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Ask QuestionPosted by Rohit Singh 5 years, 4 months ago
- 1 answers
Posted by Royal Nitin 5 years, 4 months ago
- 1 answers
Aangi Mehta 5 years, 4 months ago
Posted by Saswat Kumar Jena 5 years, 4 months ago
- 3 answers
Gaurav Seth 5 years, 4 months ago
3x-y=3........1
9x-3y=9..(divided by 3)
3x-y=3......2
3x=3-y
X=3-y/3
sub X in 1
3x-y=3
3(3-y/3)-y=3
3-y-y=3
-2y=3-3
y=0
sub y in 2
3x-y=3
3x-0=3
3x=3
X=1
Yogita Ingle 5 years, 4 months ago
3x-y=3........(i)
9x-3y=9..(divided by 3)
3x-y=3......(i)
3x=3-y
X=3-y/3
sub X in (i)
3x-y=3
3(3-y/3)-y=3
3-y-y=3
-2y=3-3
y=0
sub y in (ii)
3x-y=3
3x-0=3
3x=3
X=1
Lucifer?? Morningstar?? 5 years, 4 months ago
Posted by Harikrishnaa J.R 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Let the zeros be a,b,c and d
Then,
..........(1)
..........(2)
Using (1) and (2), we get
when a=-1, b=-2
when a=-2, b=-1
Posted by Abhay Pratap Singh 5 years, 4 months ago
- 0 answers
Posted by Adhyayan Kumar 5 years, 4 months ago
- 1 answers
Posted by Khushwinder Singh 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
et the sum of first n terms of the A.P.=Sn
Given: Sn = 3n2 – 4n ...(i)
Now,
Replacing n by (n –1) in (i), we get,
Sn – 1 = 3(n – 1)2 – 4(n – 1)
nth term of the A.P. an = Sn – Sn – 1
∴ an = (3n2 – 4n) – [3(n – 1)2 – 4(n – 1)]
⇒ an = 3 [ n2 – (n – 1)2] – 4 [n – (n – 1)]
⇒ an = 3 (n2 – n2 + 2n – 1) – 4 (n – n + 1)
⇒ an = 3(2n –1) – 4
⇒ an = 6n – 3 – 4
⇒ an= 6n – 7
Thus, the nth term of the A.P = 6n – 7.
Posted by Student ✍️✍️✍️ 5 years, 4 months ago
- 2 answers
Palak ? 5 years, 4 months ago
Posted by Student ✍️✍️✍️ 5 years, 4 months ago
- 5 answers
Palak ? 5 years, 4 months ago
Riyana D'Cunha 5 years, 4 months ago
Posted by Athulya Sajan Kadicheeni 5 years, 4 months ago
- 0 answers
Posted by Rajnish Kumar 5 years, 4 months ago
- 5 answers
Tarannum Jahan 5 years, 3 months ago
Riyana D'Cunha 5 years, 4 months ago
Posted by Mansee Sharma 5 years, 4 months ago
- 2 answers
Posted by Nikhil Sharma 5 years, 4 months ago
- 2 answers
Posted by Nishkarsh Singh 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Given points are A(-2, k), B(-2k , -3) and P(2, 2)
It is given that point P is the equidistant from the points A and B
So, PA = PB
Now,
Squaring on both sides
⇒ (- 2 - 2)2 + (k - 2)2 = (-2k - 2)2 + (-3 - 2)2
⇒ 16 + k2 + 4 - 4k = 4k2 + 4 + 8k + 25 [∵ ( a - b)2 = a2 - 2ab + b2 ]
⇒ 4k2 + 4 + 8k + 25 -16 - k2 - 4 + 4k = 0
⇒ 3k2 + 12k + 9 = 0
⇒ k2 + 4k + 3 = 0
⇒ k2 + 3k + k + 3 = 0
⇒ k(k + 3) + 1(k + 3) = 0
⇒ (k + 3) (k + 1) = 0
⇒ (k + 3) = 0 or (k + 1) = 0
∴ k = -1 or -3.
Posted by Parinitha S 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Step-by-step explanation:
cos = b/h and sin = b/h
LHS
Sin2 +cos2
={p/h}2 +[b/h]2
=p2 +b2 /h2
=h2/h2
=1
=RHS.......{...HENCE PROVED}
Posted by Teja Pravallika 5 years, 4 months ago
- 2 answers
Pranali Solanke 5 years, 4 months ago
Posted by Gajendra Prasad Mallick 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
Given 3 points A(2,3), B(5,k) and C(6,7) which are collinear we have to find the value of k.
Points are collinear if the slopes of any two pairs are equal.
Slope of AB = y2 -y2/x2 - x1= k-3/5-2
Slop of BC= y2 -y2/x2 - x1= 7-k/6-5
As lines are collinear slopes are equal
⇒k-3/5-2= 7-k/6-5
⇒ k- 3= 2(7-k)
⇒ k= 6
The value of k is 6.
Posted by Navami Mahato 5 years, 4 months ago
- 0 answers
Posted by Liyana Mymoona 5 years, 4 months ago
- 2 answers
Navami Mahato 5 years, 4 months ago
Chandresh Tiwari 5 years, 4 months ago
Posted by Nitesh Jogi 5 years, 4 months ago
- 1 answers
Posted by Sujith Raj 5 years, 4 months ago
- 5 answers
Riyana D'Cunha 5 years, 4 months ago
Gaurav Seth 5 years, 4 months ago
7x-2y=20 .... (1)
11x+15y = -23 .... (2)
Multiply equation (1) by 15 and (2) by 2, we get
105x - 30y = 300 ... (3)
22x + 30y = -46 ... (4)
Adding (3) and (4), we get
127x = 254
→ x = 2
Substitute the value of x = 2 in (1), we get
7(2)-2y=20
→ 2y = -6
→ y = -3
Therefore x = 2 and y = -3.
Posted by Vikas Rai 5 years, 4 months ago
- 1 answers
Riyana D'Cunha 5 years, 4 months ago
Posted by Riya Mol 5 years, 4 months ago
- 1 answers
Riya Mol 5 years, 4 months ago
Posted by Yash Khemani 5 years, 4 months ago
- 2 answers
Riyana D'Cunha 5 years, 4 months ago
Palak ? 5 years, 3 months ago
Posted by Jay Gandhi 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
We know, if A and B lies on circle and C is the centre of circle , then line joining of points A and B is intersected by Centre of circle.
e.g., O lies on midpoint of AB. means, we have to use midpoint section formula.
here, A (-1, y) and B(5,7) lies on circle with centre C(2,-3y) .
A--------------C------------------B
now, use midpoint section formula,
[if (x,y) is the midpoint of (x1,y1) and (x2, y2) then, x = (x1 + x2)/2 and y = (y1+y2)/2 ]
so, -3y = (y + 7)/2
=>-6y = y + 7
=> -7y = 7
=> y = -1
Posted by Arun Arun 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Let AB be the pole and BC be its shadow.
Given that AB/BC = 1/√3
Let ACB be the angle of elevation.
In triangle ABC,
X is equal to theta
tan x = AB/BC
tan x = 1/√3
tan x = tan 30
X = 30
Hence angle of elevation =30∘
Posted by Sanjeev Kumar@4664 Sanjeev 5 years, 4 months ago
- 0 answers

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