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Ask QuestionPosted by Aishwarya Balajishinde Shinde 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
Let us assume that √3 is a rational number.
then, as we know a rational number should be in the form of p/q
where p and q are co- prime number.
So,
√3 = p/q { where p and q are co- prime}
√3q = p
Now, by squaring both the side
we get,
(√3q)² = p²
3q² = p² ........ ( i )
So,
if 3 is the factor of p²
then, 3 is also a factor of p ..... ( ii )
=> Let p = 3m { where m is any integer }
squaring both sides
p² = (3m)²
p² = 9m²
putting the value of p² in equation ( i )
3q² = p²
3q² = 9m²
q² = 3m²
So,
if 3 is factor of q²
then, 3 is also factor of q
Since
3 is factor of p & q both
So, our assumption that p & q are co- prime is wrong
hence,. √3 is an irrational number
Posted by Yash Jaiswal????? 5 years, 4 months ago
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Yash Jaiswal????? 5 years, 4 months ago
Sumesh ☺️☺️☺️ 5 years, 4 months ago
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Aman Sukla 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
4x+3y=11........(i)
3y-4x=19
-4x + 3y = 19 ........(ii)
adding (i) and (ii)
6y = 30
y = 30/6 = 5
Put y = 5 in (i)
4x + 3(5) = 11
4x + 15 = 11
4x = 11 - 15
4x = -4
x = -1
Posted by Avanthika Gadiyar 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
For many experiements it is reasonable to assume that all possible outcomes are equally likely.
For example:
- Draw a random sample of size n from a population. The assumption that the sample is drawn at random means that all samples of size n have an equal chance of being chosen (much of statistical analysis depends on the assumption that samples are chosen randomly).
- Flip a fair coin n times and observe the sequence of heads and tails that results.
- Roll n dice, die 1, die 2, die 3, . . . , die n, and observe the ordered sequence of numbers on the uppermost faces.
Lucifer?? Morningstar?? 5 years, 4 months ago
Posted by Jaya Mishra 5 years, 4 months ago
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Posted by Rahul Singh 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
510 = 2 × 5 × 3 × 17
92 = 2 × 2 × 23
LCM(510,92) = Product of the greatest power of each factor
=2×2×3×5×17×23
=23,460
HCF(510,92)=Product of lowest power if each common factor
=2
Posted by Praveen Gangwar 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 
to 
as he walks towards the building. Find the distance he walked towards the building.
Ans. AB = 30 m and PR = 1.5 m
AC = AB – BC
= AB – PR
= 30 – 1.5
= 28.5 m
In right triangle ACQ,
QC = 
m
In right triangle ACP,
PQ = 
PQ = 
= 
m
Hence, the walked towards the building is m.
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Gaurav Seth 5 years, 4 months ago
For any two numbers a and b, there exists q and r such that
a = bq + r .... Using euclid division algorithm
Here 0 <= r < b
Taking b = 6, a = 6q + r
where 0 <= r < 6
This means r can take the values 0, 1, 2, 3, 4 and 5
When r = 0, 2, 4 the value of a will be 6q, 6q+2, 6q+r which are even
When r = 1, 3, 5
a = 6q + 1, a = 6q + 3, a = 6q + 5 are all odd numbers.
Hence, any positive odd integer is of the form 6q + 1, 6q + 3 or 6q + 5
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