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Ask QuestionPosted by Jagrati Sharma?? 5 years, 4 months ago
- 5 answers
Bhavya Kapoor 5 years, 4 months ago
Posted by Moksha Maheta 5 years, 4 months ago
- 1 answers
Posted by Riyana D'Cunha 5 years, 4 months ago
- 2 answers
Posted by Aniket Pandey 5 years, 4 months ago
- 1 answers
Posted by Veshu Pathak 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
3x-5y=7--->1
6x-10y=3--->2
Multiple eq 1 with 2
Such that, 6x-10y=14
Now, substrat 1 from 2
6x-10y=14
-(6x-10y=3)
--------------
12x=3
X=3/12
X=⅓
Sub X value in any equation,
6(⅓)-10y=3
2-10y=3
-10y=3/2
-y=3/2/10
-y=3/20
y=-3/20
Posted by Desy Joseph 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Let the present age of Arjun be x years and present age of sonu be y years.
According to given conditions,
5 years ago,
x - 5 = 3(y - 5)
x - 3y = -10 ...... (Eqn 1)
10 year later,
x + 10 = 2(y + 10)
x - 2y = 10 ........ (Eqn 2)
On subtracting eqn 1 from 2,
(x - 2y) - (x - 3y) = 10 + 10
-2y + 3y = 20
y = 20
On substituting y = 20 in eqn 2,
x = 2 × 20 + 10
x = 50
Hence present age of Arjun is 50 years and present age of Sonu is 20 years
Posted by Yash Goyal 5 years, 4 months ago
- 2 answers
Posted by Abhishek Kumar 5 years, 4 months ago
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Posted by Surendra Gehlot 5 years, 4 months ago
- 2 answers
Yogita Ingle 5 years, 4 months ago
We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.
Posted by Narinder Singh Singh 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
In ΔADC and ΔBAC,
∠ADC = ∠BAC (Given)
∠ACD = ∠BCA (Common angle)
∴ ΔADC ~ ΔBAC (By AA similarity criterion)
We know that corresponding sides of similar triangles are in proportion.
∴ CA/CB =CD/CA
⇒ CA2 = CB.CD.
An alternate method:
Given in ΔABC, ∠ADC = ∠BAC
Consider ΔBAC and ΔADC
∠ADC = ∠BAC (Given)
∠C = ∠C (Common angle)
∴ ΔBAC ~ ΔADC (AA similarity criterion)
⇒
∴ CB x CD = CA²
Posted by Sukhchain Saini 5 years, 4 months ago
- 3 answers
Yukti Sood 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
In the given pair, 38220 > 196, thus let 38220 = a and 196 = b
Now by applying the Euclid’s division algorithm, we get
38220=196×195+0 (Here q=195 and r=0)
Since, in the above equation we get, r = 0, therefore, 196 is the HCF of the given pair 196 and 38220.
Vishvajit Yadav 5 years, 4 months ago
Posted by Sidharth Charan 5 years, 4 months ago
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Narinder Singh Singh 5 years, 4 months ago
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Tarannum Jahan 5 years, 3 months ago
Yukti Sood 5 years, 4 months ago
Riyana D'Cunha 5 years, 4 months ago
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Ayaan Sabharwal 5 years, 3 months ago
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Anwesha :) 5 years, 4 months ago
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Chandresh Tiwari 5 years, 4 months ago
Posted by Pranjal Devashish 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
So, x = 1/2, y = 1/3 is the solution of the given equation.
Posted by Pranjal Devashish 5 years, 4 months ago
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Posted by Shubham Srivastav 5 years, 4 months ago
- 4 answers
Gaurav Seth 5 years, 4 months ago
Step-by-step explanation:
Given : Expression
To find : The solution of the given expression?
Solution :
Applying property,
We know,
Posted by Arpit Sharma 5 years, 4 months ago
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Posted by Kalp Shah 5 years, 4 months ago
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Jagrati Sharma?? 5 years, 3 months ago
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