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Ask QuestionPosted by Saroj Malwal 5 years, 6 months ago
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Posted by Subhra Bera 5 years, 6 months ago
- 1 answers
Gaurav Seth 5 years, 6 months ago
Given points are (1,7),(4,2),(-1,-1),(-4,4)
Let the points are A,B,C,D.
Distance formula = √(x₂-x₁)²+(y₂-y₁)²
AB = √(4-1)²+(2-7)²
= √9+25
= √34
BC = √(-1-4)²+(-1-2)²
= √25+9
= √34
CD = √(-4-(-1))²+(4-(-1))²
= √9+25
= √34
DA = √(1-(-4))²+(7-4)²
= √25+9
= √34
- We know that the all sides of the square are equal. Here by the distance formula, we got the for sides equal So,from this we can say that these points are the vertices of a square.
Posted by Rajeev Thakur 5 years, 6 months ago
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Posted by Ankit Fulwari 5 years, 5 months ago
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Mansi Mishra 5 years, 6 months ago
Posted by Nishu Rawat 5 years, 6 months ago
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Posted by Krishin M Veer 5 years, 6 months ago
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Aalok Patil 5 years, 6 months ago
Posted by Chahat Singh 5 years, 6 months ago
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Chahat Singh 5 years, 6 months ago
Posted by Ishika Awasthi 5 years, 6 months ago
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Posted by Sunny Yadav 5 years, 6 months ago
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Posted by Jaspreet Kaur 5 years, 6 months ago
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Posted by Aditya Sharma 5 years, 6 months ago
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Posted by Raja Ram 5 years, 6 months ago
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Yogita Ingle 5 years, 6 months ago
Let take that 3 + 2√5 is a rational number.
So we can write this number as
3 + 2√5 = a/b
Here a and b are two co prime number and b is not equal to 0
Subtract 3 both sides we get
2√5 = a/b – 3
2√5 = (a-3b)/b
Now divide by 2 we get
√5 = (a-3b)/2b
Here a and b are integer so (a-3b)/2b is a rational number so √5 should be a rational number But √5 is a irrational number so it contradict the fact
Hence result is 3 + 2√5 is a irrational number
Posted by Áñkít Râwãt 5 years, 6 months ago
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Posted by Mahek Star 5 years, 6 months ago
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Lee Mikyong 5 years, 6 months ago
Gaurav Seth 5 years, 6 months ago
38220>196 we always divide greater number with smaller one.
Divide 38220 by 196 then we get quotient 195 and no remainder so we can write it as
38220 = 196 * 195 + 0
As there is no remainder so deviser 196 is our HCF
Posted by Mohit K 5 years, 6 months ago
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Anonymous . 5 years, 6 months ago
Posted by Aman Kumar Mahawar 5 years, 6 months ago
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Posted by Tanya Kri 5 years, 6 months ago
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Posted by Mishmee Paul 5 years, 6 months ago
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Anonymous . 5 years, 6 months ago
Posted by Vishawanath Gadaraddi 5 years, 6 months ago
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Yogita Ingle 5 years, 6 months ago
Given series is 3, 8, 13, ...... 253
here, first term , a = 3
common difference , d = 5
Let us find total number of terms at first.
use {tex}\bf{T_n=a+(n-1)d}{/tex}
=> 253 = 3 + (n - 1)5
=> 250 = 5(n - 1)
=> n - 1 = 50
=> n = 51
so, there are 51 terms in given series.
now we know, mth term from last =last term - mth term + 1
so, 20th term from last = 51 - 20 + 1 = 32
hence, 20th from last = 32th term from first
use , {tex}\bf{T_{32}=a+(32-1)d}{/tex}
= 3 + 31 × 5 = 3 + 155 = 158
hence , 20th term from last = 158
Posted by Bindiya Rout 5 years, 6 months ago
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Posted by R Shidhaye 5 years, 6 months ago
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Abhishek Gupta 5 years, 6 months ago
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Gaurav Seth 5 years, 6 months ago
To find zero of the polynomial, we simply equate the equation to 0.
=> 5x + 4 = 0
=> 5x = - 4
=> x = - 4/5.
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