi deepu

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Find the discriminant of the quadratic equation 3x²-4x-2=0

Posted by Jeevanshi Sagar 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Aadya Singh ? 6 years, 2 months ago

D= b^2 - 4ac = (-4)^2 - 4×3(-2) = 16+24 = 40

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⛩️Singh?Empire (Believe In Study).? 6 years, 2 months ago

2√(-2)

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By shreya,deep,suhana pk,all my frnds specially my best frnd shreya ab mai sirf Saturday ko hi aunga,agar mai ne kisi ko hurt kiya h to plz sorry

Posted by #Mission Lbsnaa?? 6 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Deepika... ☺? 6 years, 2 months ago

Why ankesh... Why r u going??

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⛩️Singh?Empire (Believe In Study).? 6 years, 2 months ago

We have to gave priority to our study.....

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Shanaya ? 6 years, 2 months ago

Take care byee

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Find value of k

Posted by Anand Tripathi 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

📕Queen 📕Queen 6 years, 2 months ago

Where is question

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Yashi .... 6 years, 2 months ago

Where is eq.?

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Sec square 60 - 1 =2

Posted by Poonam Devi 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Naitik Adlakha 6 years, 2 months ago

Sec square 30 - 1= 2 (Root 3) square - 1 = 2 3 - 1 = 2 2 = 2 Hence proved

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(1+cot theta+tan theta )/sec2 theta - coaec2 theta = sin^2-cos^2

Posted by Abhay Shrivastava 6 years, 2 months ago

CBSE > Class 10 > Mathematics

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to fill a swimming pool two pipes are used if the pipe of larger diameter used for 4 hours and the pipe of smaller diameter for 9 hours only half of the pool can be filled find how long it would take for each pipe to fill the pool separately if the pipe of smaller diameter takes 10 hours more than the pipe of larger diameter to fill the pool

Posted by Shreya Lalit 6 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

⛩️Singh Empire? (Believe In Study)? 6 years, 2 months ago

20 and 30

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Aadya Singh ? 6 years, 2 months ago

So, time taken by larger pipe to fill the pool is 20 hrs. and time taken by smaller pipe is 30 hrs.

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Aadya Singh ? 6 years, 2 months ago

Let x hours be the total time taken by the larger pipe to fill the tank. So, in 1 hour it would fill 1/x part of tank. Similarly, y hours are needed for the smaller pipe. Then, in 1 hour it would fill 1/y part. A.T.Q - y= 10 + x......(1) And , 4/x + 9/y = 1/2.....(2) . Put the value of y in (2) , we get, 4/x + 9/ 10+x = 1/2 => x^2-16x-80=O => (x-20) (x+4) => Either x=20 or x= -4 . Since, the value of x can't be negative. So, x = 20 and y = x+10 = 20+10=30

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Along a road lie an odd number of stones place at intervals of 10 metres. These stones have to be assembled around the middle stones. A person can carry only one stone at a time. Aman carried the job with one of the end stones by carrying them in succession. In carrying all the stones he covered a distance of 3 km. Find the number of stones.

Posted by Soumyaranjan Patel 6 years, 2 months ago

CBSE > Class 10 > Mathematics