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? Pranali.A.P ? 5 years, 5 months ago
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Sana(Silent Love).. ?? 5 years, 5 months ago
Aditya Chaturvedi 5 years, 5 months ago
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Bharath Talliboina 5 years, 5 months ago
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Testing Testing1 5 years, 5 months ago
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Aditya Chaturvedi 5 years, 5 months ago
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Lucifer ? Morningstar? 5 years, 5 months ago
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? Pranali.A.P ? 5 years, 5 months ago
Posted by Himanshu Jha 5 years, 5 months ago
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Yogita Ingle 5 years, 5 months ago
4/x + 3y=14 and 3/x - 4y=23
Let 1/x = m,
4m + 3y = 14...(1)
and 3m - 4y = 23 ... (2)
Multiply (1) by 4 and (2) by 3, we get
16m + 12y = 56 ... (3) and 9m - 12y = 69 .... (4)
Adding (3) and (4), we get
25m = 125
→ m = 5
From (1),
4(5) + 3y = 14
→ 3y = 14 - 20
→ y = -2 and m = 1/x = 5 → x = 1/5
Posted by ? Pranali.A.P ? 5 years, 5 months ago
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Posted by Harshit Mahar 5 years, 5 months ago
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Lucifer ? Morningstar? 5 years, 5 months ago
Posted by Jashan Choudhary 5 years, 5 months ago
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Gaurav Seth 5 years, 5 months ago
Let us assume that √3 is a rational number.
then, as we know a rational number should be in the form of p/q
where p and q are co- prime number.
So,
√3 = p/q { where p and q are co- prime}
√3q = p
Now, by squaring both the side
we get,
(√3q)² = p²
3q² = p² ........ ( i )
So,
if 3 is the factor of p²
then, 3 is also a factor of p ..... ( ii )
=> Let p = 3m { where m is any integer }
squaring both sides
p² = (3m)²
p² = 9m²
putting the value of p² in equation ( i )
3q² = p²
3q² = 9m²
q² = 3m²
So,
if 3 is factor of q²
then, 3 is also factor of q
Since
3 is factor of p & q both
So, our assumption that p & q are co- prime is wrong
hence,. √3 is an irrational number
Posted by Urvashi Singh 5 years, 5 months ago
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Gaurav Seth 5 years, 5 months ago
Constructing a 90º Angle
We can construct a 90º angle either by bisecting a straight angle or using the following steps.
Step 1: Draw the arm <i>PA</i>.
Step 2: Place the point of the compass at <i>P</i> and draw an arc that cuts the arm at <i>Q</i>.
Step 3: Place the point of the compass at <i>Q</i> and draw an arc of radius <i>PQ</i> that cuts the arc drawn in Step 2 at <i>R</i>.
Step 4: With the point of the compass at <i>R</i>, draw an arc of radius <i>PQ</i> to cut the arc drawn in Step 2 at <i>S</i>.
Step 5: With the point of the compass still at <i>R</i>, draw another arc of radius <i>PQ</i> near <i>T</i> as shown.
Step 6: With the point of the compass at <i>S</i>, draw an arc of radius <i>PQ</i> to cut the arc drawn in step 5 at <i>T</i>.
Step 7: Join <i>T</i> to <i>P</i>. The angle <i>APT</i> is 90º.

.. .... 5 years, 5 months ago
Lucifer ? Morningstar? 5 years, 5 months ago
Posted by Nikhil Singh 5 years, 5 months ago
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Posted by Pranav Singh 5 years, 5 months ago
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Lucifer ? Morningstar? 5 years, 5 months ago
Posted by Lucifer?? Morningstar?? 5 years, 5 months ago
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Gaurav Seth 5 years, 5 months ago
'a' or the first term=26
and 'd' or the common difference =21-26=-5
n=?
Sum of n terms of A.P=11
Sum of n terms of A.P=n/2(2a+(n-1)d
11=n/2(52-5n+5)
22=n(57-5n)
22=57n-5n2
5n2-57n+22=0
By splitting the middle term,
5n2-55n-2n+22=0
5n(n-11)-2(n-11)=0
(5n-2)(n-11)=0
n-11=0
n=11
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Drift? Boi? 5 years, 5 months ago
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