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Posted by Shashank Mahato 5 years, 8 months ago
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꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 5 years, 8 months ago
Posted by Shivani Yadav 5 years, 8 months ago
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Posted by Sailam Sharma 5 years, 8 months ago
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Posted by Anil Sagar 5 years, 8 months ago
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Posted by Priyanka Rani 5 years, 8 months ago
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Gaurav Seth 5 years, 8 months ago
Radius of wheel= 80/2 = 40cm
∴ The distance travelled in one revolution is = 2πr = 2 x 22/7 x 40 = 1760/7 cm.
speed of car= 66km/hr= 66 x 1,00,000/60 cm/min = 1,10,000 cm/min.
distance covered by car in 1 min = 1,10,000cm
distance covered by car in 10min = 110,000 x 10 = 11,00,000cm.
number of complete revolution =
distance covered in 10min / distance covered in one revolution.
= 11,00,000/ 1760/7
= 11,00,000/1 x 7/1760 = 4375 revolutions.
Hence, in 10min each wheel of car makes 4375 revolutions.
Posted by Chitranjali Sakuja 5 years, 8 months ago
- 2 answers
Gaurav Seth 5 years, 8 months ago
Perimeter of that triangle = 60cm
the measure of hypotaneous = 25cm
then the rest sides must measure = 60-25
= 35
let one side be x
then, thw measure of the third side must be 35 - x
using pythagoras theorem
(25)^2 =(x)^2 + (35-x)^2
625 = x^2 + x^2 - 70x + 1225
x^2 + x^2 - 70x + 1225 = 625
x^2 + x^2 - 70x + 1225 -625 = 0
2 x^2 - 70x + 600 = 0
2x^2 - 40x - 30 x + 600= 0
2x (x-20) -30 ( x - 20) = 0
(x-20)(2x-30)=0
x -20 = 0
x = 20
2x -30 =0
2x =30
x = 15
so,
one of the side measure either 20 cm 15 cm
if one side measure 20cm then the other must measure 35 -20 = 15cm
and if it measured 15 cm then the other side measure 35-15 = 20 cm
so,
we will get 20cm and 15 cm as our remaining sides.
one of then will be height and the other misy be the base,
now apply the formula of area of triangle i.e
(1/2) (height)(base)
= (1/2 )(20)(15)
= 150 cm^2
so, the area of that triangle will be 150 cm^2.
Posted by ꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 5 years, 8 months ago
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꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 5 years, 8 months ago
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Posted by ??Cute?? Niharoo?? 5 years, 8 months ago
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꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 5 years, 8 months ago
Posted by Nagarajan Manikandan 5 years, 8 months ago
- 1 answers
Gaurav Seth 5 years, 8 months ago
To Find, The smallest number which is divisible by 306 and 657, Find the L.C.M. of 306 and 657.
So,
306 = 2 × 3 × 3 × 17
657 = 3 × 3 × 73
L.C.M. of 306 and 657 = 2 × 3 × 3 × 17 × 73 = 22,338
Hence 22,338 is the smallest number which is divisible by 306 and 657.
Posted by Gokulpriyan Karthikeyan 5 years, 8 months ago
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Posted by Namdeo Mayank 5 years, 8 months ago
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꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 5 years, 8 months ago
Posted by Ram Yadav 5 years, 8 months ago
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Posted by Saloni Singh 5 years, 8 months ago
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Posted by Yuvaraj K E 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
Let the numerator = x
Let the denominator = y
Now,
fraction becomes = x/y
According to the first condition,
(x − 1)/y = 1/3
⇒y = 3x − 3 ......(1)
According to the second condition,
x/(y + 8) = 1/4
⇒y + 8 = 4x
⇒y = 4x − 8 .........(2)
from (1) and (2),
3x − 3 = 4x − 8
⇒3x − 4x = −8 + 3
−x = −5
⇒x = 5
from (1), we get
y = 15 − 3 = 12
So, the required fraction = 5/12
Posted by Munireddy Ekambaram 5 years, 8 months ago
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Posted by ]••´º´•» Ｄί?Ş?? «•´º´••[• 5 years, 8 months ago
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Posted by Shafeeq Olive 5 years, 8 months ago
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