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  • 1 answers

Ritik Modi 11 months, 2 weeks ago

0.491
  • 2 answers

Ridhima Goyal 11 months, 2 weeks ago

(a+b)² = a² + b² + 2ab

Sankalp Dinesh 11 months, 2 weeks ago

(a+b)² = a² + 2ab + b².
  • 0 answers
  • 1 answers

Harsh Gehlawat 11 months, 2 weeks ago

2-x-(2k+2) and zero is -4 then Put x = -4 2-(-4)-(2k+2) 2+4-2k-2 6-2-2k 4-2k Put it equal to zero 4-2k=0 -2k=-4 2k=4 K=4/2 K=2 Hence with a simple solution answer is ready
  • 3 answers

Ashish Kumar 11 months, 2 weeks ago

yes

Rashmi , Tadiyal 11 months, 2 weeks ago

Yes

Raman Raj 11 months, 2 weeks ago

Yes
  • 1 answers

Harsh Gehlawat 11 months, 2 weeks ago

2
  • 1 answers

Harsh Gehlawat 11 months, 2 weeks ago

Cos A
  • 1 answers

Ishant Sharma 11 months, 3 weeks ago

I have difficulty in trigonometry
  • 2 answers

Ashish Kumar 11 months, 1 week ago

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Saksham Joshi 11 months, 3 weeks ago

Land
  • 3 answers

Anand Yadav 11 months, 2 weeks ago

√2 is a irrational number √2b=a { a and b are the co prime } √2b=a { both side are squaring} 2b=a { a is divisible by 2 } {2 is divisible by a } Let a=√2c. { c is an integer } 2b=√2c {squaring of √2c } 2b=2c. { c is divisible by 2} { b is divisible by 2} Where a and b are common factor So contradiction is a is √2 irrational number when wrong assertion

Mehakpreet Sandhu 11 months, 3 weeks ago

Watch dear sir video on YouTube

Aditya Singh 11 months, 3 weeks ago

You write direct Latsume to √2 is a rational number Where , √2=p/q =√2p=
  • 1 answers

Miss Anshi 11 months, 1 week ago

Questions is wrong?
  • 1 answers

Sankalp Dinesh 11 months, 2 weeks ago

You want only steps to solve or you want solution with steps??
  • 1 answers

Saksham Hinge 11 months, 3 weeks ago

Let 1 s t term of A . P = a and common difference = d We have to prove that S 12 = 3 ( S 8 − S 4 ) S 12 = 12 2 [ 2 a + ( 12 − 1 ) d ] S 8 = 8 2 [ 2 a + ( 8 − 1 ) d ] S 4 = 4 2 [ 2 a + ( 4 − 1 ) d ] Now, R . H . S = 3 ( S 8 − S 4 ) = 3 [ 8 2 ( 2 a + ( 8 − 1 ) d − 4 2 ( 2 a + ( 4 − 1 ) d ] = 3 [ 8 x + 28 d − 4 a − 6 d ] = 6 ( 2 a + 11 d ) = 12 2 [ 2 a + ( 12 − 1 ) d ] = S 12 = L . H . S
  • 1 answers

Ansh Gupta 11 months, 3 weeks ago

Prove that "Sin²A + Cos²A = 1"
  • 2 answers

Sakshi Sharma 11 months, 3 weeks ago

Given: HCF of two numbers 306 and 657 is 9 To find: LCM of number We know that, LCM x HCF = first number x second number LCM x 9 = 306 x 657 LCM=306x 6579 =22338

Ansh Gupta 11 months, 4 weeks ago

Hey Nisha where is fourth question of 1.2 exercise. Are you joking.
  • 1 answers

Jagmohan Singh 11 months, 4 weeks ago

There's something wrong in your question As SinA = 1/CosecA
  • 1 answers

Jagmohan Singh 11 months, 4 weeks ago

Formula for finding the area of Circle is πr²
  • 2 answers

Anshika Singh 11 months, 2 weeks ago

You can send...

Jagmohan Singh 11 months, 4 weeks ago

I can provide you the text solution But I'll recommend you understand it visually You can watch any video or I can send you my video link .
  • 3 answers

Anshika Singh 11 months, 2 weeks ago

Answer is 2 hour

Anshika Singh 11 months, 2 weeks ago

No

Ansh Gupta 11 months, 3 weeks ago

Nearly about 343 hours.. I have calculated this in my mind without use of copy or pen. If this is incorrect reply me I will try to solve next time in copy and will give you another solution. Ansh
  • 1 answers

Naitik Rajput 11 months, 4 weeks ago

1+sec/sec = sin²A/1-cos 1/sec+sec/sec = 1-cos²/1-cos Cos+1=(1-cos)(1+cos)/1-cos Cos +1 =1+cos LHS = RHS

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