CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

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Currency is a medium of exchange for goods and services. Ashok made a payment to shopkeeper, for the article he purchased, in the denomination of ₹500 and 20. He paid 2640 to the shopkeeper. If all the denomination of * 500 is to be changed by 100 then the boy could have paid * 640 only. Assume the number of currency notes of 500 as 'f' and the number of currency notes of 20 as 'g'". Based on the above information, answer the following questions: i) Write a linear equation representing the amount paid by Ashok. 1 ii) If Ashok had to pay * 2800 to the shopkeeper, how many *20 notes did he need? 1 iii) Find the number of notes in the denomination of ₹500 Ashok had? OR How many total currency notes did Ashok gave to shopkeeper?

Posted by Manas Maurya 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Suryesh Kumar 1 year, 5 months ago

(¡) 5f + 7g = 2640 (¡¡) 15 (¡¡¡) 5 , or , 12

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In the given figure, XZ is parallel to BC. AZ = 3 cm, ZC = 2 cm, BM = 3 cm and MC = 5 cm. Find the length of XY.

Posted by Nitin Kumar 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Arpita Sharma 1 year, 5 months ago

Where is the figure

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What is formula of step deviation in statistics class 10

Posted by Jeet Singh 1 year, 5 months ago

CBSE > Class 10 > Mathematics

4 answers

Gurjot Kaur 1 year, 5 months ago

Mean= a + [∑fiui/∑fi ]×h

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Anurag Singh 1 year, 5 months ago

a+sigmafiui/sigmafi

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Chinmayi P P 1 year, 5 months ago

Mean =a + fiui/fi × h

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Jeet Singh 1 year, 5 months ago

Mean = a + fiui/fi × h

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Find the nature of roots of root3xsquare-root7x+3root3

Posted by Sangmesh Patil 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Choudhury 1 year, 5 months ago

In this case, a = √3, b = -√7, and c = 3√3. Substituting these values in the formula, we get: b² - 4ac = (-√7)² - 4(√3)(3√3) = 7 - 36 = -29 < 0 So, there are no real roots for the given equation

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In given figure DE parallel BC , if ad=2cm ,bd=2.5cm, ae=3.2cm. Find ac

Posted by Aayush Verma 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Choudhury 1 year, 5 months ago

In Triangle ADE and ABC, AD=2 BD=2.5 AE=3.2 DE ll BC, ∴∠ADE=∠ABC ( corresponding angles) ∠AED=∠ACB ( corresponding angles) ∠BAC is common Δ ADE is similar to Δ ABC In similar triangles, we know that the ratio of corresponding sides is equal ∴ AB/AD=AC/AE (AD+BD)/AD = AC/AE (2+2.5)/2=AC/3.2 4.5/2=AC/3.2 ( 4.5×3.2)/2= AC 7.2=AC Hence the value of AC is 7.2

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In parallelogram ABCD bisector of angle A and b intersect each other at all the value of angle aob is

Posted by Manasi Manasi 1 year, 5 months ago

CBSE > Class 10 > Mathematics

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Posted by Kamlesh Kumar 1 year, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Gurjot Kaur 1 year, 5 months ago

1.(a + b)³ = a³ + b³ + 3a²b + 3ab² 2.(a - b)3 = a3-b3 - 3a2b + 3ab2

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Bsdusud Osozixu 1 year, 5 months ago

Ok understood 👌🆗

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Bsdusud Osozixu 1 year, 5 months ago

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How to find modal class upper limit

Posted by Sneha Gupta 1 year, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Sankalp Dinesh 1 year, 5 months ago

First find the modal class that is the class with highest frequency and so it's upper limit is the class's upper value.

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Sneha Gupta 1 year, 5 months ago

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Udayraj Singh Chouhan

Posted by Udayraj Chouhan 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sankalp Dinesh 1 year, 5 months ago

???¿???

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Please send me homework

Posted by Ayush Kumar 1 year, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Miss Anshi 1 year, 4 months ago

😂

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Sankalp Dinesh 1 year, 5 months ago

Which homework???

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Great Great 1 year, 5 months ago

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Find the 11th term of the AP (5a-x), 6a, (7a+x)

Posted by Dhyey Soni 1 year, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Suryesh Kumar 1 year, 5 months ago

Given , AP=(5a-x),(6a),(7a+x) Here , A = 5a-x T¹=5a-x , T ²=6a, T³=7a+ x, D = T²-T¹ => D = 6a - (5a-x) => D= 6a - 5a+ x => D = a + x Now , T ^n = A+ (n-1)D => T ¹¹= A + (11-1)D => T ¹¹ = (5a-x) +10 (a+x) => T ¹¹ = 5a-x + 10a + 10x => T ¹¹ = 10a + 5a +10x - x => T ¹¹ = 15a + 9x Hence the 11th term of this AP is 15a + 9x

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Shubhank Mittal 1 year, 5 months ago

Given, a=( 5a-x) d=a2-a1 6a-(5a-x) 6a-5a+x a+x an =a+(n-1)d a11= 5a-x+(11-1)a+x 5a-x+(10) a+x 5a-x+ 10a +10x 15a+9x answer

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The area of rectangular gets reduced by 9 square unit. If it's land this reduced by 5 yd and bread. This increase by three weeks if we increase the land by three roots and the bread by two units a year increased by sixty seven square europe find the dimension of

Posted by Rishika Garg 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Piyush Kushwah 1 year, 5 months ago

Hey can explain to me

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Draw the graph of equation X - Y + 1is 0 and 3X + 2Y −12 is 0. Find the point of Intersection of lines and shade the triangular region formed by these lines and x axis

Posted by Rishika Garg 1 year, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The nature of roots 3x²-6x+1=0

Posted by Ritik Modi 1 year, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Suryesh Kumar 1 year, 5 months ago

D = b² - 4ac , => D = 36 - 12 => D = 24 , Here D is greater than 0 (D >0 ) . Hence the nature of roots is real and unequal .

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Sankalp Dinesh 1 year, 5 months ago

Real and distinct roots.

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Ritik Modi 1 year, 5 months ago

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Kisi ne challenge banaya mathematics 10th ke liye toh please share the code..🙏🏼🙏🏼 (Except Trigonometry and Heights and Distances)..

Posted by Sankalp Dinesh 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Nikita Kanwar 1 year, 5 months ago

56123,,51hg।+₹°√§

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10+k=0

Posted by Ritik Modi 1 year, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Gurjot Kaur 1 year, 5 months ago

k=-10

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Harsh Yadav 1 year, 5 months ago

K=-10

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Ridhima Goyal 1 year, 5 months ago

K = -10

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'n' an=4n+5. a3. ?

Posted by Pavankumar Dindalakoppa 1 year, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Sankalp Dinesh 1 year, 5 months ago

an = 4n + 5--- (1), Putting value of n as 3 in the first equation, I wil get a3 = 4(3) + 5 = 12 + 5 = 17. So, the third term of this A.P. is 17.

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Pavankumar Dindalakoppa 1 year, 5 months ago

Please answer

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Lcm of 3 and 7

Posted by Mehul Bansal Viii-C [23] 1 year, 5 months ago

CBSE > Class 10 > Mathematics

4 answers

Aijaz Ansari 1 year, 5 months ago

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Harsh Yadav 1 year, 5 months ago

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Ridhima Goyal 1 year, 5 months ago

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Harsh Vardhan 1 year, 5 months ago

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Cosec•

Posted by Lahari P Sarathi Lahari P Sarathi 1 year, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Suryesh Kumar 1 year, 5 months ago

1/sin

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How can easy trigonometery

Posted by Madhav Sharma 1 year, 5 months ago

CBSE > Class 10 > Mathematics

5 answers

Alka Dohare 1 year, 5 months ago

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Amitosh Singh 1 year, 5 months ago

Dont study

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Mohd Kamil 1 year, 5 months ago

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Mohd Kamil 1 year, 5 months ago

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Lahari P Sarathi Lahari P Sarathi 1 year, 5 months ago

[Cosec theta-cot theta+1÷cosec theta+cot theta-1]=1-cos theta ÷sin theta

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How to manage time in one word

Posted by Kar Thi 1 year, 5 months ago

CBSE > Class 10 > Mathematics