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Sia ? 6 years, 2 months ago
Distance of point from x-axis {tex}= | a |{/tex}
Distance of point from y-axis = 4
A.T.Q.{tex}| a | = \frac { 1 } { 2 } \times 4{/tex}
{tex}\Rightarrow | a |{/tex} = 2
{tex}\Rightarrow{/tex} {tex}a = \pm 2{/tex}
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Sia ? 6 years, 2 months ago
cosec A + cot A = p
{tex}\frac{1}{sinA}{/tex} + {tex}\frac{cosA}{sinA}{/tex}= p
1 + cosA = psinA
Squaring both the sides
(1 + cosA)2 = p2 (sinA)2
(1 + cosA)2 = p2 (1 - (cos)2)
(1 + cosA)2 = p2 (1 - (cos)) (1+cosA)
1 + cosA = p2 (1 - cosA)
cosA = (p2-1)/(p2+1)
Hence proved
Posted by A Vignesh 6 years, 2 months ago
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Ram Kushwah 6 years, 2 months ago
TOTAL EVENTS ARE
HH,TT,HT,TH
a) Atlease one head are HH,HT,TH
so P(E)=3/4
b) one head and one tale are : HT,TH
P(E)=2/4=1/2
Posted by Karan Kumar 6 years, 2 months ago
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Jatin Rao 6 years, 2 months ago
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