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  • 5 answers

Aadya Singh ? 6 years, 2 months ago

1/4 l^2 ( π + 24)

Sahil ??? 6 years, 2 months ago

95l^2/4 or l^2{(24+π)/4}

Sahil ??? 6 years, 2 months ago

Oh it is l

Prince Yadaw 6 years, 2 months ago

1/4 [l 2 (24+π)

Sahil ??? 6 years, 2 months ago

What is the length of edge or diameter
  • 4 answers

Farman Ali 6 years, 1 month ago

D2-D1

Shruti Kumari 6 years, 2 months ago

a2-a1

Sahil ??? 6 years, 2 months ago

Subtract any term of the ap from ot's succeding term to get the common difference,it is usually given as a2-a1.

Aadya Singh ? 6 years, 2 months ago

Common difference = second term - first term
  • 4 answers

Aadya Singh ? 6 years, 2 months ago

Mine ..... Your solution is right ?

Sahil ??? 6 years, 2 months ago

Your's or mine

Aadya Singh ? 6 years, 2 months ago

LHS - CosA/(1-tanA) + sinA/(1-cotA) => cosA/cotA + sinA/tanA => cosA/cosA/sinA + sinA/sinA/cosA => cosA×sinA/cosA + sinA × cosA/sinA => sinA + cosA ( since, sinA get cancelled by sinA and cosA get cancelled by cosA) . Now, LHS = RHS. So, it's prove.

Sahil ??? 6 years, 2 months ago

LHS=cosA/(1-tanA)+sinA/(1-cotA). =cosA/(1-sinA/cosA) +sinA/(1-cosA/sinA). =cosA/(cosA-sinA)/cosA+sinA/(sinA-cosA)/sinA. =cos^2A/(cosA-sinA)+sin^2A/(sinA-cosA). =(-1)(cos^2A)/(-1)(cosA-sinA)+sin^2A/(sinA-cosA). = -cos^2A/(sinA-cosA)+sin^2/(sinA-cosA). =(sin^2A-cos^2A)/(sinA-cosA). =(sinA+cosA)(sinA-cosA)/(sinA-cosA). =sinA+cosA.
  • 0 answers
  • 3 answers

Aadya Singh ? 6 years, 2 months ago

123

Sahil ??? 6 years, 2 months ago

HCF=123

Kamal Yadav 6 years, 2 months ago

123
  • 1 answers

Rahul Ranjan Singh 6 years, 2 months ago

Plz send questions
  • 3 answers

Rahul Ranjan Singh 6 years, 2 months ago

Circumference of circle=88cm So,2πr=88 Radius=14cm Area of sector=Φ°\360°*πr² So,72°/360°*πr² Hence,72°/360°*22/7*14*14 =123.5cm²

Chandan Kumar 6 years, 2 months ago

Thanks

Sahil ??? 6 years, 2 months ago

123.2 cm^2
  • 0 answers
  • 0 answers
  • 1 answers

Mayank Sharma 6 years, 2 months ago

Curved surface area = 2πr² and total surface area=3πr²
  • 1 answers

Sahil ??? 6 years, 2 months ago

a=5 and b=-2
  • 2 answers

~ Honey... ?? 6 years, 2 months ago

It's Trigonometry

Rocking Star 6 years, 2 months ago

It's trigonometry
  • 1 answers

Devansh Pandey 6 years, 2 months ago

Sec A= h/b = 13/12. Let h= 13x and b=12x. Then p= √13x * 13x - 12x * 12x. = √169x² - 144x². = √25x². = 5x. 1. CosecA= h/p. =13x/5x. =13/5. 2. CotA =b/p. = 12x/5x. =12/5. 3. SinA = p/h. =5x/13x. =5/13. 4. CosA = b/h = 12x/13x = 12/13. 5. TanA = p/b = 5x/12x = 5/12
  • 1 answers

Ujjwal Ujjwal 6 years, 2 months ago

ans In LHS 1+cos A/SinA each side dividing by1-cosA (1-cosA)×(1+cosA)/(1-cosA)×sinA 1-cos^2A/1-cosA×sinA we know the property =1-cos^2A=sin^2A
  • 1 answers

Student Lyf ? 6 years, 2 months ago

For what sample paper or anything else.?
  • 1 answers

Sia ? 6 years, 2 months ago

Width of the room left uncovered = 0.25 m 
Now, Length of the room to be carpeted = 4.9 - (0.25+0.25) = 4.9 -0.5 = 4.4 m
Breadth of the room be carpeted = 3.5 - (0.25+0.25) = 3.5-0.5 = 3 m
Area to be carpeted = 4.4 {tex}\times{/tex} 3 = 13.2 m2
Breadth of the carpet 80 cm = 0.8 m
We know, Area of the room = Area of the carpet
 Length of a carpet = {tex}\frac { \text { Area to be carpeted } } { \text { Width of a carpet } }{/tex} = {tex}\frac { 13.2 } { 0.80 }{/tex} = 16.5
Cost of carpet = Rs. 80 per metre
{tex}\therefore{/tex} cost of 16.5 m carpet = Rs. 80 {tex}\times{/tex} 16.5 = Rs. 1320

  • 1 answers

Sia ? 6 years, 2 months ago

You can check our website and app.

  • 2 answers

Sahil ??? 6 years, 2 months ago

58.65

Aadya Singh ? 6 years, 2 months ago

58.65
  • 6 answers

Om Gupte 6 years, 2 months ago

3

Md Zaki 786 6 years, 2 months ago

3

Sumit Gautam 6 years, 2 months ago

3

Tannu ? 6 years, 2 months ago

3

Aadya Singh ? 6 years, 2 months ago

3

Arshdeep Singh 6 years, 2 months ago

5
  • 1 answers

Honey... ?? 6 years, 2 months ago

What is this
  • 1 answers

Honey... ?? 6 years, 2 months ago

√(x2 - x1)^2 + (y2 - y1) ^2
  • 1 answers

Devansh Pandey 6 years, 2 months ago

If in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio and hence the two triangles are similar.
  • 2 answers

Supriya Sharma 6 years, 2 months ago

a=bq + r

Prince Yadaw 6 years, 2 months ago

Euclid’s Division Algorithm (lemma): According to Euclid’s Division Lemma if we have two positive integers a and b, then there exist unique integers q and r such that a = bq + r, where 0 ≤ r ≤ b. (Here, a = dividend, b = divisor, q = quotient and r = remain
  • 1 answers

Devansh Pandey 6 years, 2 months ago

Let a be a positive integer and b = 3. Then r =0,1or2. Case first when r is equal to zero. a= ( 3q+0)² =9q² =3(3q²)=3m where m is equal to 3q². Case second when r is equal to 1. a= (3q+1)²= (3q)²+ 2*3q +1²= 9q²+6q+1 =3(3q²+2q)+1 = 3m+1. Where m is equal to 3q²+2q. Case 2nd when r is equal to 2. a= (3q+2)² = (3q)²+ 2*3q*2 +2² =9q²+12q+4 =9q²+12q+3+1 =3(3q²+12q+1)+1 =3m+1. Where m is equal to 3q²+12q+1
  • 3 answers

It'S Me Aadarsh 6 years, 2 months ago

a²-b² ?

Abhinav ? 6 years, 2 months ago

a^2-b^2

Sahil ??? 6 years, 2 months ago

a^2-b^2
  • 3 answers

Sahil ??? 6 years, 2 months ago

Since the ponts are collinear thus area=0. p(q-2)+0(2-0)+2(0-q)=0 => pq-2p+0+0-2q=0. pq-2p-2q=0 => pq=2p+2q => pq=2(p+q). 1/2=(p+q)/pq => 1/2=p/pq+q/pq =>1/2=1/q+1/p. 1/p+1/q=1/2???

Aadya Singh ? 6 years, 2 months ago

How?

Sahil ??? 6 years, 2 months ago

(1)1/p+1/q=1/2
  • 4 answers

It'S Me Aadarsh 6 years, 2 months ago

Bcoz the value of pie is assumed only i.e. 22/7 and it has a million of decimal places.??

Prince Yadaw 6 years, 2 months ago

Because value of π is 22/7 if we divide so not ending so it is non terminating vapue so it is irrational

Sahil ??? 6 years, 2 months ago

Because the value of π is 22/7 which gives non terminating non repeating value.So it is an irrational number.

Student Lyf ? 6 years, 2 months ago

Because it has a different value at each step whenever we divide 22/7 at each rime we get a new value and the calculation never ends....
  • 9 answers

Rohan Raj 6 years, 2 months ago

ab aisa naam rakhega to kon janega

Rohan Raj 6 years, 2 months ago

sorry nihit bro....

Naughty Oracle 6 years, 2 months ago

Ao school

Naughty Oracle 6 years, 2 months ago

Apna frnd ko bhul gya re pushy??

Honey... ?? 6 years, 2 months ago

hi

Sahil ??? 6 years, 2 months ago

Radius=7×cuberoot21/44

Rohan Raj 6 years, 2 months ago

bhul gaya....

Rohan Raj 6 years, 2 months ago

I don't know about this destroyer...

Honey... ?? 6 years, 2 months ago

Who is Destroyer??? ??

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