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In the given figure FG is the tangent to the circle with center A. If angle DCB=15° and CE=DE find angle GCE and angle BCE

Posted by Account Deleted 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Ch 4 exercise

Posted by Anas Shaikh 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

A mother is five times as hold as her daughter. Five years later the mother will be three times as old as her daughter . Find The sum of their present ages in years .

Posted by Kalpesh Patidar 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

solve The pair of linear equation X=5and y=7 graphically

Posted by Harsha Gowda J 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Ex 3.1 sol

Posted by Kishor..😎✨️ Patil'S.. 😎 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Prove that root 5 be irrational

Posted by Ujjwal Pandey 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Divyanshi Mishra 1 year, 3 months ago

Assume that √5 is a rational number √5=p/q , where p&q are co- prime p=√5q On squaring both sides , we get P^2 =5q^2 (equation 1) P^2 is divisible by 5 P is also divisible by 5 ( by theorem) P=5m From equation 1 =(5m)^2 = 5q^2 = 25m^2= 5q^2 =q^2 =5m q^2 is divisible by 5 q is also divisible by 5 (by theorem) Here we can conclude that p&q both have atleast 5 as a common factor Which contradict our assumption that p&q are co-prime Hence √5 is an irrational number

ANSWER

Rohan mother is 26yrs older than him the product of their ages in years 3 from now will be 360

Posted by Parth Singh 1 year, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Tanvi Verma 1 year, 3 months ago

Let rohan age = x His mother age =x+26 After 3 years Rohan age =x+3 His mother age=x+29 ATQ (x+3)(x+29)=360 Solve this equation you get your answer if x is negative or in fraction neglect it because age cannot be negative or not in fraction .

Kunal Chauhan 1 year, 3 months ago

let the age of Rohan be x and his mother age be x+26 case 1 x(x+26)=360 x² + 26x = 360 x²+26x-360=0 so x=10(Rohan age) mother age =36

ANSWER

Real roots

Posted by Preetika Singh 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the sum of exponents of prime factor in the prime factorisation of 325

Posted by Lavi Sagar 1 year, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Amber Baderai 1 year, 3 months ago

3

Nikunj Gupta 1 year, 3 months ago

3

ANSWER

Bhai kaise chal rhi hai 10🗿 jandigi depression m chal rhi hai meri tu0 _-_

Posted by Rahul 🗿 V 1 year, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Rahul 🗿 V 1 year, 3 months ago

KOye na jald depression ke din khatam honge :3

Megha Thakur 1 year, 3 months ago

Same here yr

ANSWER

If a triangle is having one side of 8cm and other two sides are of 4cm each then which type of triangle is it? a) Scalene b) Equilateral c) Isosceles d) None of the above

Posted by Devansh Yadav 1 year, 3 months ago

CBSE > Class 10 > Mathematics

5 answers

Neena Verma 1 year, 3 months ago

C

Balakumaran Sivakumar 1 year, 3 months ago

Isosceles

Nikunj Gupta 1 year, 3 months ago

C

Mayank Saarthak 1 year, 3 months ago

Isosceles triangle

Haret Gujjar 1 year, 3 months ago

(c) isosceles

ANSWER

Determine if the points (1,5),(2,3)and(-2,-11)are collinear

Posted by Rishabh Jain 1 year, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Mayank Singh 1 year, 3 months ago

1 st find the value of AB ,BC AND AC BY DISTANCE FORMULA AND CHECK AB +BC =AC IF ITIS EQUAL SO THESE POINTS ARE COLLINEAR

Mayank Saarthak 1 year, 3 months ago

Yes these points are collinear..

Bichitra Bhatta 1 year, 3 months ago

8+48

Haret Gujjar 1 year, 3 months ago

Yes

ANSWER

Due to covid pandemic, no schools are opened. Arpita was at home for 7 month

Posted by Hemapriya Hemapriya 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If α, β are the zeroes of f(x)=px2−2x+3p and α+β=αβ, then the value of p is :

Posted by Aneesh Kumar Patro 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Kumar 1 year, 3 months ago

First of all factorise them. Solve it like polynomials. Then let first answer be alpha and second be beeta

ANSWER

Point A is on x-axis, point B is on y-axis and the point P lies on line segment AB, such that P (4,-5) and AP: PB 5: 3. Find the coordinates of point A and B. (

Posted by Blah Blah 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the greatest number that will divided by 445, 572and 699 leaving reminder 4,5 and 6 respectively

Posted by Ojasv Chattar 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Kumar 1 year, 3 months ago

(445-4),(572-5),(699-6) and the answer of these three no. Find their HCF.

ANSWER

Seema rights test to upgrade her level the test has 25 questions for a total score of 150 points among 25 questions each multiple choice questions car is 3 marks and descriptive type of question carries 8 marks

Posted by Megha Thakur 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Cottheta 2 find 4sin -3cos/2sin +6cos

Posted by Archit Verma 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Miraj Sharma 1 year, 3 months ago

Hii

ANSWER

If sin theta is 1/2 and theta is acute angle then (3cos theta - 4cos cube theta

Posted by Hari Rithi 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Anik Kumar Chaudhary 1 year, 3 months ago

[12√3 - 64(√3)³]/8

ANSWER

In triangle ABC D and E are mid points of sides BC and AC respectively. If given vertices are A(4,-2) and B(2,-2) and C(-6,-7) then verify the result DE=1/2 AB

Posted by Nishat Mazumder 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

In the figure AC||BD IS AE/CE=DE\BE? justify your answer

Posted by Shruti Tiwari 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

CosQ/secQ

Posted by Yashasvi Dixit 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Mayank Saarthak 1 year, 3 months ago

Cos²Q

ANSWER

If one zero is the reciprocal of other find the value of k in 3kx² - 7x + 11

Posted by Shristy Dewangan 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhargava Bharath 1 year, 3 months ago

The product of the zeros of a quadratic equation is equal to the constant term divided by the coefficient of the squared term. So, for the quadratic equation 3kx² - 7x + 11, the product of the zeros would be: x * (1/x) = 1 Now, we can use the sum of the zeros of a quadratic equation, which is equal to the negative coefficient of the linear term divided by the coefficient of the squared term. So, for our equation: x + (1/x) = -(-7) / 3k x + (1/x) = 7 / 3k Now, we have two equations: x * (1/x) = 1 x + (1/x) = 7 / 3k Let's simplify the first equation: x * (1/x) = 1 1 = 1 Now, for the second equation, let's solve for x + (1/x): x + (1/x) = 7 / 3k Since we know that x * (1/x) = 1, we can multiply both sides of the second equation by x: x * (x + (1/x)) = x * (7 / 3k) This simplifies to: x² + 1 = 7x / 3k Now, let's find the common denominator on the right side: x² + 1 = (7x * x) / (3k * x) x² + 1 = (7x²) / (3kx) Now, let's bring all terms to one side of the equation: x² + 1 - (7x²) / (3kx) = 0 To solve this quadratic equation for x, we need to find the common denominator: (3kx * x² + 3kx - 7x²) / (3kx) = 0 Now, we need to find the LCD (Least Common Denominator) of the terms in the numerator: LCD = 3kx Now, let's multiply both sides of the equation by the LCD to get rid of the fraction: 3kx * (3kx * x² + 3kx - 7x²) / (3kx) = 0 * (3kx) This simplifies to: 3kx * (3kx * x² + 3kx - 7x²) = 0 Expanding the expression: 9k²x³ + 3k²x² - 21kx³ = 0 Combine the x³ terms: (9k² - 21k) * x³ + 3k²x² = 0 For this equation to be true for all x, the coefficients of x³ and x² must be zero: 9k² - 21k = 0 (Coefficient of x³) 3k² = 0 (Coefficient of x²) Solving the second equation: 3k² = 0 k² = 0 k = 0 Now, for the first equation: 9k² - 21k = 0 9(0)² - 21(0) = 0 0 - 0 = 0 Since both equations are true when k = 0, the value of k that satisfies the conditions is k = 0.

ANSWER

A teacher had written on the blackboard the following algebraic expressions: 1. 2x + 15 2. x^2 + 6x 3. x^2 + 8x - 15 4. x^3 - 12x + 7 The teacher called two students, Sita and Kamal. I. The teacher told Sita to add expressions (1) and (2). II. Now the teacher said Kamal to subtract expression (2) from (3). Now answer the following questions: i. Find the zeros of the polynomial formed by Kamal. ii. If a and b are zeros of the polynomial formed by Sita, then find the value of ab.

Posted by Traptijain Jain 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is mean by identity

Posted by Shreyan Anarase 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

1 ÷ 2 alpha + beta and 1 ÷ 2alpha + beta

Posted by Shwetha P 1 year, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Harsh Vardhan 1 year, 3 months ago

1

Adwaith K 1 year, 3 months ago

1

ANSWER

Card total table

Posted by Shivendra Pal 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

5^(x+1)+5^(2-x)=5^3+1 by factorisation

Posted by Ashutosh Das 1 year, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The line segment joining A(-2,9) and B(6,3) is a diameter of a circle with centre C. Fin the coordinates of C.

Posted by Ragini Shaw 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Haret Gujjar 1 year, 3 months ago

C(2,6)

ANSWER

In DE || BC then the value of EC is

Posted by Jay Sutar 1 year, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Haret Gujjar 1 year, 3 months ago

Ec equal BD

ANSWER

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