Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Hashmita Chelani 6 years, 2 months ago
- 0 answers
Posted by Aman Patel 6 years, 2 months ago
- 0 answers
Posted by Vishal Saini 6 years, 2 months ago
- 6 answers
Posted by Shashank Agarwal 6 years, 2 months ago
- 2 answers
Pragati Jain 6 years, 2 months ago
Posted by ᥫ᭡ㅤᏒᴀᴜsʜꫝɴ .. 6 years, 2 months ago
- 7 answers
Posted by Diya Panchal 6 years, 2 months ago
- 3 answers
Yogita Ingle 6 years, 2 months ago
The HCF of 126 and 168 is 42.
Steps to find HCF
Find the prime factorization of 126
126 = 2 × 3 × 3 × 7
Find the prime factorization of 168
168 = 2 × 2 × 2 × 3 × 7
To find the gcf, multiply all the prime factors common to both numbers:
Therefore, HCF = 2 × 3 × 7
GCF = 42
Posted by Rumi Singh 6 years, 2 months ago
- 3 answers
Sahil ??? 6 years, 2 months ago
Posted by Mohammed Shareef 6 years, 2 months ago
- 3 answers
Mangalleibi Kongbam 6 years, 2 months ago
Aadya Singh ? 6 years, 2 months ago
Posted by Ankit Thakur 6 years, 2 months ago
- 1 answers
Posted by Dk Somesh 6 years, 2 months ago
- 3 answers
Posted by Rahul K Mishra 6 years, 2 months ago
- 3 answers
Posted by Akshit . 6 years, 2 months ago
- 31 answers
~ Honey... ? 6 years, 2 months ago
~ Honey... ? 6 years, 2 months ago
Rahul K Mishra 6 years, 2 months ago
Yashi .... 6 years, 2 months ago
Posted by Mohit Rathi 6 years, 2 months ago
- 1 answers
Tara ?? 6 years, 2 months ago
Posted by Yangchen Sherpa 6 years, 2 months ago
- 2 answers
Kamal Pandey 6 years, 2 months ago
Posted by Christy Baiju 6 years, 2 months ago
- 2 answers
Tara ?? 6 years, 2 months ago
Posted by Dhrumil Bhagat 6 years, 2 months ago
- 1 answers
Sia ? 6 years, 2 months ago
Let us suppose that the Radius of the bigger end of the frustum (bucket) of cone = R = 20 cm
Suppose r denotes the Radius of the smaller end of the frustum (bucket) of the cone = 8 cm
Height = 16 cm
Now, Volume = {tex}\frac{1}{3} \pi{/tex}h[R2 + r2 + Rr]
= {tex}\frac{1}{3} \times \frac{22}{7} \times{/tex}16[202 + 82 + 20(8)]
= {tex}\frac{352}{21}{/tex}[400 + 64 + 160]
= {tex}\frac{352\times 624}{21}{/tex}
= {tex}\frac{219648}{21}{/tex}
= 10459.43 cm3
Now,
Slant height of the cone = l = {tex}\sqrt{(R -r)^2 + h^2}{/tex}
l = {tex}\sqrt{(20 -8)^2 +16^2}{/tex}
l = {tex}\sqrt{12^2 +16^2}{/tex}
l = {tex}\sqrt{144 + 256}{/tex}
l = {tex}\sqrt{400}{/tex}
l = 20 cm
Slant height is 20 cm
Now,
Surface area = {tex}\pi{/tex}[R2 + r2 + (R + r){tex}\times{/tex}l]
= {tex}\frac{22}{7}{/tex}[202 + 82 + (20 + 8){tex}\times{/tex}16]
= {tex}\frac{22}{7}{/tex}[400 + 64 + 448]
= {tex}\frac{22}{7} \times{/tex}912
= {tex}\frac{20064}{7}{/tex}
= 2866.29 cm2
Thus, the surface area of the bucket is 28866.29
Posted by Satvik Vardhaan 6 years, 2 months ago
- 2 answers
Posted by Dinesh Gangwar 6 years, 2 months ago
- 6 answers
Posted by Raj Pushkar 6 years, 2 months ago
- 3 answers
Posted by Vaishnavi Dalvi 6 years, 2 months ago
- 1 answers
Gaurav Seth 6 years, 2 months ago
x is positive real no
As we know square root of prime no is always irrational
So if x is prime no
Then √x will lie between 0 and x
So here there exists irrational
Now
If x is irrational
then its any fraction will also be irrational
So here y exists also
Now if x is not a prime and perfect square no
Then
As Between 0 and perfect square no except 1 there always exists a prime no ,also there exists square root of prime
Ex lets take x= 4
So 0 , 1 ,2,3,4
There exists 2,3 both prime
Also √2, √3 also lies between 0 and 4
So it would also give irrational no y
Posted by Yogendra Gupta 6 years, 2 months ago
- 1 answers
Posted by Prince Yadaw 6 years, 2 months ago
- 18 answers
Posted by Lakshya Rathore 6 years, 2 months ago
- 1 answers
Riddhima Yadav 6 years, 2 months ago
Posted by Naitik Sharma 6 years, 2 months ago
- 1 answers
Posted by Pallavi Singh 6 years, 2 months ago
- 6 answers
Aadya Singh ? 6 years, 2 months ago
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
