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  • 2 answers

Akshit ???? 6 years, 2 months ago

Hiii

Sahil Singh 6 years, 2 months ago

Hlo....
  • 3 answers

Qwerty G 6 years, 2 months ago

The right ans is 14 k

Aadya Singh ? 6 years, 2 months ago

14 k

Ram ? 6 years, 2 months ago

16k
  • 2 answers

Naruto Uzumaki??? 6 years, 2 months ago

Oh yeah i just forgot about those value. Anyways thank you??

Palak Genius 6 years, 2 months ago

Because since 30 is 1/2
  • 2 answers

Rohit Kumar 6 years, 2 months ago

In ΔABC, XY || AC and area of ΔBXY = area of quadrilateral XYCA ⇒ ar (ΔABC) = 2.ar (ΔBXY) ----------------(1) XY || AC and BA is a transversal. ⇒ ∠BXY = ∠BAC --------------------------- (2) So, In ΔBAC and ΔBXY, ∠XBY = ∠ABC (common angle) ∠BXY = ∠BAC [from equation (2)] ⇒ ΔBAC ~ ΔBXY ⇒ ar(ΔBAC) / ar(ΔBXY) = BA2 / BX2 ⇒ BA = √2 BX ⇒ BA = √2 (BA – AX) ⇒ (√2 – 1) BA = √2 AX ⇒ AX/XB = (√2 – 1) / √2

Rohith Mathew 6 years, 2 months ago

WTF?Geography=\Maths.Ass
  • 5 answers

Ramana Pirla??? 6 years, 2 months ago

a²+b²+2ab

Rohit Kumar 6 years, 2 months ago

A square +b square+2ab

Aadya Singh ? 6 years, 2 months ago

a^2 + b^2 + 2ab

Palak Genius 6 years, 2 months ago

a2 +b2+2ab

Rohith Mathew 5 years, 8 months ago

Die you bitch!Suck your *****
  • 1 answers

Ram Kushwah 6 years, 2 months ago

15tanA=14

tanA =14/15

tan2A=2tan2A/1-tan2A

=2*(14/15)/(1-225/196)

tan2A=28/15/29/225=420/29

=======================================

Now 2sinAcosA/cos2A-sin2A

=sin2A/cosA=tan2A

=420/29

  • 1 answers

Ram Kushwah 6 years, 2 months ago

We know that area of an equilateral triangle with side a

={tex}\sqrt3{/tex} a2/4

now let side of square =x

then area of equilateral triangle on one side

A1={tex}\sqrt3{/tex} x2/4--------------------------(1)

If length of diagonal is d then

d2=x2+x2=2x2

area of equilateral traingle at diagonal

A2=={tex}\sqrt3{/tex} *2x2/4

=2*({tex}\sqrt3{/tex} a2/4)

=2A1

hence proved

 

  • 4 answers

Aadya Singh ? 6 years, 2 months ago

Approx 8

Atharva Jain 6 years, 2 months ago

no its approx 8 7.777

Atharva Jain 6 years, 2 months ago

10

Ashmit Modi 6 years, 2 months ago

Approx 8 is the answer
  • 1 answers

Aadya Singh ? 6 years, 2 months ago

When it's denominator is not in the form of 2^m × 5^n , then the number is non- terminating.
  • 4 answers

Rishi Sharma 6 years, 2 months ago

And you

Rishi Sharma 6 years, 2 months ago

Reply pls

Rishi Sharma 6 years, 2 months ago

Ok

Rishi Sharma 6 years, 2 months ago

We know that, √2 = 1.4142135..... √3 = 1.73205080...... As we know that rational numbers are those decimal numbers which are either terminating or repeating. So, you can given any terminating or repeating decimal number between 1.4142135 ...... and 1.73205080 ....... as your answer. Thus your answer can be any of the following rationals: 1.415, 1.416, 1.417, 1.532, 1.582, 1.60, 1.62, 1.70, 1.72 etc. Potenz root 4 (2) is a rational no.between root 2 and root 7...as simple as that :)
  • 0 answers
  • 5 answers

? ? 6 years, 2 months ago

Yes

Akshit Panchal 6 years, 2 months ago

Yr use mnane me help to kr diye

Sahil Singh 6 years, 2 months ago

Hey

? ? 6 years, 2 months ago

Yhi hu

⭐⭐⭐Diya⭐⭐⭐ 6 years, 2 months ago

Hi
  • 1 answers

Qwerty G 6 years, 2 months ago

Center of angle of sector =360/12=30 Radius of circle =14 cm Area of sector =22/7×14×14×30/360=153/3=51.3333.......
  • 3 answers

Qwerty G 6 years, 2 months ago

(100 -100)/(100-100)=2 (10)^2 -(10)^2/10(10-10) (10+10)(10-10)/10(10-10) (10+10)/10 20/10 =2

Rufra Pratap Singh Rathore 6 years, 2 months ago

100-100/100-100 =(10+10) (10-10)/10(10-10) =10+10/10 =20/10 =2

Vedang Nain 6 years, 2 months ago

100-100÷100-100 = 2 =>(10) square+(10) square ÷10 (10-10) =2 =>(10+10)(10-10)÷10(10-10) =2 =>(10+10)÷10=2 =>20÷10=2 =>2=2 Hence proved
  • 0 answers
  • 2 answers

Rohit Kumar 6 years, 2 months ago

Converse of Basic Proportionality Theorem Statement If a line divides any two sides of a triangle (Δ) in the same ratio, then the line must be parallel (||) to the third side. Diagram Given In ΔABC, D and E are the two points of AB and AC respectively, such that, AD/DB = AE/EC. To Prove DE || BC Proof In ΔABC, given, AD/DB = AE/EC ----- (1) Let us assume that in ΔABC, the point F is an intersect on the side AC. So we can apply the Thales Theorem, AD/DB = AF/FC ----- (2) Simplify, in (1) and (2) ==> AE/EC = AF/FC Add 1 on both sides, ==> (AE/EC) + 1 = (AF/FC) + 1 ==> (AE+EC)/EC = (AF+FC)/FC ==> AC/EC = AC/FC ==> EC = FC From the above, we can say that the points E and F coincide on AC. i.e., DF coincides with DE. Since DF is parallel to BC, DE is also parallel BC Hence the Converse of Basic Proportionality therorem is proved

Harsh Sethi 6 years, 2 months ago

Ex14.1
  • 0 answers
  • 0 answers
  • 3 answers

Bikram Bal 6 years, 2 months ago

Tan 2A=cot(A-18) cot(90-2A)=cot(A-18) 90-2A=A-18 90+18=A+2A 108=3A 108/3=A A=36

Yogita Ingle 6 years, 2 months ago

Ratios of Complementary angles ,

Two angles are said to be Complementary , if their sum is equal

to 90°.

As you know that ,

Cot ( 90 - x ) = tan x

According to the problem given,

Tan 2A = cot ( A - 18 )

Cot ( 90 - 2A ) = cot ( A - 18 )

Remove the cot both sides

we get ,

90 - 2A = A - 18

-2A - A = - 18 - 90

- 3A = - 108

A = ( - 108 ) / ( - 3 )

A = 36°

Aadya Singh ? 6 years, 2 months ago

A = 36
  • 7 answers

Ram ? 6 years, 2 months ago

0.23

Prashant Chaudhary 6 years, 2 months ago

Hlo ?

Aaliya Yduvanshi.... 6 years, 2 months ago

Our calculations..

Safaqnaz Khan 6 years, 2 months ago

This app

Aadya Singh ? 6 years, 2 months ago

What was you checking?

Safaqnaz Khan 6 years, 2 months ago

I was just checking

Aadya Singh ? 6 years, 2 months ago

0.23

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