Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Rohini Waghe 5 years, 4 months ago
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Posted by Tanisha Mukherjee 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
5. In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number mangoes. The following was the distribution of mangoes according to the number of boxes.
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Ans. Since value of number of mangoes and number of boxes are large numerically. So we use step-deviation method.
From given data, Assume mean 
= 57, Width of the class 
= 3
= 
(approx.)
Using formula, Mean 
= 57 + 3 (0.0625) = 57 + 0.1875 = 57.1875 = 57.19 (approx.)
Hence mean number of mangoes kept in a packing box is 57.19.
Posted by Tanisha Mukherjee 5 years, 4 months ago
- 3 answers
Yogita Ingle 5 years, 4 months ago
5. In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number mangoes. The following was the distribution of mangoes according to the number of boxes.
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Ans. Since value of number of mangoes and number of boxes are large numerically. So we use step-deviation method.
From given data, Assume mean = 57, Width of the class = 3
= (approx.)
Using formula, Mean = 57 + 3 (0.0625) = 57 + 0.1875 = 57.1875 = 57.19 (approx.)
Hence mean number of mangoes kept in a packing box is 57.19.
Posted by Tanisha Mukherjee 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
5. In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number mangoes. The following was the distribution of mangoes according to the number of boxes.
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Ans. Since value of number of mangoes and number of boxes are large numerically. So we use step-deviation method.
From given data, Assume mean = 57, Width of the class = 3
= (approx.)
Using formula, Mean = 57 + 3 (0.0625) = 57 + 0.1875 = 57.1875 = 57.19 (approx.)
Hence mean number of mangoes kept in a packing box is 57.19.
Posted by Girish Chandramouli 5 years, 4 months ago
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Posted by Niyati Gautam 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
Given that cubic polynomial,
x³-3x²+x+1
then,
(a-b)+a+(a+b)=-b/a
3a=-(-3)/1
3a=3
a=3/3
a=1
Again,
(a-b)*a*(a+b)=-d/a
a(a²-b²)=-1/1
1(1²-b²=-1
1-b²=-1
-b²=-1-1
-b²=-2
b±2
b=±√2
that
a=1
b=√2
Posted by Karan Jadhav 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
Area of sector =Φ/360°*πr²
WhereΦ=angle of sector
area =6*6*22/6*7
=792/42=18.85
area of sector =18.85cm²
Posted by Lucifer?? Morningstar?? 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
4x²-80x+400 = 0
x2 - 20x + 100 = 0
x2 - 10x - 10x + 100 =0
x ( x - 10) - 10 (x - 10) =0
(x -10) (x - 10) = 0
x - 10 = 0, x - 10 = 0
x = 10 and x = 10
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Loving Nature ?????? 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
It is given that:
Length of a tile = 15m 17m = 1517cm [∵ 1m = 100cm]
Breadth of a tile = 9m 2m = 902cm
∴ Side of each square tile = HCF (1517, 902)
Prime factorization:
1517 = 37 × 41
902 = 22 × 41
∴ HCF = product of smallest power of each common prime factor in the numbers = 41
∴ Required number of tiles = Area of ceiling/Area of one tile = 1517 x 902/ 41 x 41 = 37 x 22 = 814
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Loving Nature ?????? 5 years, 4 months ago
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Palak ? 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
The given link has all the subject question papers:
CBSE question papers 2018, 2017, 2016, 2015, 2014, 2013, 2012, 2011, 2010, 2009, 2008, 2007, 2006, 2005 and so advancing for all the subjects are available under this download link. Practicing real question paper certainly helps students to get confidence and improve performance in weak areas.
Click on the given link :
<a href="https://mycbseguide.com/blog/cbse-previous-year-question-papers-for-class-10/">https://mycbseguide.com/blog/cbse-previous-year-question-papers-for-class-10/</a>
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Gaurav Seth 5 years, 4 months ago
- As you know that π is a irrational number as it's decimal expension is non- terminating & Non- repeating.
- But these statements are actually true because we have assumed the APPROPRIATE value of π as 22/7 to make calculation easier.
- If you divide 22/7 then it's decimal expension will come 3.14... which as approximately value equal to π.
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Aditya Pandey 5 years, 4 months ago
0Thank You