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Yogita Ingle 6 years ago
A is on y axis and it's ordinate is 5
So coordinates of A is (0,5)
and coordinates of B is (-3,1)
Length of AB can be found out by using the distance formula
= √【(x1 -x2)^2 + (y1 -y2)^2】
= √【(-3-0)^2 + (1-5)^2】
=√【9 + 16】
=√25
=5
So length of AB is 5 units.
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Yogita Ingle 6 years ago
A(8, -9)
B(2, 3)
Here p divides the line segment joining point A(8, -9)
B(2, 3)
A(8, -9) lies on the 4 quadrant
And b point lies on the 1 st quadrant
We can get the division of point p by section formula
If AP:BP =1:2
Then the coordinates of p =
X = 8×2+2×1/2+1=6
Y=-9×2+3×1/2+1= -5
& (+, -) lies on 4th quadrant
Hence it will lie on the 4th quadrant
Posted by Harman Singh 6 years ago
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Yogita Ingle 6 years ago
The value of k must be less than or equal to 4.
Step-by-step explanation:
The given quadratic equation is
x2+4x+k=0
A quadratic equation ax2+bx+c=0 has real roots if
{tex}b^2-4ac\geq 0{/tex}
We have,
a=1,b=4,c=k
{tex}(4)^2-4(1)(k)\geq 0{/tex}
{tex}16-4k\geq 0{/tex}
{tex}16\geq 4k{/tex}
Divide both sides by 4.
{tex}4\geq k{/tex}
Therefore the value of k must be less than or equal to 4.
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