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Solve graphically 4x-5y-20=0 and 3x+5y-15=0

Posted by Sanskriti Agarwal 5 years, 5 months ago

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Prove that sin thita -cos thita +1/sin thita + cos thita - 1 =1/sec thita + tan thita , using identity sec² thita =1+ tan²thita

Posted by Arya Jadav 5 years, 5 months ago

CBSE > Class 10 > Mathematics

4 answers

Arya Jadav 5 years, 5 months ago

Ok Thanks

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Pankaj Malik 5 years, 5 months ago

LHS = (sinθ - cosθ + 1)/(sinθ + cosθ - 1) dividing by cosθ both Numerator and denominator = (sinθ/cosθ - cosθ/cosθ + 1/cosθ)/(sinθ/cosθ + cosθ/cosθ - 1/cosθ) = (tanθ + secθ - 1)/(tanθ - secθ + 1) Multiply (tanθ - secθ) with both Numerator and denominator = (tanθ + secθ - 1)(tanθ - secθ)/(tanθ - secθ + 1)(tanθ - secθ) = {(tan²θ - sec²θ) - (tanθ - secθ)}/(tanθ - secθ + 1)(tanθ - secθ) = (-1 - tanθ + secθ)/(tanθ - secθ + 1)(tanθ - secθ) [ ∵ sec²x - tan²x = 1 ] = -1/(tanθ + secθ) = 1/(secθ + tanθ) = RHS

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Pankaj Malik 5 years, 5 months ago

Its mistake sorry

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Pankaj Malik 5 years, 5 months ago

In the question, We have been provided a trigonometric function, Therefore, on simplifying the given equation by putting in the values of the respective terms in the LHS, we get, On dividing by 'cosθ' in both Numerator and Denominator, we get, Now, we know that, sec²θ - tan²θ = 1 On putting in the given equation, we get, i.e. Now, we can see here that, LHS of the equation is equal to the RHS. Therefore, we can see that the equation has been proved. Hence, Proved.

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Hiw many silver coins,1.75cm in diameter and of thickness 2..,must be melted to form a cuboid of dimensions 5.5cm×10cm×3.5cm

Posted by Lekhya Thota 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Pankaj Malik 5 years, 5 months ago

Assume silver coin to be a cylinder Dimensions of silver coin Height= 2 mm = 0.2 cm Diameter= 1.75 cm Radius= Diameter/2 = 1.75/2 = 0.875 cm Dimensions of cuboid Length= 5.5 cm Breadth= 10 cm Height = 3.5 cm Volume of one silver coin = pi *(r^2)*h = 3.141(0.875)(0.875)(0.2) = 0.481 cm^3 Volume of cuboid = l * b * h = 5.5(10)(3.5) = 192.5 cm^3 No. of coins required to form cuboid = Volume of cuboid/Volume of one coin = 192.5/0.481 = 400.207 = 401 (rounded to next nearest number) The answer is 401

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In traingle pqr right angle atq PQ=3 and PR=6 determine angle QPR and angle PRQ

Posted by Babli Tiwari 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Pankaj Malik 5 years, 5 months ago

∆PQR is a right angle triangle by Pythagoras theorem (PR)^2=(PQ)^2+(QR)^2 6^2=3^2+((QR)^2 36=9+(QR)^2 36-9=(QR)^2 (QR)^2=27 QR=✓9×3 QR=3✓2 AngleQPR =60° because side opposite to P is ✓3/2 times the hypo(PR) Angle PRQ=30° because side opposite to R is 1/2 of the hypo(PR)

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A=4,n=7,d=4 the an is

Posted by Chehak Aggarwal 5 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Gajavelli Swathi 5 years, 5 months ago

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D.S.Vignesh Saravanan 5 years, 5 months ago

an = a + ( n - 1 ) d an = 4 + 6 ( 4 ) an = 4 + 24 an = 28

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Yogita Ingle 5 years, 5 months ago

Formula of nth term =

Where n is the no. of term

d is the common difference

a is the first term

Substitute the given values :

Hence the value of a is 28.

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2x+5x-6x

Posted by Aradhya Gupta 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Suryansh Singh 5 years, 5 months ago

X only

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Mithali Pattanaik?? 5 years, 5 months ago

Pura question kya hai??

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30 rs is 1000g . what is the gram if rs 20?

Posted by Hardik P 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Study Lover ?‍? ?‍? 5 years, 5 months ago

In rs 30,gram=1000. In rs 1,gram=1000/30. In rs 20,gram=33.33×20=666.66.

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Mithali Pattanaik?? 5 years, 5 months ago

500g

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The pair of linear equation2x-5y=3 and 2y-5x-8=0have

Posted by Sukhwinder Kaur 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Suryansh Singh 5 years, 5 months ago

Unique solution

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Up to how much table should I know in 10

Posted by Rekha . 5 years, 5 months ago

CBSE > Class 10 > Mathematics

5 answers

Gajavelli Swathi 5 years, 5 months ago

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Suryansh Singh 5 years, 5 months ago

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Helper . 5 years, 5 months ago

Ek bhi nhi

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Hippie Maari 5 years, 5 months ago

Neenu ninnu premistunnanu

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Hippie Maari 5 years, 5 months ago

Me me me me ekapai only u and me

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cos 45 / sec 30 cosec 30

Posted by Prrriyyaaaaaa Kuuuumaaariiii 5 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Helper . 5 years, 5 months ago

Are cos 45 ki value hoti h 1 and sec30 ki value hoti h 1/underroot 3 multiply by cossec 30 ki value

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Hippie Maari 5 years, 5 months ago

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Lucifer ? Morningstar? 5 years, 5 months ago

1/√2×2/√3×2= 2√6/3

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A circle has a chord of length 14 √3cm and the chord subtends an angle of 30° in the circumference. Find the length of circumference of the circle.

Posted by Dakshin Ramesh 5 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

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How I got notes of trigonometry on this application

Posted by Ankit Singh Thakur 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Mahi..... ♾ 5 years, 5 months ago

Open the app click on maths subject then the content are shown click on the chapter which u want to study then on the top the ncert revision note are shown or ncert solution are shown click on ncert revision notes then the notes are appear.ok then u can study ???

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Ankit Singh Thakur 5 years, 5 months ago

Please tell me someone

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All trigonometry ratio and identity?

Posted by Ankit Singh Thakur 5 years, 5 months ago

CBSE > Class 10 > Mathematics

5 answers

Ankit Singh Thakur 5 years, 5 months ago

How

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Lucifer ? Morningstar? 5 years, 5 months ago

Then got it in this app

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Ankit Singh Thakur 5 years, 5 months ago

I want trigonometry notes

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Lucifer ? Morningstar? 5 years, 5 months ago

What are u trying to ask .

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Ankit Singh Thakur 5 years, 5 months ago

Please answer this question anyone please

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How many pairs of positive integer x,y exist such that H.C.F(x,y)+L.C.M(x,y)

Posted by Sunil Yadav 5 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

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In ∆ abc, right angled at b, AB=5cm and angle ACB=30° then the lengths of the side BC is............

Posted by Gautam Soni 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Study Lover ?‍? ?‍? 5 years, 5 months ago

In ∆ABC, Tan 30=AB/BC =>1/√3=5/BC =>BC=5√3cm. I hope this helps you ??.

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Lucifer ? Morningstar? 5 years, 5 months ago

BC=5√3 cm

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Maths is so hard can help me

Posted by Gauri Kumari 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Lucifer ? Morningstar? 5 years, 5 months ago

Ask ur doubt in this app and there are many students who can help u

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22\7×24.5

Posted by Decru'Z Mridu 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

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7. Raju started work in 2003 at an annual salary of Rs 5000 and received an increment of Rs 200 each year. In which year did his income reach Rs 7000?

Posted by Ak18 Ak18 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Study Lover ?‍? ?‍? 5 years, 5 months ago

Initial income=5000. Final income=7000(required). Let the no of years be 'n'. 5000+(n-1)200=7000 =>(n-1)200=2000 =>n-1=10 =>n=11 Raju income reach 7000 in 2014.

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Hippie Maari 5 years, 5 months ago

2011

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If the third and the ninth terms of an AP are 4 and –8 respectively, which term of this AP is zero?

Posted by Ak18 Ak18 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

given 3rd term = 4
i.e, a+2d=4 ---- 1
and 9th term = -8
i.e., a+8d=-8 ------------- 2
by by subtacting 1 and 2 we get,
      a+2d = 4
      a+8d = -8
     -    -      +
     ----------------
        -6d = 12
     ---------------
so, d = -12/6
      d = -2
substitute it in (1) we get,
a+2(-2) = 4
a = 4+4 =8
a=8

here we get a=8

2nd term = a+d = 8+(-2) = 8-2 = 6
3d term = a+2d = 8+2(-2) = 8-4 = 4
4th term = a+3d = 8+2(-3) = 8-6 = 2
5th term = a+4d = 8+2(-4) = 8-8 =0
6th term = a+5d =8+5(-2) = 8-10 = -2 .......

so the series we got is 8,6,4,2,0,-2.....
here we get zero at 5th place
so, 5th number in the series is 0.

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ANSWER

Which term of the AP: 3, 8, 13, 18 … is 78?

Posted by Ak18 Ak18 5 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Dinesh Kumar Yadav 5 years, 5 months ago

A=3 d=5 Tn=78 Formula :- a + (n-1)d Putting value, 3 + (n-1)*5 = 78 (n-1)*5 = 78-3 (n-1)*5 = 75 (n-1) = 75/5 n-1) = 15 n = 15+1 = n = 16

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Hippie Maari 5 years, 5 months ago

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Yogita Ingle 5 years, 5 months ago

The given sequence is 3, 8, 13, 18, ....78.
'a' = 3, 'd' = 5, last term = 78, 'n' = ?

t_n=a+(n−1)d

⟹78=3+(n−1)5

⟹78=3+5n−5

⟹78=5n−2

⟹5n=80

n=16.

The 16th term is 78.

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P of x is equals to x square - 6 x + 9

Posted by Rajitha Velupula 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

p(x) = x² -6x + 9

p(x)=x² -3x -3x+ 9

p(x) = x(x -3) - 3(x-3)

= (x-3)(x-3)

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Find the number of terms in the following AP: 7, 13, 19…., 205

Posted by Ak18 Ak18 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

7,13,19........,205

Consider,

t_n = 205

t_n = a + (n - 1) d = 205 where a = 7 and d = 13 - 7 = 6

7 + (n - 1) × 6 = 205

6(n - 1) = 198

n - 1 = 33

n = 34

Hence, the number of terms in the given sequence are 34.

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. Find the missing variable from a, d, n and an, where a is the first term, d is the (2) common difference and an is the nth term of AP. d = –3, n = 18, an = - 5

Posted by Ak18 Ak18 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

d = –3, n = 18, a_n=-5

We need to find a here.

Using formula a_n= a+(n-1)d

Putting values of d,a_n and n, we get ,

–5 = a + (18 – 1) (–3)

⇒ −5 = a + (17) (−3)

⇒ −5 = a – 51
⇒ a = 46

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in of the following ,form an AP ,find the common difference d and write three more terms.-10,-6,-2,2....

Posted by Ak18 Ak18 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

-10, - 6, - 2, 2 …
Here,
a₂ - a₁= (-6) - (-10) = 4
a₃ - a₂ = (-2) - (-6) = 4
a₄ - a₃ = (2) - (-2) = 4
⇒ a_n+1 - a_n is same every time.
Therefore, d = 4 and the given numbers are in A.P.
Three more terms are
a₅= 2 + 4 = 6
a₆= 6 + 4 = 10
a₇ = 10 + 4 = 14

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Is syallbus will reduce or not

Posted by Priyanshu Maurya 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Amudala Suresh 5 years, 5 months ago

(a+b)(a+b)

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If pth term of an AP is q and qth term is p than prove that its (p+q)th term is zero.

Posted by Anushka Dixit 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 5 months ago

Let a is the first term of AP and d is the common difference

p^th term = a + (p-1) d = q .................(1)

q^th term = a + (q-1) d = p .................(2)

By subtracting eqn(2) from eqn(1), we get d = -1

if we subsititue d = -1 in eqn.(1), we get a = p+q-1

n^th term = a+(n-1)d = (p+q-1) + (n-1)(-1) = p+q-n

(p+q)^th term = a+(p+q-1)d = (p+q-1)+(p+q-1)(-1) = 0

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The area of the rectangle is 528m2.The length of the plot is one metre more than twice its breadth.find the length and breadth of the plot

Posted by Harshitha Hr10A 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Lucifer ? Morningstar? 5 years, 5 months ago

Given, l×b=528 => (2b+1)b=528 => 2b²+b-528 | | 2b²-32b+33b-528 => 2b(b-16)+33(b-16) => (2b+33)(b-16) => b=16 and l=33.

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Lucifer ? Morningstar? 5 years, 5 months ago

Let the length and breadth be l and b respectively. A/q l=2b+1

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If cosa=3/5, find the value of sina-1/tana/2tana

Posted by Shivangi Shukla 5 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Ayush Raj 5 years, 5 months ago

Sin a - 1 = -1/5

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Ayush Raj 5 years, 5 months ago

2tan a = 8/3

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Ayush Raj 5 years, 5 months ago

Tan a = 4/3

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Prove that 1/2 is irrational

Posted by Vivek Yadav 5 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Vivek Yadav 5 years, 5 months ago

Thanks

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Ayush Raj 5 years, 5 months ago

1/2 is not an irrational number

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Nikku Shekhawat 5 years, 5 months ago

To prove 1/√2 is irrational Let us assume that √2 is irrational 1/√2 = p/q (where p and q are co prime) q/p = √2 q = √2p squaring both sides q² = 2p² .....................(1) By theorem q is divisible by 2 ∴ q = 2c ( where c is an integer) putting the value of q in equitation 1 2p² = q² = 2c² =4c² p² =4c² /2 = 2c² p²/2 = c² by theorem p is also divisible by 2 But p and q are coprime This is a contradiction which has arisen due to our wrong assumption ∴1/√2 is irrational

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Express 0.127͞ as fraction

Posted by Rishi Chawla 5 years, 5 months ago

CBSE > Class 10 > Mathematics