CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

S-t=3 …(i) S/3+t/2=6 …(ii) First solve equation (i) S-t=3 =S=3+t …(iii) Now substituting the value of S in equation (ii) 3+t/3+t/2=6 =6+2t+3t=36 =6+5t=36 =5t=36-6 =5t=30 =t=30/5 =t=6 Now, Equation (iii) S=3+t S=3+6 S=9 Answer:- The value of S=9 and the value of t=6

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L=28 Sn=144 N=9 WHAT IS THE VALUE OF "A"

Posted by Mugilesh Mugilesh 2 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Khwahis Parveen 2 years, 3 months ago

l=28 Sn =144 n=9 a=? By using the formula, Sn=n/2(a+l) =144=9/2(a+28) =144=9a+252/2 =144×2=9a+252 =288=9a+252 =288-252=9a =36=9a =a=36/9 =a=4

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Harish Nandha 2 years, 3 months ago

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Find the quadratic polynomial, the sum of whose zeros is 0 and their product is –1. Hence, fi nd the zeros of the polynomial.

Posted by Uzair Ahmad Khan 2 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Ankit Kumar 2 years, 3 months ago

The sum of zeros= 0 Product of zeros= -1 Required quadratic polynomial= x²-(sum of zeros)x+product of zeros =X²-(0)x-1 =X²-1

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Krish Gupta 2 years, 3 months ago

x²-0x+-1

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Factorise x^2-55x+750

Posted by Niruganti Saileela 2 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aditya Mathur 2 years, 3 months ago

X^2 -55X +750 X^2 -30X -25X +750 X(X - 30)-25(X-30) (X-30) (X-25) X=30 X=25

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Venu Gopal has twice as many sisters as he has as brothers

Posted by Jay Patil 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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A man inversted an amount at 12% per annum simple interest and another amount at 10% panel simply interest he received and annual interest of 2600 but if he had in the change the amount invest he would have received 140 less what amount does different rates

Posted by Janvika Komirishetty 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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Difference between two numbers is 26 and one number is three times the other find the number

Posted by Janvika Komirishetty 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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Find the coordinate of the point which divides the line segment joining the points (4,- 3) and (8,5) in the ratio 3:1 internally.

Posted by Manusridurga Gali 2 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Amrit Kumar 2 years, 3 months ago

And. Y=my2+ny1/m+n=3*5+1*-3=15+(-3)=12/m+n 12/3+1=12/4=3

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Amrit Kumar 2 years, 3 months ago

Or X=mx2+nx1/m+n=3*8+1*4=24+4=28/m+n=28/3+1=28/4=7

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Amrit Kumar 2 years, 3 months ago

Let the point p 3:1 by the mid point formula m(x1+X2)/2and (y1+y2)/2 8+4/2=6and -3+5=2 and now 6/2=3

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If a line intersect sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC ,prove that AD/AB=AE/AC

Posted by Sahajpal Singh 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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2x+3y=42and 2x+35y=32

Posted by Ayushman Shrivastava 2 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aryan Pawar 2 years, 3 months ago

2x+3y=42 -2x-35y=-32 0. -32y=10 y=10/32=5/16. -------1 Substituting y in 2x+3y=42 2x+3(5/16)=42 2x+15/16=42 (32x+15)/16=42 32x+15=672 32x=657 x=657/32

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The sum of two numbers is 34 if 3 is subtracted from one number and 2 is added to another number the product of the two numbers becomes 260 find the numbers

Posted by Khushboo Bisht 2 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Vandana Kumari 2 years, 3 months ago

Let 1st number be x And 2nd number be (34-x) A.T.Q., (x-3)(34-x+2) = 260 (x-3)(36-x) = 260 (36x-x²-108+3x) = 260 (-x²+39x-108) = 260 -x²+39x-368 = 0 x²-39x+368 = 0 x²-16x-23x+368 = 0 x(x-16)-23(x-16) = 0 (x-16)(x-23) = 0 (x-16) = 0 or (x-23) = 0 x = 16 or x = 23 Hence, the required numbers are 16 and 18.

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Account Deleted 2 years, 3 months ago

If my answer is wrong you can do repeat with this method

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Account Deleted 2 years, 3 months ago

Let no x and 34- x (X-3) (34-x+2) =260 (X-3)(36-x)=260 36x-x(square) -108+3x=260 39x-x(square)-108-260=0 {Sign changes all digit} X(square)-39x+368=0 x(square)-23x-16x+368=0 X(x-23)-16(x-23)=0 (X--23)(x-16). {factors/roots/solution} X=23,x=16 Numbers required 23 and 16

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16x² - 9 =0 factories

Posted by Anjali Singh 2 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Himanshu Dhakad 2 years, 3 months ago

Simple hai Kuch nhi krna bs simple identity use hogi (a²-b²)=(a+b)(a-b) ye wali... Saaf saaf dikh Raha hai ki 16 Likha hai mtlb 4 Ka square kyuki 4x4=16 HOTA or 9 Likha hai mtlb 3 Ka square bs khatam ...... (4x)² - (3)² = 0 ab ye identity BN gyi jisme a ki value hai 4x or b ki value hai 3 ab open krdo identity ko toh bn Jayega (4x+3)(4x-3)=0 Ab.....(4x+3)=0 ho Jayega or sath mein (4x-3)=0 bhi ho Jayega ab dono brackets ko solve krenge or X ki value nikalenge ....pehle bracket s value ayegi X=-3/4 or dusre s X=3/4

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Chapter 2 and Ex 2.2

Posted by Manish Singh Dewda Rajputana Dewda Ji 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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m/nx²+n/m=1-2x

Posted by A A 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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Give me 10 mcq of polinomial

Posted by Chetna Jain 2 years, 3 months ago

CBSE > Class 10 > Mathematics

5 answers

Khwahis Parveen 2 years, 3 months ago

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Khwahis Parveen 2 years, 3 months ago

2) The zeros of the polynomial x²-2x-3 are a)-3,1 b)-3,-1 c)3,-1 d)3,1

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Khwahis Parveen 2 years, 3 months ago

1)Which of the following is a polynomial? a)x²-5x+4√x+3 b)√x+1/√x c)9x²-4x+√2 d)√2x²-3√3x+√6

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Account Deleted 2 years, 3 months ago

Jai jinendra

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Account Deleted 2 years, 3 months ago

Hi chetna

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Write whether the square of any positive integer can be formed 3m+2 where m is a rational number justify your answer

Posted by Managala Mohitkar 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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If the first term of an A.P. is 5, the nth term is 40 and the sum of first n terms is 180, find the value of n.

Posted by Mohd Israiel Anis 2 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Himanshu Dhakad 2 years, 3 months ago

an=a+(n-1)d 40=5+(n-1)d 35=(n-1)d.......1 Sn=n/2(2a+(n-1)d) 180=n/2(2*5+(n-1)d) 360=n(10+(n-1)d) Using 1 equation 360=n(10+35) 360=n(45) n=360/45 n=8 Answer

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Mohd Israiel Anis 2 years, 3 months ago

Answer

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Neeraj and Hrithik went to a nearby pizza shop for lunch. The shop had a unique method for the price allotment of pizza every day. The price of each pizza they prepare on a specific day is equal to 4 more than twice the total number of pizzas they produced on that day. The total cost of production on that day was 448 rupees. Answer the following questions: 1. The quadratic equation for given situation is: 2. Find the number of pizzas produced. Or Write the general form of quadratic equation. 3. Find the cost of each pizza.

Posted by Vaishnavi Mishra 2 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Himanshu Dhakad 2 years, 3 months ago

Let the number of pizzas produced on that day be X So price of each pizza(as per question) will be= (2x + 4) Rs Since it is given that total cost of production on that day is Rs.448 (Price of each pizza)*(number of pizzas produced) = 448 (2x + 4)*X = 448 2x² + 4x = 448 X² + 2x = 224 X² + 2x - 224 = 0 Now factorisation as.. (Multiply krne pr 224 or minus krne pe plus Ka 2 Toh 16-14=2 and 16*14= 224) X² + 16x - 14x - 224 = 0 X(X+16)-14(X+16)=0 (X+16)(x-14)=0 So X= 14 and X=-16 Since number of pizzas produced on that day cannot be nigative therefore number of pizzas produced are 14

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Why value 'n' in A.P. is always positive

Posted by S P Jaishwal 2 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Himanshu Dhakad 2 years, 3 months ago

Kyuki Kisi bhi cheez ki agr count krenge toh wo negative nhi ho skta kbi like if you are counting number of tables then it cannot be like minus 7 tables so n is always positive

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Rajiv Sharma 2 years, 3 months ago

What is resistivity

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30th term of Ap:10,7,4.....,is (a)97 (b) 77 (c) -77 (d) -87

Posted by Ankit Kumar Gurjar 2 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Himanshu Dhakad 2 years, 3 months ago

Simple hai 30th term ki value poochi hai or AP de Rakhi hai....given AP mein a=10 ho Gaya or d ki value minus 3 ....ab 30th term ko likh skte hai (a+29d) ab bs value put Karo "a" ki or d ki (10+29*(-3)) solve krenge or answer hoga minus 77 Hope it will help you;)

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S P Jaishwal 2 years, 3 months ago

( c) -77

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2xsquare+1x

Posted by Fathimath Naja Naja 2 years, 3 months ago

CBSE > Class 10 > Mathematics

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The sum of the first 100 even natural numbers is :

Posted by Pratibha Pratibha 2 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Himanshu Dhakad 2 years, 3 months ago

Dekho first 100 even natural numbers Ka sum krna hai okk toh ek AP likh k dekhte hai .....natural numbers kya hote hai like general counting 1 2 3 4...ESE numbers but even likhne hai toh AP Kuch ESI banegi.>>>2,4,6,8,9,10...... Hope you know that even number wo hote hai Jo 2 se divide ho jate hai completely so ab Hume a AP mil gayi......nikalna hai 100 natural even numbers Ka sum Sum of n terms Ka formula HOTA hai Sn=n/2(2a+(n-1)d) Yaha n ki value 100 ho jayegi kyuki 100 even numbers Ka sum krna hai or AP Jo humne banai hai usse clearly "a" ki value 2 hai or d ki value bhi 2 bs values put krke solve kr denge ....S100=100/2(2*2+(100-1)2)..............S100=50(4+99*2)......S100=50(202)......S100=10,100 answer Hope it will help you;)

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S P Jaishwal 2 years, 3 months ago

11100

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