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  • 1 answers

Aadya Singh ? 6 years, 1 month ago

One rational number is 0.27 and one irrational number is 0.266266626666.......
  • 3 answers

Archana Kumari 6 years, 1 month ago

(3)again by Pythagorus theorem you can find the length of the third side.

Archana Kumari 6 years, 1 month ago

(1) draw a perpendicular that bisect the base. (2) by Pythagorus theorem find the length of the perpendicular.

Aadya Singh ? 6 years, 1 month ago

By using Pythagoras theorem, i.e. , (Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2
  • 2 answers

Jatin Gupta 6 years, 1 month ago

Kab hai

Jyoti Pant 6 years, 1 month ago

no dear exam march ma hota hai . Feb ma optional subject ka exam hota hai. Main subject ka exam march ma hota
  • 9 answers

Archana Kumari 6 years, 1 month ago

Ans-45.089

Archana Kumari 6 years, 1 month ago

Ans-150.857143 Or 150.85

Sahil ??? 6 years, 1 month ago

Back

Sahil ??? 6 years, 1 month ago

Deep is nack

Radha Sharma 6 years, 1 month ago

No its answer. Is4(4π-3√3)

~ ¤ 6 years, 1 month ago

Ji

Sahil ??? 6 years, 1 month ago

Can someone give the full solution?

Chandan Kumar 6 years, 1 month ago

30

Abhimanyu S 6 years, 1 month ago

30
  • 2 answers

Sahil ??? 6 years, 1 month ago

HCF is 45

Rahul Thakur 6 years, 1 month ago

225=135*1+90 135=90*1+45 90=45*2+0 HCF=45
  • 1 answers

Jay Kumar Sharma 6 years, 1 month ago

Nope.Buddy
  • 2 answers

Aadya Singh ? 6 years, 1 month ago

Height of pillar = (400/3)m and it's distance from the hill is (200/√3) m

Sahil ??? 6 years, 1 month ago

Height of the tower=(400/3)m and it's distance from hill=(200/√3)m.
  • 1 answers

Gaurav Seth 6 years, 1 month ago

 PS = 12 cm
As PQ = QR =RS 
∴ PQ =QR =RS = 1/3 x PS = 1/3 x 12 = 4 cm.
QS = 2 PQ 
QS = 2 x 4 = 8 cm
∴ Area of shaded region = Area of semicircle with PS as diameter + Area of semicircle with PQ as diameter – Area of semicircle with QS as diameter.
= ½ [ 3.14 x 6 2 + 3.14 x 2 2 - 3.14 x 4 2 ]
= ½ [ 3.14 x 36 + 3.14 x 4 – 3.14 x 16 ] 
= ½ [ 3.14 ( 36 + 4 – 16)]
= ½ ( 3.14 x 24 ) = ½ x 75.36 
∴ Area of shaded region = 37.68 cm2

  • 2 answers

Chandan Kumar 6 years, 1 month ago

√37

Gaurav Seth 6 years, 1 month ago

Let

A ( 5 , -2)

B (6 ,  4)

C ( 7 , -2)

 

Length of each sides

 

AB = BC = √37

Hence verified that these vertices are of an isosceles triangles

  • 3 answers

Massenger Bhardwaj 6 years, 1 month ago

Root3÷2

Chandan Kumar 6 years, 1 month ago

√3/2
√3/2
  • 1 answers

Gaurav Seth 6 years, 1 month ago

To prove : 5-√3 is irrational

Proof: 
Let us assume that 5 -√3 is rational.

Let ,
 5 - √3 = r , where "r" is rational

5 - r = √3

Here,
LHS is purely rational.But,on the other hand ,RHS is irrational.
This leads to a contradiction.
Hence,5-√3 is irrational

  • 2 answers

Sahil ??? 6 years, 1 month ago

x=3 and y=10

Gaurav Seth 6 years, 1 month ago

Let the fraction be x/y

Given that
x+2/y =1/2 -----> equ i
x/y-1 =1/3 -----> equ ii

From i and ii
2(x+2) =1(y) -------> equ i
3(x) =1(y-1) -------> equ ii

=> 2x+4=y
3x=y-1

Subtract i and ii. we get

2x - y = -4
3x - y = -1
(-) (+) = (+)
______________
-x = -3
_____________

=> x=3
subtitute x=3 in equ i. we get

2(3+2)=y
=> 2(5) =y
=> y=10

Therefore the value of x and y are 3 and 10 respectively.

  • 2 answers

Sahil ??? 6 years, 1 month ago

SinA=1/3 and secA=3/8

Miss. 1234 6 years, 1 month ago

Can u plz check ur ques. again !!!because I've seen the same ques in ncert book ch-8 exercise-8.1 ques 4 in which " 15cotA =8 " is given.......and you've wrote only cotA =8 in ques...........
  • 2 answers

Sahil ??? 6 years, 1 month ago

Sides of square are 24 and 8.

Gaurav Seth 6 years, 1 month ago

Let the side of one square be x

Perimeter of this square = 4x

Given, Difference of perimeter of 2 squares = 64 m

Thus, Perimeter of the other square = (64 + 4x) m  

And, each side of this second square =  = (16 +x) m

According to the problem, sum of the areas of two squares is 640 

Since side of a square cannot be negative, each side of the square = 8 m.

And, each side of second square = (16+8) m = 24 m

  • 1 answers

Karnanshu Thakur 6 years, 1 month ago

Can't be done because it has no real roots
  • 2 answers

Rudra Menkudale 6 years, 1 month ago

Here, x=6 and y =3

Gaurav Seth 6 years, 1 month ago

Step-by-step explanation:

Let ABCD is a parallelogram with vertices  (1,2) ; (4,y) ; (x,6) ; (3,5) respectively.

As we know that

The mid-points of two diagonals must be same.

So, we will apply "Mid point rule":

Mid point of AC is given by

Mid point of BD is given by

Now, Mid point of AC = Mid point of BD

Hence, The value of x = 6 and y = 3.

  • 1 answers

Gaurav Seth 6 years, 1 month ago

You can get the idea on how the questions will come in board exams:

Click on the below link to get the sample paper issued by CBSE :

Basic paper:

<a href="http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsBasic_SQP.pdf">http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsBasic_SQP.pdf</a>

Standard paper:

<a href="http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsStandard_SQP.pdf">http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsStandard_SQP.pdf</a>

  • 1 answers

Gaurav Seth 6 years, 1 month ago

Let √2 be a rational number 

Therefore, √2= p/q  [ p and q are in their least terms i.e., HCF of (p,q)=1 and q ≠ 0

On squaring both sides, we get 
                   p²= 2q²                                                                                    ...(1)
Clearly, 2 is a factor of 2q²
⇒ 2 is a factor of p²                                                                    [since, 2q²=p²]
⇒ 2 is a factor of p

 Let p =2 m for all m ( where  m is a positive integer)

Squaring both sides, we get 
            p²= 4 m²                                                                                          ...(2)
From (1) and (2), we get 
           2q² = 4m²      ⇒      q²= 2m²
Clearly, 2 is a factor of 2m²
⇒       2 is a factor of q²                                                      [since, q² = 2m²]
⇒       2 is a factor of q 

Thus, we see that both p and q have common factor 2 which is a contradiction that H.C.F. of (p,q)= 1

     Therefore, Our supposition is wrong

Hence √2 is not a rational number i.e., irrational number.

  • 4 answers

Gaurav Seth 6 years, 1 month ago

You can get the idea on how the questions will come in board exams:

Click on the below link to get the sample paper issued by CBSE :

Basic paper:

<a href="http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsBasic_SQP.pdf">http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsBasic_SQP.pdf</a>

Standard paper:

<a href="http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsStandard_SQP.pdf">http://cbseacademic.nic.in/web_material/SQP/ClassX_2019_20/MathematicsStandard_SQP.pdf</a>

Salik Shabab 6 years, 1 month ago

Trigonometery se 12 marks ka question aayega

Dhiraj Kumar 6 years, 1 month ago

There is very least difference between basic and standard you will not get any long questions in basic else everything is same

Salik Shabab 6 years, 1 month ago

Ncert book
  • 1 answers

Gaurav Seth 6 years, 1 month ago

Given:

The aeroplane when 3000 m high passes vertically above another aeroplane.  

Angle of elevation of the aeroplane’s at the same observation = 60°and 45°

To find:

How much high is the one plane to other = ?

Solution:

The height at which the aeroplane (1) is from the ground is of height = 3000m.

The observer is standing at point A from where he observe both the planes one at D and another at C

The height at which the aeroplane (2) is from the ground is of height = h meters.

To find the height difference between the two planes, we first have to find the height of the second plane

The angle for the second plane is 45, which means

Now equating the value of the length between the planes and the observer

The height of the second plane from the ground is 1732m

Therefore, the Distance between the planes or the second plane is (3000 – 1732) = 1268 m lower than the first plane,

The height that the first plane is from second plane is 1268 m.  

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  • 8 answers

Massenger Bhardwaj 6 years, 1 month ago

a^2+b^2+2ab

Uzair Saif 6 years, 1 month ago

A2+b2+2ab
Sorry for this ....
Sorry suhana g but ham log jo yek bar decide kar late use kabhi nahi badalte isiliya ham name nahi bata sakte....

Poorvika Malle 6 years, 1 month ago

a^2+2ab+b^2

User Dead? 6 years, 1 month ago

a² + b² + 2ab.
Kya yrr .....a^2+b^2+2ab

Abhinav ? 6 years, 1 month ago

(a+b)^2 = a^2+b^2+2ab
  • 3 answers

?(#Chocolate Lover)?? 6 years, 1 month ago

Right triangle??

Rahees Rana 6 years, 1 month ago

1/2× base × height

Massenger Bhardwaj 6 years, 1 month ago

1÷2 ×base×corresponding altitude
  • 1 answers

Aadya Singh ? 6 years, 1 month ago

All the solutions is given in this app...

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