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Pythagoras Theorem
Statement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
Given: A right triangle ABC right angled at B.
To prove: AC2 = AB2 + BC2
Construction: Draw BD
AC

Proof :
We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.
ADB 
ABC
So,
(Sides are proportional)
Or, AD.AC = AB2 ... (1)
Also,
BDC 
ABC
So, 
Or, CD. AC = BC2 ... (2)
Adding (1) and (2),
AD. AC + CD. AC = AB2 + BC2
AC (AD + CD) = AB2 + BC2
AC.AC = AB2 + BC2
AC2 = AB2 + BC2
Hence Proved.
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