CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Here x₁ = -3, y₁ = 10, x₂ = 6, y₂ = -8 ...... [m(6) + n (-3)]/(m+n) , [m (-8) + n (10)]/(m+n) = (-1,6) ....... (6m - 3n)/(m+n), (-8m+10n)/(m+n) = (-1,6) ....... equating the coefficients of x and y....... (6m-3n)/(m+n) = -1 ....... (-8m+10n)/(m+n) = 6........... 6m - 3n = -1 (m+n)............ 6m - 3n = -1 (m+n).......... 6m-3n=-m-n.......... 6m+m=-n+3n......... 7m=2n.. ......... m/n= 2/7......... m:n = 2:7.......... So the point (-1,6) is dividing the line segment in the ratio 2:7.

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Gaurav Seth 5 years, 4 months ago

Let P(-1, 6) divides the line segment joining the points A(-3, 10) and B(6, -8) in the ratio K : 1.
Then the co-ordinates of P are given by

Here, we have
x₁ = -3, y₁ = 10
x₂ = 6, y₂ = -8
and m₁ = K, m₂ = 1
So, the co-ordinates of P are

But the co-ordinates of P are given as P(-1, 6)

Hence, required ratio = 2 : 7.

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ANSWER

It is immediately ok.

Posted by Vanshika Baliyan 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Vivek Yadav 5 years, 4 months ago

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Which YouTube channel explain statistics in the best way plz tell. Imigiately.

Posted by Vanshika Baliyan 5 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

In case of even number find the sum of 1n term

Posted by Mannat Anand 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Ranjan 5 years, 4 months ago

Let n = 2 Then sun of first 2 term of even number equal to even, 2 + 4 = 6 This shows that sum of nth term of even number is always even

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Exercise 12.3

Posted by Purva Choudhary 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Love Preet 5 years, 4 months ago

available on this app..

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Find the zeroes of quadratic Polyno mial 3x2 and verify the relatiinship between the zeroes of the corfficient

Posted by Rajesh Rai 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

-√(2/3),√(2/3) are zeroes of the given polynomial

Explanation:

Given Quadratic polynomial p(x) = 3x²-2

i) To find the zeroes of p(x),

we must take p(x)=0

3x²-2 = 0

=> 3x² = 2

=> x² = 2/3

=> x = ±√(2/3)

Verification:

Let m,n are two zeroes of the polyomial,

m = -√(2/√3)and n = √(2/3)

Compare p(x) with ax²+bx+c , we get

a = 3 , b = 0 , c=-2

i) sum of the zeroes =

= -√(2/3)+√(2/3)

= 0

ii) Product of the zeros

= [-√(2/3)][√(2/3)]

= -2/3

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prove that quadratic equation ax^2+bx+c =-b+-√b^2 -4ac

Posted by Vishvajit Yadav 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

Quadratic Formula Derivation

Consider the equation ax²+bx+c = 0, a ≠ 0.

Dividing the equation by a gives,

x²+ b/a x+c/a = 0

By using method of completing the square, we get

(x+b/2a)² – (b/2a)² + c/a = 0

(x+b/2a)² – [(b²-4ac)/4a²]= 0

(x+b/2a)² = (b²-4ac)/4a²

Roots of the equation are found by taking the square root of RHS. For that b²-4ac should be greater than or equal to zero.

When b²-4ac ≥ 0,

(x + b2a) = ± b2 − 4ac√2a

x = −b ± b2 − 4ac√2a —-(1)

Therefore roots of the equation are, −b + b2 − 4ac√2a and −b − b2 − 4ac√2a

The equation will not have real roots if b²-4ac < 0, because square root is not defined for negative numbers in real number system.

Equation (1) is a formula to find roots of the quadratic equation ax²+bx+c = 0, which is known as quadratic formula.

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HCF of 867 and 255

Posted by Aagam Jain 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 4 months ago

By using Euclid division Lemma
a=bq+r
where a is > b
so a = 867 and b =255
867=255×3+102
here r≠ 0 so a = 255 and b = 102
255 = 102 × 2 + 51
here r ≠ 0 so a = 102 and b = 51
102 = 51 × 2 + 0
here r = 0
so, Hcf of (867,255) is = 51

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A train covered a certain distance at a uniform speed. If the train would have been 10km/h; faster it would take 2 hour less than the scheduled time. And, if the train were slower by 10km/h; it would have taken 3 hours more than the scheduled time. Find the distance covered by the train.

Posted by Chandraveer Behra 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 4 months ago

Let the speed of the train be xkm/h and the time taken by train to travel the given distance be t hours and the distance to travel be dkm. We know that,

⇒Speed=Distance/Time

⇒x= d/t

∴d=xt.......(i)

Case 1

⇒(x+10)×(t−2)=d

⇒xt+10t−2x−20=d

⇒d+10t−2x−20=d

⇒−2x+10t=20...... (ii)

Case 2

⇒(x−10)×(t+3)=d

⇒xt−10t+3x−30=d

⇒d−10t+3x−30=d

⇒3x−10t=30......... (iii)

Adding equations (ii) and (iii), we gets

⇒x=50

Substitute the value of x in (ii) we gets

⇒(−2)×(50)+10t=20

⇒−100+10t=20

⇒10t=120

⇒t=12 hours

Substitue the value of t and x in equation (i), we gets

Distance to travel =d=xt

⇒d=12×50=600Km

Hence, the distance covered by the train is 600km.

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ANSWER

Which one of the following salts will dissolve in water to form an alkaline solution?

Posted by Pruthvijeet Kalantri 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

On dissolving in water, which of the following salt give an alkaline solution?
A. Ammonium Chloride
B. Sodium Carbonate
C. Sodium Acetate
D. Sodium Chloride
Ans. B
Explanation: On dissolving in water, Sodium Carbonate salt gives an alkaline solution.

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ANSWER

Is the triangle with sides 25cm,5cm and 24cm a right triangle? Give reasons

Posted by Anjali Patel 5 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Yogita Ingle 5 years, 4 months ago

Let a = 25 cm, b = 5 cm and c =24 cm
Now, b² + c² = (5)² + (24)²
= 25+ 576 = 601 ≠ (25)²
Hence, given sides do not make a right triangle because it does not satisfy the property of Pythagoras theorem.

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Anita Maheshwari 5 years, 4 months ago

Hence,given sides do not make a right angle triangle because it doesn't satisfy the property of pythagoras theorem

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? Pranali.A.P ? 5 years, 4 months ago

Hence, given sides do not make a right triangle because it does not satisfy the property of Pythagoras theorem.

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9÷3×3=9 CAN ANYONE TELL ME HOW IT IS POSSIBLE

Posted by Ajay Yadav 5 years, 4 months ago

CBSE > Class 10 > Mathematics

5 answers

Rahul Raaz Rahul Raaz 5 years, 4 months ago

9÷3×3 =3×3 =9

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Smile Please 5 years, 4 months ago

Please follow BODMAS in these type of questions...

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.. .... 5 years, 4 months ago

Is now my answer is correct or not ???

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.. .... 5 years, 4 months ago

Question is 9÷3×3=9:- So let,9÷3=3 then 3 is left so we can multiply the 3×3 so we get 9

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Shashank Mishra 5 years, 4 months ago

Yes, because according to BODMAS first we have to divide and then multiply.

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ANSWER

Why 9÷3×3=0

Posted by Ajay Yadav 5 years, 4 months ago

CBSE > Class 10 > Mathematics

5 answers

.. .... 5 years, 4 months ago

Yes,but why 9 is answer ???

1Thank You

Ajay Yadav 5 years, 4 months ago

Your answer is incorrect mahi

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Ajay Yadav 5 years, 4 months ago

Your answer is incorrect

1Thank You

Ajay Yadav 5 years, 4 months ago

You can see in calculator Answer is 9

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.. .... 5 years, 4 months ago

3×3=9 then 9÷9=1 not 0 (is my answer is correct or not)

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ANSWER

Find the product of 3√4×√2

Posted by Md Tamimul Haque 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Harsh Chauhan 5 years, 4 months ago

√4=2 so ,the value is 3×2×√2=6√2

2Thank You

ANSWER

7cm,24cm,25cm, in triangle they are the length of its hypotenuse

Posted by Bhomic Roy 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

Yes , sides 7cm,24cm,25cm form a right angle triangle

Step-by-step explanation:

In right triangle, the square of the hypotenuse length is equal to the sum the squares of base and perpendicular length .

Hypotenuse² = Perpendicular² + Base²

As given

Do sides 7cm ,24cm ,25cm form a right angle triangle .

As hypotenuse sides is always greater length side i.e 25 cm .

625 = 576 + 49

625 = 625

Thus the square of the hypotenuse length is equal to the sum the squares of base and perpendicular length .

Therefore sides 7cm,24cm,25cm form a right angle triangle

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Explain how 2+2=5 ?

Posted by Shashank Mishra 5 years, 4 months ago

CBSE > Class 10 > Mathematics

5 answers

Ajay Yadav 5 years, 4 months ago

TELL ME HOW 4+4=10

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Shashank Mishra 5 years, 4 months ago

Sorry the third line was written by mistake The second step is not there in the solution

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Shashank Mishra 5 years, 4 months ago

No, it was not by mistake I can prove this.... By this method— We can take20–20=25–25 And we can write it also as (5×5)–(5×5)=(5×5)–(5×5) Now by taking out the common factor we get 4(5–5)=5(5–5) Canceling (5–5) from both sides Gives us. 4=5 So it is now clear that 2 + 2 can also be 5 Mujhe aaj hi Pata Chala ye method

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? Pranali.A.P ? 5 years, 4 months ago

Vo galti se ho gya hai aap se 2+2= 4 hota hai

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Sabir Sadha 5 years, 4 months ago

2+2=4

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5 pencils and 7 pens together cost 50Rs,whereas 7 pencils and 5 pen together cost 46Rs. FIND THE COST OF 1 PENCIL AND THAT OF 1 PEN(Form the pair of linear equations and find the solution graphically)I NEED BRIEF EXPLANATION FOR THIS QUESTION!!!!!

Posted by Aishwarya Vishwakarma 5 years, 4 months ago

CBSE > Class 10 > Mathematics

4 answers

Rahul Kamat 5 years, 4 months ago

Sorry solve graphically

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Rahul Kamat 5 years, 4 months ago

Find the value of x and y

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Rahul Kamat 5 years, 4 months ago

Then A/q 5y +7x = 50 rs.----- (1) And 7y+5x= 46 rs.------(2) Solving eq. 1 and 2 by elimination method

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Rahul Kamat 5 years, 4 months ago

Let the cost of pencil be 'y' Rs. And that of pen be 'x' Rs.

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From where should i go for replacement of maths marks with computer application code 165 Help me I realy in need

Posted by Diya Maurya 5 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Express the trigonometric ratios sinA, secA and tanA in terms of cotA

Posted by Vicky Arora 5 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Omkar Meher 5 years, 4 months ago

Right answer

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Yogita Ingle 5 years, 4 months ago

[ i ] sinA in terms of cotA :

sinA = 1 / cosecA

We know that: cosec²A = 1 + cot²A

sinA = 1 / √1 + cot²A

[ ii ] secA in terms of cotA :

We know that: 1 + tan²A = sec²A

secA = 1 + tan²A

secA = 1 + 1 / cot²A

secA = √(cot²A + 1 ) /cotA

[ iii ] tanA in terms of cotA :

tanA = 1 / cotA

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I've a question i got compartment in my class 10th. I'm soo confused all total in math i got 24 marks and in science i got 42 in all total but in exam i got 24 and 18 in practical. So mujhe sirf maths ka compartment dena hoga ya science ka b dena hoga

Posted by Looser . 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Ranjan 5 years, 4 months ago

Only maths ka dena hoga

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ANSWER

Sin(b+c)/2*cosA/2+cos(b+c)/2*Sina/2

Posted by Shibi Vs 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Ranjan 5 years, 4 months ago

We knoe that A+B+C=180 B+C=180-A (B+C)/2=(180-A)/2 (B+C)/2=90-A/2 Cos(B+C)/2=Cos(90-A/2) Cos(B+C)/2=Sin A/2 Or, Sin(B+C)/2=Sin(90-A/2) Sin(B+C)/2=Cos A/2 Now, According to question Sin(b+c)/2 * cos A/2 +cos(b+c)/2 *sin A/2 Cos A/2 *cos A/2 + sinA/2 *sin A/2 Cos^2 A/2+sin^ A/2 1 is ur answer

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X^2-3√5x+10 = 0

Posted by Kavita Bidla 5 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 5 years, 4 months ago

x²-3√5x+10=0

Splitting the middle term, we get

=> x²-2√5x-√5x+10=0

=> x²-2√5x-√5x+2×5=0

=> x²-2√5x+√5x +2×√5×√5=0

=> x(x-2√5)-√5(x-2√5)=0

=> (x-2√5)(x-√5)=0

=> x-2√5 =0 Or x-√5 = 0

=> x = 2√5 Or x = √5

Therefore,

Roots of given Quadratic equation are:

2√5 Or √5

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? Pranali.A.P ? 5 years, 4 months ago

x²-3√5x+10=0......... Splitting the middle term, we get...... => x²-2√5x-√5x+10=0........ => x²-2√5x-√5x+2×5=0......... => x²-2√5x+√5x +2×√5×√5=0........ => x(x-2√5)-√5(x-2√5)=0........ => (x-2√5)(x-√5)=0........ => x-2√5 =0 Or x-√5 = 0....... => x = 2√5 Or x = √5........ Therefore,........ Roots of given Quadratic equation are.......: 2√5 Or √5...... •••••

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What is 20+5

Posted by Narendra Kushwah 5 years, 4 months ago

CBSE > Class 10 > Mathematics

5 answers

Liv 5 years, 4 months ago

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Sayak Kundu 5 years, 4 months ago

It's 25

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Kavita Bidla 5 years, 4 months ago

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.. .... 5 years, 4 months ago

25 bro

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? Pranali.A.P ? 5 years, 4 months ago

1Thank You

ANSWER

Sir, new syllabus CBSE ma nahi dekha raha ha

Posted by Ankit Singh 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 4 months ago

Click on the given link for revised syllabus :

<a href="http://cbseacademic.nic.in/Revisedcurriculum_2021.html">http://cbseacademic.nic.in/Revisedcurriculum_2021.html</a>

<font color="#FF6600"><font style="box-sizing: border-box;">Revised Curriculum for the Academic Year 2020-21</font></font>

<a data-toggle="collapse" href="http://cbseacademic.nic.in/Revisedcurriculum_2021.html#collapse2" style="box-sizing:border-box; color:inherit; text-decoration:none; display:block; font-weight:bold">Revised Secondary Curriculum (IX-X)</a>

</div> </div> <div class="panel panel-default" style="border:1px solid #dddddd; margin-bottom:0px; border-radius:4px; margin-top:5px"> <div class="panel-heading" style="border-bottom:0px #dddddd; padding:10px 15px; border-top-left-radius:3px; border-top-right-radius:3px; border-top-color:#dddddd; border-right-color:#dddddd; border-left-color:#dddddd">

<a data-toggle="collapse" href="http://cbseacademic.nic.in/Revisedcurriculum_2021.html#collapse1" style="box-sizing:border-box; color:inherit; text-decoration:none; display:block; font-weight:bold">Revised Senior Secondary Curriculum (XI-XII)</a>

</div> </div> </div>

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Multiple of 54

Posted by Mamta Agrawal 5 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Liv 5 years, 4 months ago

54,108,162,......

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? Pranali.A.P ? 5 years, 4 months ago

54,108,162,216,270,324,378,432,486,540,594,648,702,756,810,864,918,972,1026,1080,1134,1188,1242,1296,1350,1404,1458,1512,1566,1620,1674,1728,1782,1836,1890,1944,1998,2052,2106,2160,2214,2268,2322,2376,2430,2484,2538,2592,2646,

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Abhishek Kumar 5 years, 4 months ago

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ANSWER

Find the roots of the following quadratic equations,by the formula method. 1)5xsquare - 6x - 2 = 0 2)4xsquare + 3x + 5 = 0

Posted by Boregowda Boregowda 5 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

? Pranali.A.P ? 5 years, 4 months ago

Roots are x = (3±√14)/5..... Explanation:.... Compare 5x²-6x-2=0 with ....... =x²+bx+c=0 we get...... a = 5, b = -6 , c = -2 ....... Discreminant (D) = b²-4ac........ = (-6)²-4×5×(-2)........................................... = 36 + 40...................... = 76............... By Quadratic Formula:...................... x = [(-b±√D)/2a]..................... = [-(-6)±√76]/(2×5)............ = ( 6±2√14)/10............. = (3±√14)/5.............. Therefore,........... Roots are x = (3±√14)/5..,.............. •••.............

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Aditya Pandey 5 years, 4 months ago

https://youtu.be/1xKSSckSA0Q

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ANSWER

what number comes between 2and 4? If you know the answer then tell me

Posted by Shashank Mishra 5 years, 4 months ago

CBSE > Class 10 > Mathematics