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The discriminant of quadratic equation 2x²-11 . Anybody please tell

Posted by Himanshi . 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 3 months ago

Comparing with standard quadratic equation ax² + bx + c = 0

a = 2, b = 0, c = -11

Discriminant D = b² – 4ac

= (0)² – 4.2.(-11)

= 0 + 88

= 88

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Chapter 14 exercises 14.1 7question solution using direct method

Posted by Subiksha Vijaya 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

7. To find out the concentration of SO₂ in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:

Concentration of SO₂ ( in ppm)	Frequency
0.00 – 0.04	4
0.04 – 0.08	9
0.08 – 0.12	9
0.12 – 0.16	2
0.16 – 0.20	4
0.20 – 0.24	2

Find the mean concentration of SO₂ in the air.

Solution:

To find out the mean, first find the midpoint of the given frequencies as follows:

Concentration of SO₂(in ppm)	Frequency (f_i)	Mid-point (x_i)	f_ix_i
0.00-0.04	4	0.02	0.08
0.04-0.08	9	0.06	0.54
0.08-0.12	9	0.10	0.90
0.12-0.16	2	0.14	0.28
0.16-0.20	4	0.18	0.72
0.20-0.24	2	0.20	0.40
Total	Sum f_i = 30		Sum (f_ix_i) = 2.96

The formula to find out the mean is

Mean = x̄ = ∑f_ix_i /∑f_i

= 2.96/30

= 0.099 ppm

Therefore, the mean concentration of SO₂ in air is 0.099 ppm.

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Solve, exercise 5.1,Q.4,(xii)

Posted by Vishakha Girl 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Vishakha Girl 5 years, 3 months ago

Thanks

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Gaurav Seth 5 years, 3 months ago

(xii) √2, √8, √18, √32 …

Here,

a₂ – a₁ = √8-√2 = 2√2-√2 = √2

a₃ – a₂ = √18-√8 = 3√2-2√2 = √2

a₄ – a₃ = 4√2-3√2 = √2

Since, a_n₊₁ – a_n or the common difference is same every time.

Therefore, d = √2 and the given series forms a A.P.

Hence, next three terms are;

a₅ = √32+√2 = 4√2+√2 = 5√2 = √50

a₆ = 5√2+√2 = 6√2 = √72

a₇ = 6√2+√2 = 7√2 = √98

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Please answer ex -6.3 question no.10 page no.140...

Posted by #?Abhishek...? . 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

Class 10 Maths Exercise 6.3

10. CD and GH are respectively the bisectors of ACB and EGF such that D and H lie on sides AB and FE at ABC and EFG respectively. If ABC FEG, show that:

(i)

(ii) DCB HE

(iii) DCA HGF

Ans. We have, ABC FEG

A = F………(1)

And C = G

C = G

1 = 3 and 2 = 4 ……….(2)

[CD and GH are bisectors of C and G

respectively]

In s DCA and HGF, we have

A = F[From eq.(1)]

2 = 4[From eq.(2)]

By AA-criterion of similarity, we have

DCA HGF

Which proves the (iii) part

We have,DCA HGF

Which proves the (i) part

In s DCA and HGF, we have

1 = 3[From eq.(2)]

B = E[ DCB HE]

Which proves the (ii) part

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Rohan's mom age is 26 years older than his son. And his son is twice his age in 3 years. What is his present age

Posted by Prem Dh Majhi 5 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Prime factor

Posted by Rakesh Kushwaha 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

#?Abhishek...? . 5 years, 3 months ago

That number which is divisible by 1 or itself is said to be prime number E.g_ 1,2 ,3,5,7,11......?

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pg no. 214 probability question no. 43

Posted by Ragini Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Sonu Gop 5 years, 3 months ago

Contact me on whats app for any type of solution of phy,che,bio and math

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Gaurav Seth 5 years, 3 months ago

Post the question

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Check whether the following quadratic equation x2-3x+5=(x+5)2

Posted by Namitha Namitha 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 3 months ago

x²-3x+5=(x+5)²
x²- 3x+5 = x² + 10x + 25

x² - x² -3x - 10x + 5 - 25 = 0
- 13x - 20 = 0

It's not a quadratic equation.

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Sin-2sin^3/2cos^3-cos=tan Prove it

Posted by Niharika Raj 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

LHS =

= RHS

LHS

=sin a -2sin ^3 a/ 2cos^3 a + cos a
=sin a (1-2sin^2a)/ cos a ( 2cos2a+1)
=sin a/cos a × 1-2sin2a/2cos2a+1
=tan a × 2(1-sin2a)/2(1-sin2 a)+1
=tana ×1/1
=tan a=RHS

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In the triangle with sides 25cm,5cm and 24 cm a right triangle? Give reasons for your answer.

Posted by Puranjay Vyas 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Niharika Raj 5 years, 3 months ago

No according to converse of Pythagoras theorem If H2 = p2 + b2 then the triangle is right angle..... So, in this triangle square of hypotenuse is not equal to sum of the squares of perpendicular and base..... ? That's all I hope it is helpful

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Ganesh

Posted by Sujith Raj 5 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Syllabus of math

Posted by Shagan Dandiwal 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Love Preet 5 years, 3 months ago

Sry,don't know bro

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Ch 5 , Arithmetic progression , Q If 8n =4n - n2, find an

Posted by Shubhangi Mozarkar 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Rohit Kumar 5 years, 3 months ago

Sum of the first n term = 4n - n^2 Sn = 4n-n^2 then n=1 ,4×1-1^2 =3 the sum of first term is 3 then n=2 , 4×2-2^2=4 the sum of 2 term is 4 then second term = sum of 2 term - sum of 1 term = 4 -3 = 1 then a = 3 , a+d=1 then d =-2 then n term is a+ (n-1)×d = 3+(n-1)×-2 = 5 -2n

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Gaurav Seth 5 years, 3 months ago

We have given that
Sum of the first n terms = 4n – n²
⇒ S_n = 4n – n²

S_{n –1} = 4(n – 1) – (n – 1)²
= (4n – 4) – (n² + 1 – 2n)
= 4n – 4 – n² – 1 + 2n
= 6n – n² – 5
∴ nth term = S_n – S_{n – 1}
= (4n – n²) – (6n – n² – 5)
= 4n – n² – 6n + n² + 5
= 5 –2n.

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Question of ch5 , Q If 8n=4n-n2 find an

Posted by Shubhangi Mozarkar 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

We have given that
Sum of the first n terms = 4n – n²
⇒ S_n = 4n – n²

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Pythagores theorem

Posted by Mohit Thakur 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Syed Sadiq Ahamed 5 years, 3 months ago

The sum of hypotenuse is equal to the sum of other two side of triangle is called pythagoras theorem. AC²=AB²+BC²

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Gaurav Seth 5 years, 3 months ago

Pythagoras Theorem

Statement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.

Given: A right triangle ABC right angled at B.

To prove: AC² = AB² + BC²

Construction: Draw BD AC

Proof :

We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.

ADB ABC

So, (Sides are proportional)

Or, AD.AC = AB²... (1)

Also, BDC ABC

So,

Or, CD. AC = BC²... (2)

Adding (1) and (2),

AD. AC + CD. AC = AB² + BC²

AC (AD + CD) = AB² + BC²

AC.AC = AB² + BC²

AC² = AB² + BC²

Hence Proved.

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Confusion ??? Master ??? 5 years, 3 months ago

Hypotenuse^2 = base ^ 2 + altitude ^ 2

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Help please please

Posted by Aaisha Maaria 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Love Preet 5 years, 3 months ago

How can i help u?

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Neha Singh 5 years, 3 months ago

What's the question u are asking help for

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Shubh Mishra 5 years, 3 months ago

What is the question

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Pic ?

Posted by Aaisha Maaria 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Love Preet 5 years, 3 months ago

What?

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Can i send puc

Posted by Aaisha Maaria 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Love Preet 5 years, 3 months ago

Why?

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Only if i take a pic and send u will be able to answer the math doupt

Posted by Aaisha Maaria 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Love Preet 5 years, 3 months ago

But u can't share a pic here..

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the values after using trigonometry indenties can be with minus sign?

Posted by Navnidhi Gandhi 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Syed Sadiq Ahamed 5 years, 3 months ago

No, the trigonometric values are never calculated as minus,

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Madhu Kaushik 5 years, 3 months ago

see the length will always be positive

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Navnidhi Gandhi 5 years, 3 months ago

_+ root 1-sin² A .......why it can't be in minus

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Maths exam paper

Posted by Ananya Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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Tan(x+30°)=1,then find the value of x

Posted by Vaibhav Raj 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

A n s w e r :
t a n (x + 30 °) = 1

tan (x + 30°) = tan 45°

(x + 30 °) = 45 °

x = 15 °

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X=2 and y=2x value of y =

Posted by Aryavir Malik 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Syed Sadiq Ahamed 5 years, 3 months ago

y=2x,x=2 so y=2x =2(2)=4,y=4

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Confusion ??? Master ??? 5 years, 3 months ago

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Aryavir Malik 5 years, 3 months ago

Value of y=4

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Prove bpt thereom

Posted by Sarang S 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

#?Abhishek...? . 5 years, 3 months ago

Please write clearly...

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Prove that 8x can not end with digit O, for any natural no. n.

Posted by Binay Sharma 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Amir Inamdar 5 years, 3 months ago

Yes 8*n will not end with zero because , the number will end with zero then it's factors should 2and5

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Yogita Ingle 5 years, 3 months ago

We know 8ⁿ = (2³)ⁿ = 2³ⁿ

If 8n end with zero then 10 is factor of 8ⁿ.

8ⁿ = 2³ⁿ = (5)(2)

5 is factor of 2, which is a contradiction

So, our assumption is wrong. Hence 8ⁿ cannot end with zero.

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What is the maximum value of sin theeta????

Posted by Sunidhi Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditya Kumar Singh 5 years, 3 months ago

Nanq

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Yogita Ingle 5 years, 3 months ago

The sine function forms a wave that starts from the origin

sin θ = 0 when θ = 0 ˚ , 180˚ , 360˚ .
Maximum value of sin θ is 1 when θ = 90 ˚. Minimum value of sin θ is –1 when θ = 270 ˚. So, the range of values of sin θ is –1 ≤ sin θ ≤ 1.

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Find x if (root 2x +9) + x = 13

Posted by Sunidhi Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

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2÷7

Posted by Dhruv Lamba 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Anupama ?? 5 years, 3 months ago

0.285714 285714…..…...................

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Sanskriti Sans 5 years, 3 months ago

0.28

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Kukatla Ajith Kumar Yadav Yadav 5 years, 3 months ago

3.5 is the answer

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Can 35 be the term of the given sequence -34, -30, -26

Posted by Samruddhi Br 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Madhav Emineni 5 years, 3 months ago

Let An=35 Given that, A=-34 D=4 (since, [-30-(-34)=4]) So, An=A+(n-1)D 35=-34+(n-1)4 =-34+4n-4 =-38+4n => 4n-38=35 =>4n=35+38 =>n=73/4 But here n is number of digits therefore 35 cannot be the number of this A.P

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Find the discriminant of the following equation:(x+1)^2-x^2

Posted by Suganth Kamal 5 years, 3 months ago

CBSE > Class 10 > Mathematics