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  • 2 answers

Study Lover ?‍? ?‍? 5 years, 5 months ago

Solving NCERT maths and exemplar with honesty is enough. Other reference books are- 1.RS Agarwal 2.All in one 3.S chand mathematics

Ishika ? 5 years, 5 months ago

You should try RS Aggarwal or All in one...☺️☺️
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

Slope between (p+1,p), (p, p+1) = slope between (p, p+1), (p-1,p-2) (p+1-p)/[p-(p+1)] = [(p-2)-(p+1)]/(p-1-p) 1/-1 = -3/-1 -1 = 3
  • 5 answers

Sana(Silent Love).. ?? 5 years, 5 months ago

I think u should go for RS aggarwal as it is very simple nd easy to understand and ya best for revision.......

Aditya Chaturvedi 5 years, 5 months ago

I think you should refer RS agrwal it is simple and best for revision

Ishika ? 5 years, 5 months ago

Sorry i mean RD sharma is very hard.

Ishika ? 5 years, 5 months ago

Examplar becoz is very hard?☺️☺️

Om Omar 5 years, 5 months ago

R. D. Sharma
  • 1 answers

Bharath Talliboina 5 years, 5 months ago

Find the centre of circle passing through the points 6, - 63, - 7 and 3, 3
  • 2 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

In simple way, x/2=3² => x=9×2 => x=18

Testing Testing1 5 years, 5 months ago

Start with:√(x/2) = 3 Square both sides:x/2 = 32 Calculate 32 = 9:x/2 = 9 Multiply both sides by 2:x = 18
  • 2 answers

Unknown One 5 years, 5 months ago

a=bq +r, where r=,or less than b

Aditya Chaturvedi 5 years, 5 months ago

Euclids division algorithm states that for every two positive integers a and b there unique exist q and r such that a=bq+r,where 0<or =r<b In words it means Dividend =divisor ×quotient + remainder
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

Available in this app?plz?thoda ksht kre ?
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

Available in this app ?plz ? thoda ksht kre?
  • 1 answers

Lucifer ? Morningstar? 5 years, 5 months ago

D=(-12)²-4×4(-9) => 144+144= 288. So it's nature is real and equal
  • 5 answers

? Pranali.A.P ? 5 years, 5 months ago

????

Drift? Boi? 5 years, 5 months ago

????

? Pranali.A.P ? 5 years, 5 months ago

Jo hukum mere aaka ?

Drift? Boi? 5 years, 5 months ago

Kyu pata karo.

? Pranali.A.P ? 5 years, 5 months ago

I don't know ??
  • 2 answers

? Pranali.A.P ? 5 years, 5 months ago

When a die is thrown 2 times, the possible no. of outcomes = 6×6 = 36 . Out of these 36 cases only two cases are favorable for the happening of the event I.e. getting the sum 11 and these two cases are (5, 6) & (6, 5) . Therefore required probability = 2/36 = 1/18 .

Parth Alase 5 years, 5 months ago

12
  • 2 answers

Yogita Ingle 5 years, 5 months ago

4/x + 3y=14 and 3/x - 4y=23

Let 1/x = m,

4m + 3y = 14...(1)

and 3m - 4y = 23 ... (2)

Multiply (1) by 4 and (2) by 3, we get

16m + 12y = 56   ... (3) and 9m - 12y = 69 .... (4)

Adding (3) and (4), we get

25m = 125

→ m = 5

From (1),

4(5) + 3y = 14

→ 3y = 14 - 20

→ y = -2 and m = 1/x = 5 → x = 1/5

? Pranali.A.P ? 5 years, 5 months ago

x=1/5, y=-1
  • 1 answers

Mohit Saini 5 years, 5 months ago

10×3 (x=3) 10×3-1=29 10×0(x=0) 10×0-1=-1
  • 2 answers

Virsan Edage 5 years, 5 months ago

Y=6/5 and X=19/5

Lucifer ? Morningstar? 5 years, 5 months ago

Multiply EQ (१) by 2 and subtract eq(२) , 2x+2y-2x+3y=१0-4 | | 5y=6 => y=6/5 then x=19/5
  • 3 answers

Gaurav Seth 5 years, 5 months ago

Let us assume that √3 is a rational number.

then, as we know a rational number should be in the form of p/q

where p and q are co- prime number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

Now, by squaring both the side

we get,

(√3q)² = p²

3q² = p² ........ ( i )


So,

if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )


=> Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,

if 3 is factor of q²

then, 3 is also factor of q


Since

3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

hence,. √3 is an irrational number

Harshit Mahar 5 years, 5 months ago

3 is rational

Lucifer ? Morningstar? 5 years, 5 months ago

3 is not irrational number
  • 3 answers

Gaurav Seth 5 years, 5 months ago

Constructing a 90º Angle

We can construct a 90º angle either by bisecting a straight angle or using the following steps.

Step 1:  Draw the arm <i>PA</i>.
Step 2:  Place the point of the compass at <i>P</i> and draw an arc that cuts the arm at <i>Q</i>.
Step 3:  Place the point of the compass at <i>Q</i> and draw an arc of radius <i>PQ</i> that cuts the arc drawn in Step 2 at <i>R</i>.
Step 4:  With the point of the compass at <i>R</i>, draw an arc of radius <i>PQ</i> to cut the arc drawn in Step 2 at <i>S</i>.
Step 5:  With the point of the compass still at <i>R</i>, draw another arc of radius <i>PQ</i> near <i>T</i> as shown.
Step 6:  With the point of the compass at <i>S</i>, draw an arc of radius <i>PQ</i> to cut the arc drawn in step 5 at <i>T</i>.
Step 7:  Join <i>T</i> to <i>P</i>. The angle <i>APT</i> is 90º.

.. .... 5 years, 5 months ago

(Hii) Urvashi aap 10th class me aagi ho or 90 degree angle drow karna nahi janti ho kya???

Lucifer ? Morningstar? 5 years, 5 months ago

Use a protector, point out at 90° and draw a line ,u got ur answer
  • 2 answers

Anil Kumar 5 years, 5 months ago

Right answer

Lucifer ? Morningstar? 5 years, 5 months ago

Let the first term be a and common difference be d. A/q a+7d=-23 ....(१) and a+11d=-२9....(२) equate both equation then, d=-3/2 and first term is -67/2
  • 1 answers

Gaurav Seth 5 years, 5 months ago

'a' or the first term=26
and 'd' or the common difference =21-26=-5
n=?
Sum of n terms of A.P=11
Sum of n terms of A.P=n/2(2a+(n-1)d
11=n/2(52-5n+5)
22=n(57-5n)
22=57n-5n2
5n2-57n+22=0
By splitting the middle term,
5n2-55n-2n+22=0
5n(n-11)-2(n-11)=0
(5n-2)(n-11)=0
n-11=0
n=11

  • 5 answers

Virsan Edage 5 years, 5 months ago

Hi

? Pranali.A.P ? 5 years, 5 months ago

Koi na ?

Anushka ?? 5 years, 5 months ago

Thanks

? Pranali.A.P ? 5 years, 5 months ago

Seconds

? Pranali.A.P ? 5 years, 5 months ago

3600
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

using Pythagoras law we got QR² = PR² - PQ² => QR = √ PR² - PQ² => QP = √ ( 13 )² - ( 12 )² => QP = √ 169 - 144 => QP = √25 => QP = 5 .°. tan P = QR/PQ tan P = 5/12 and Cot R = QR/PQ Cot R = 5/12 now tan P - Cot R = 5/12 - 5/12 = 0 answer is nothing means 0 ! xD
  • 2 answers

? Pranali.A.P ? 5 years, 5 months ago

Thanks ??

Drift? Boi? 5 years, 5 months ago

px^2-14x+8=0 let  a and b be the roots of the equation b=6a sum of roots = -b/a product of roots = c/a here a=p , b=-14 , c=8 a+b=14/p ab=8/p a+6a=14/p 7a=14/p a=2/p a*6a=8/p 6a^2=8/p 3a^2=4/p 3*(2/p)^2=4/p 3*4/p^2=4/p p=3
  • 2 answers

? Pranali.A.P ? 5 years, 5 months ago

Question ka answer do
??♥️❤️♥️
  • 1 answers

? Pranali.A.P ? 5 years, 5 months ago

Available in this app ,?plz ?thoda ksht kre ?

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