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꧁༺★King K. Tyagi Ji}★༺꧂ ??? 6 years ago
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Shreyash Saraswat 6 years ago
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꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 6 years ago
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Posted by ꧁༒☬Sowndu☬༒꧂???꧁༒????༒꧂ ??? 6 years ago
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Posted by ❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
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Shreyash Saraswat 6 years ago
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❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
algebra 20 marks
co-ordinate geometry 6marks
geometry 15 marks
trigonometry 12 marks
mensuration 10 marks
statistics and probability 11 marks
total 80 marks
Posted by ❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
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Yogita Ingle 6 years ago
Given, x=a and y=b.
Given equations, x - y = 2( assume it as equation 1)
x + y = 24( assume it as equation 2)
Equation 1+2,
x - y = 2
x + y= 24
- - - - - - -
2x = 6( y gets cancelled as there is a negative y and a positive y implies y-y=0)
x = 26/2
x = 13
But x=a implies a=13
substitute a in equation 1 (it can be substituted even in equation 2)
x-y=2
13 - y = 2
y=13-2
y=11
But y = b implies b = 11
Therefore, a=13 and b=11
Posted by ❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
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❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
(1) x²- x + 12
(2)x²+x+12
(3)2x²+2x-24
(4)none of the above
Posted by ❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
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❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
Shreya S❤ 6 years ago
Posted by ❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
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Yogita Ingle 6 years ago
area of ∆ABC is 4
x1 = x
x2 = 1
x3 = 0
y1 = 0
y2 = 1
y3 = 2
• area of ∆ABC :-
{tex}= \frac{1}{2} ( x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)){/tex}
{tex}4 = \frac{1}{2} (x(1 - 2) + 1(2 - 0) + 0(0 - 1)){/tex}
8 = x - 2x + 2
8 - 2 = - x
6 = - x
x = - 6
So, the value of x is ( - 6 )
Posted by ❤ ?§✝️⛎Đý ®️@Ňķëŕ ?❤ 6 years ago
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Posted by Hitesh Borana 6 years ago
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Hitesh Borana 6 years ago
Posted by Chitranjali Sakuja 6 years ago
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