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Ask QuestionPosted by Ankesh ...... 6 years, 2 months ago
- 41 answers
Dr. Sanskari ?⚕️?⚕️ 6 years, 2 months ago
Dr. Sanskari ?⚕️?⚕️ 6 years, 2 months ago
Shreya .... 6 years, 2 months ago
Dr. Sanskari ?⚕️?⚕️ 6 years, 2 months ago
Shreya .... 6 years, 2 months ago
Posted by Mahbar Ali 6 years, 2 months ago
- 0 answers
Posted by Vraj Italiya 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are integers.
so, √5 = p/q
p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesn't occurs with √5 since its not an integer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.
Posted by Aysha Alam 6 years, 2 months ago
- 1 answers
Posted by Ali Gamer 34 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
Let the width be x.
then length be x + 4
As
l+b=36
x+(x+4)=36
2x+4=36
2x=36-4
2x=32
x=16.
Hence, The length of garden will be 20 m and width will be 16 m.
Posted by Mausam Singh 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
Let, x-2y=0 equation 1
and 3x+4y=20 equation 2
Now, we plot these two equations.
The graph of x-2y=0 is shown with green line.
The graph of 3x+4y=20 is shown with blue line.
The solution to this system will be their intersection point.
The intersection point of these graph is (4,2)
Refer the attached graph below.
Therefore, The solution to the given equation is at point (4,2) or x=4,y=2
Posted by Prabal Das 6 years, 2 months ago
- 6 answers
Ritika Singh 6 years, 2 months ago
Posted by Joti Joti 6 years, 2 months ago
- 0 answers
Posted by Singh Rahul 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
Let the cost of a pen be Rs 'x' and the cost of a pencil box be Rs. 'y'
As, the cost of 4 pens and 4 pencil boxes is Rs. 100
So, 4x + 4y = 100 .................(1)
And, three times the cost of a pen is Rs. 15 more than the cost of a pencil box.
So, 3x = y + 15
⇒ 3x - y = 15 ......................(2)
Now multiplying the equation (1) by 3 and equation (2) by 4, we get
⇒ (4x + 4y = 100)*(3) = 12x + 12y = 300 ................(3)
⇒ (3x - y = 15)*(4) = 12x - 4y = 60 ..........................(4)
Now, subtracting (4) from (3)
12x + 12y = 300
12x - 4y = 60
- + -
_________________
16y = 240
_________________
⇒ 16y = 240
⇒ y = 240/16
⇒ y = 15
Now, substituting the value of y = 15 in (2)
⇒ 3x - y = 15
⇒ 3x - 15 = 15
⇒ 3x = 15 + 15
⇒ 3x = 30
⇒ x = 30/3
⇒ x = 10
So, the cost of a pen is Rs. 10 and the cost of a pencil box is Rs. 15
Posted by Ankesh ...... 6 years, 2 months ago
- 4 answers
Posted by H Bansal 6 years, 2 months ago
- 1 answers
Posted by Pranav Shashidhar 6 years, 2 months ago
- 2 answers
Posted by Prince Gurjar 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
Distance of a point P (a, b) from X-axis is |b| and from Y-axis is |a|.
Therefore, the distance of point P(-3, -4) from X-axis is 4 (as distance is never negative).
Posted by Prarthana R 6 years, 2 months ago
- 2 answers
??Geetha Sree ?? 6 years, 2 months ago
Yogita Ingle 6 years, 2 months ago
A5 = 26
a + 4d = 260........... (1)
a10 = 51
a + 9d = 51...............(2)
Subtracting eq.(i) from eq.(ii) we get
d = 5
putting d = 5 in eq.(i) we get
a + 4(5) = 26
a + 20 = 26
a = 6
a15 = a + 14d
a15 = 6 + 14(5)
a15 = 6 + 70
a15 = 76
Hence the 15th term of the AP is 76.
Posted by Sameer Sameer 6 years, 2 months ago
- 1 answers
Posted by Vani Nagar 6 years, 2 months ago
- 0 answers
Posted by Deepa Sharms 6 years, 2 months ago
- 1 answers
Posted by Adarsh Sanyal 6 years, 2 months ago
- 2 answers
Yogita Ingle 6 years, 2 months ago
Let a be the first term and d be the common positive difference .
Then,A.P is
a,a+d,a+2d,a+3d,a+4d
Sum of five distinct positive integers=10020
Sum of nth term of A.P
{tex}S_n=\frac{n}{2}(a+a_n){/tex}
Where a=First term
a_n=nth term of A.P
n=Total number of terms in A.P
Using the formula
{tex}10020=\frac{5}{2}(a+a_n){/tex}
{tex}a+a_n=\frac{10020\times 2}{5}=4008{/tex}
nth term of A.P is given by
{tex}a_n=a+(n-1)d{/tex}
Where d=Common difference of A.P
Using the formula
{tex}a_5=a+4d{/tex}
Substitute the value
a+a+4d=4008
2(a+2d)=4008
{tex}a+2d=\frac{4008}{2}=2004{/tex}
a=2004-2d
Substitute the value of a
{tex}a_5=2004-2d+4d=2004+2d{/tex}
d=0 cannot be consider because d is positive
Therefore, possible value of d=1,2,3,..
Substitute d=1
{tex}a_5=2004+2(1)=2006{/tex}
for d=2
{tex}a_5=2004+2(2)=2008{/tex}
Hence, the smallest possible value of last term=2006
Posted by Naina Goyal 6 years, 2 months ago
- 0 answers
Posted by Aayush Taxak 6 years, 2 months ago
- 2 answers
Naina Goyal 6 years, 2 months ago
Jaimina Gharia 6 years, 2 months ago
Posted by Sunil Sunil 6 years, 2 months ago
- 2 answers
Sona Kapoor 6 years, 2 months ago
Posted by Tahira Butool 6 years, 2 months ago
- 3 answers
Anshul Yadav 6 years, 2 months ago
Posted by Moina Gogoi 6 years, 2 months ago
- 1 answers
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Mayank Mall 6 years, 2 months ago
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