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  • 5 answers

Jagrati Sharma?? 5 years, 3 months ago

Other student tell me ans. of this que...

Jagrati Sharma?? 5 years, 3 months ago

Thanks bhavya....

Jagrati Sharma?? 5 years, 4 months ago

What Se (to Arun )

Bhavya Kapoor 5 years, 4 months ago

Let the first no. be 'a' Therefore the terms of the AP are a , a+d ,a+2d ,a+3d. So, a+(a+d)+(a+2d)+(a+3d)=50 4a+6d=50 2a + 3d = 25.......i now we know that the 4th term is 4times the first term. Therefore, 4a = a+3d 3a = 3d a = d......ii Substituting ii in i we get 2a+3a=25 a = 5 Thus the AP is 5 , 10 , 15 , 20 ....

Arun Arun 5 years, 4 months ago

Se
  • 1 answers

Aman Kumar 5 years, 4 months ago

Head head , tail tail , tail head
  • 2 answers

Yukti Sood 5 years, 4 months ago

But it is different for different total marks

Yukti Sood 5 years, 4 months ago

1 per cent means that you get 1 mark out of 100 marks
  • 1 answers

Yogita Ingle 5 years, 4 months ago

3x-5y=7--->1

6x-10y=3--->2

Multiple eq 1 with 2

Such that, 6x-10y=14

Now, substrat 1 from 2

6x-10y=14

-(6x-10y=3)

--------------

12x=3

X=3/12

X=⅓

Sub X value in any equation,

6(⅓)-10y=3

2-10y=3

-10y=3/2

-y=3/2/10

-y=3/20

y=-3/20

 

  • 1 answers

Gaurav Seth 5 years, 4 months ago

Let the present age of Arjun be x years and present age of sonu be y years.

According to given conditions,

5 years ago,

x - 5 = 3(y - 5)

x - 3y = -10 ...... (Eqn 1)

10 year later,

x + 10 = 2(y + 10)

x - 2y = 10 ........ (Eqn 2)

On subtracting eqn 1 from 2,

(x - 2y) - (x - 3y) = 10 + 10

-2y + 3y = 20

y = 20

On substituting y = 20 in eqn 2,

x = 2 × 20 + 10

x = 50

Hence present age of Arjun is 50 years and present age of Sonu is 20 years

  • 0 answers
  • 2 answers

Yogita Ingle 5 years, 4 months ago

We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance
 Now,
 40 = 2 × 2 × 2 × 5,
 42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520

Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.

Aditri Mandal 5 years, 4 months ago

2520
  • 1 answers

Gaurav Seth 5 years, 4 months ago

In ΔADC and ΔBAC,
∠ADC = ∠BAC (Given)
∠ACD = ∠BCA (Common angle)
∴ ΔADC ~ ΔBAC (By AA similarity criterion)
We know that corresponding sides of similar triangles are in proportion.

∴ CA/CB =CD/CA

⇒ CA2 = CB.CD. 

An alternate method:

Given in ΔABC, ∠ADC = ∠BAC
Consider ΔBAC and ΔADC
∠ADC = ∠BAC (Given)
∠C = ∠C (Common angle)
∴ ΔBAC ~ ΔADC (AA similarity criterion)

⇒ 



∴ CB x CD = CA²

  • 3 answers

Yukti Sood 5 years, 4 months ago

From cbse board ex 1.1 has been deleted. You don't have to practise this exercise

Yogita Ingle 5 years, 4 months ago

In the given pair, 38220 > 196, thus let 38220 = a and 196 = b

Now by applying the Euclid’s division algorithm, we get

38220=196×195+0 (Here q=195 and r=0)

Since, in the above equation we get, r = 0, therefore, 196 is the HCF of the given pair 196 and 38220.

Vishvajit Yadav 5 years, 4 months ago

solution let a=38220 and b= 196 from euclid division lemma a=bq+r 38220=196×195+0 HCF=196
  • 2 answers

Narinder Singh Singh 5 years, 4 months ago

We know that alpha+beta=-b/a=15/4 and alpha×beta=c/a=3=12/4 Hence polynomial formed is 4xsquare-15x+12

Khawaish Taneja 5 years, 4 months ago

X^2 +15/4x+3
  • 5 answers

Narinder Singh Singh 5 years, 4 months ago

9

Trina Baruah 5 years, 4 months ago

9

Shivam Rai 5 years, 4 months ago

9

Shaurya Kaushik 5 years, 4 months ago

9

Riyana D'Cunha 5 years, 4 months ago

9÷3×3= 3×3= 9
  • 3 answers

Tarannum Jahan 5 years, 3 months ago

I-NUMBER SYSTEMS REAL NUMBERS  Euclid’s division lemma UNIT II-ALGEBRA POLYNOMIALS  Statement and simple problems on division algorithm for polynomials with real coefficients. PAIR OF LINEAR EQUATIONS IN TWO VARIABLES  cross multiplication method QUADRATIC EQUATIONS Situational problems based on equations reducible to quadratic equations ARITHMETIC PROGRESSIONS Application in solving daily life problems based on sum to n terms UNIT III-COORDINATE GEOMETRY COORDINATE GEOMETRY  Area of a triangle. UNIT IV-GEOMETRY TRIANGLES Proof of the following theorems are deleted The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.  In a triangle, if the square on one side is equal to sum of the squares on the other two sides, the angle opposite to the first side is a right angle. CIRCLES No deletion CONSTRUCTIONS  Construction of a triangle similar to a given triangle. UNIT V- TRIGONOMETRY INTRODUCTION TO TRIGONOMETRY  motivate the ratios whichever are defined at 0o and 90o TRIGONOMETRIC IDENTITIES Trigonometric ratios of complementary angles. HEIGHTS AND DISTANCES No deletion UNIT VI-MENSURATION AREAS RELATED TO CIRCLES  Problems on central angle of 120° SURFACE AREAS AND VOLUMES  Frustum of a cone. UNIT VI-STATISTICS & PROBABILITY STATISTICS  Step deviation Method for finding the mean  Cumulative Frequency graph PROBABILITY No deletion

Yukti Sood 5 years, 4 months ago

Exercise - 1.1 Exercise - 2.3 Use of cross multiplication method in ch. 3 Q.3, 4, 8, 9, 10 of Exercise - 4.3 Q. 15 to Q. 20 of Exercise - 5.3 Theorem 6.6 and 6.9 Exercise- 7.3 Exercise - 8.3 Q. 2 to 7 of Exercise 11.1 Q. 7 of Exercise 12.2 and Q. 6 of Exercise 12.3 Exercise - 13.4 Exercise- 14.4 and use of step deviation method for finding mean

Riyana D'Cunha 5 years, 4 months ago

http://cbseacademic.nic.in/Revisedcurriculum_2021.html . Go on the above link and select Math u will get which topics r deleted.
  • 4 answers

Shivam Rai 5 years, 4 months ago

3:4

Anjali Patel 5 years, 4 months ago

3:4

Govind Prasad 5 years, 4 months ago

I don't how to solve

Govind Prasad 5 years, 4 months ago

114
  • 1 answers

Govind Prasad 5 years, 4 months ago

Algebra spelling is wrong
  • 2 answers

Ayaan Sabharwal 5 years, 4 months ago

.........

Ayaan Sabharwal 5 years, 3 months ago

Kg iviikgjjvifijvjj j jvijtjt.tfmvkgt gigkgotjyjgofotk yigifkthtbg
  • 1 answers

Akhilesh Padti 5 years, 4 months ago

6.5
  • 1 answers

Anwesha :) 5 years, 4 months ago

Ex- 5.3 Q no. 15, 16, 17, 18, 19, 20 Please note, only real life based situation questions are deleted. The questions can be asked directly.
  • 1 answers

Chandresh Tiwari 5 years, 4 months ago

The fundamental theorem of arithmetic says that every composite number can be factorized as a product of primes actually it says more. it says that given any composite number it can be factorized as a product of prime numbers in a unique way , except for the order in which the primes occur .
  • 1 answers

Gaurav Seth 5 years, 4 months ago

 

So, x = 1/2, y = 1/3 is the solution of the given equation.

  • 0 answers
  • 4 answers

Shubham Srivastav 5 years, 4 months ago

Wrong hai

Shubham Srivastav 5 years, 4 months ago

3/4+1/4= 4/4=1

Shubham Srivastav 5 years, 4 months ago

√3/2×√3/2+1/2×1/2

Gaurav Seth 5 years, 4 months ago

Step-by-step explanation:

Given : Expression  

To find : The solution of the given expression?

Solution :

Applying property,

We know, 

  • 5 answers

Harshit Dinodia 5 years, 4 months ago

13

Ayush Gupta 5 years, 4 months ago

13

Shivam Tripathi 5 years, 4 months ago

29-9+3-10

Pranali Solanke 5 years, 4 months ago

13

Ashu Yadav 5 years, 4 months ago

13

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