CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

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Currency is a medium of exchange for goods and services. Ashok made a payment to shopkeeper, for the article he purchased, in the denomination of ₹500 and 20. He paid 2640 to the shopkeeper. If all the denomination of * 500 is to be changed by 100 then the boy could have paid * 640 only. Assume the number of currency notes of 500 as 'f' and the number of currency notes of 20 as 'g'". Based on the above information, answer the following questions: i) Write a linear equation representing the amount paid by Ashok. 1 ii) If Ashok had to pay * 2800 to the shopkeeper, how many *20 notes did he need? 1 iii) Find the number of notes in the denomination of ₹500 Ashok had? OR How many total currency notes did Ashok gave to shopkeeper?

Posted by Manas Maurya 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Suryesh Kumar 11 months, 1 week ago

(¡) 5f + 7g = 2640 (¡¡) 15 (¡¡¡) 5 , or , 12

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In the given figure, XZ is parallel to BC. AZ = 3 cm, ZC = 2 cm, BM = 3 cm and MC = 5 cm. Find the length of XY.

Posted by Nitin Kumar 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Arpita Sharma 11 months, 1 week ago

Where is the figure

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What is formula of step deviation in statistics class 10

Posted by Jeet Singh 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

4 answers

Gurjot Kaur 11 months, 2 weeks ago

Mean= a + [∑fiui/∑fi ]×h

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Anurag Singh 11 months, 2 weeks ago

a+sigmafiui/sigmafi

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Chinmayi P P 11 months, 2 weeks ago

Mean =a + fiui/fi × h

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Jeet Singh 11 months, 2 weeks ago

Mean = a + fiui/fi × h

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Find the nature of roots of root3xsquare-root7x+3root3

Posted by Sangmesh Patil 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Choudhury 11 months, 2 weeks ago

In this case, a = √3, b = -√7, and c = 3√3. Substituting these values in the formula, we get: b² - 4ac = (-√7)² - 4(√3)(3√3) = 7 - 36 = -29 < 0 So, there are no real roots for the given equation

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In given figure DE parallel BC , if ad=2cm ,bd=2.5cm, ae=3.2cm. Find ac

Posted by Aayush Verma 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Choudhury 11 months, 2 weeks ago

In Triangle ADE and ABC, AD=2 BD=2.5 AE=3.2 DE ll BC, ∴∠ADE=∠ABC ( corresponding angles) ∠AED=∠ACB ( corresponding angles) ∠BAC is common Δ ADE is similar to Δ ABC In similar triangles, we know that the ratio of corresponding sides is equal ∴ AB/AD=AC/AE (AD+BD)/AD = AC/AE (2+2.5)/2=AC/3.2 4.5/2=AC/3.2 ( 4.5×3.2)/2= AC 7.2=AC Hence the value of AC is 7.2

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In parallelogram ABCD bisector of angle A and b intersect each other at all the value of angle aob is

Posted by Manasi Manasi 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

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Posted by Kamlesh Kumar 11 months, 1 week ago

CBSE > Class 10 > Mathematics

3 answers

Gurjot Kaur 11 months, 2 weeks ago

1.(a + b)³ = a³ + b³ + 3a²b + 3ab² 2.(a - b)3 = a3-b3 - 3a2b + 3ab2

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Bsdusud Osozixu 11 months, 2 weeks ago

Ok understood 👌🆗

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Bsdusud Osozixu 11 months, 1 week ago

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How to find modal class upper limit

Posted by Sneha Gupta 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

2 answers

Sankalp Dinesh 11 months, 2 weeks ago

First find the modal class that is the class with highest frequency and so it's upper limit is the class's upper value.

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Sneha Gupta 11 months, 2 weeks ago

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Udayraj Singh Chouhan

Posted by Udayraj Chouhan 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Sankalp Dinesh 11 months, 2 weeks ago

???¿???

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Please send me homework

Posted by Ayush Kumar 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

3 answers

Miss Anshi 11 months, 1 week ago

😂

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Sankalp Dinesh 11 months, 2 weeks ago

Which homework???

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Great Great 11 months, 1 week ago

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Find the 11th term of the AP (5a-x), 6a, (7a+x)

Posted by Dhyey Soni 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

2 answers

Suryesh Kumar 11 months, 2 weeks ago

Given , AP=(5a-x),(6a),(7a+x) Here , A = 5a-x T¹=5a-x , T ²=6a, T³=7a+ x, D = T²-T¹ => D = 6a - (5a-x) => D= 6a - 5a+ x => D = a + x Now , T ^n = A+ (n-1)D => T ¹¹= A + (11-1)D => T ¹¹ = (5a-x) +10 (a+x) => T ¹¹ = 5a-x + 10a + 10x => T ¹¹ = 10a + 5a +10x - x => T ¹¹ = 15a + 9x Hence the 11th term of this AP is 15a + 9x

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Shubhank Mittal 11 months, 2 weeks ago

Given, a=( 5a-x) d=a2-a1 6a-(5a-x) 6a-5a+x a+x an =a+(n-1)d a11= 5a-x+(11-1)a+x 5a-x+(10) a+x 5a-x+ 10a +10x 15a+9x answer

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The area of rectangular gets reduced by 9 square unit. If it's land this reduced by 5 yd and bread. This increase by three weeks if we increase the land by three roots and the bread by two units a year increased by sixty seven square europe find the dimension of

Posted by Rishika Garg 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Piyush Kushwah 11 months, 2 weeks ago

Hey can explain to me

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Draw the graph of equation X - Y + 1is 0 and 3X + 2Y −12 is 0. Find the point of Intersection of lines and shade the triangular region formed by these lines and x axis

Posted by Rishika Garg 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The nature of roots 3x²-6x+1=0

Posted by Ritik Modi 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

3 answers

Suryesh Kumar 11 months, 2 weeks ago

D = b² - 4ac , => D = 36 - 12 => D = 24 , Here D is greater than 0 (D >0 ) . Hence the nature of roots is real and unequal .

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Sankalp Dinesh 11 months, 2 weeks ago

Real and distinct roots.

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Ritik Modi 11 months, 1 week ago

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Kisi ne challenge banaya mathematics 10th ke liye toh please share the code..🙏🏼🙏🏼 (Except Trigonometry and Heights and Distances)..

Posted by Sankalp Dinesh 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Nikita Kanwar 11 months, 2 weeks ago

56123,,51hg।+₹°√§

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10+k=0

Posted by Ritik Modi 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

3 answers

Gurjot Kaur 11 months, 2 weeks ago

k=-10

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Harsh Yadav 11 months, 2 weeks ago

K=-10

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Ridhima Goyal 11 months, 2 weeks ago

K = -10

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'n' an=4n+5. a3. ?

Posted by Pavankumar Dindalakoppa 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

2 answers

Sankalp Dinesh 11 months, 2 weeks ago

an = 4n + 5--- (1), Putting value of n as 3 in the first equation, I wil get a3 = 4(3) + 5 = 12 + 5 = 17. So, the third term of this A.P. is 17.

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Pavankumar Dindalakoppa 11 months, 2 weeks ago

Please answer

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Lcm of 3 and 7

Posted by Mehul Bansal Viii-C [23] 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

4 answers

Aijaz Ansari 11 months, 2 weeks ago

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Harsh Yadav 11 months, 2 weeks ago

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Ridhima Goyal 11 months, 2 weeks ago

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Harsh Vardhan 11 months, 2 weeks ago

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Cosec•

Posted by Lahari P Sarathi Lahari P Sarathi 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Suryesh Kumar 11 months, 2 weeks ago

1/sin

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How can easy trigonometery

Posted by Madhav Sharma 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics

5 answers

Alka Dohare 11 months, 2 weeks ago

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Amitosh Singh 11 months, 2 weeks ago

Dont study

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Mohd Kamil 11 months, 1 week ago

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Mohd Kamil 11 months, 1 week ago

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Lahari P Sarathi Lahari P Sarathi 11 months, 2 weeks ago

[Cosec theta-cot theta+1÷cosec theta+cot theta-1]=1-cos theta ÷sin theta

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How to manage time in one word

Posted by Kar Thi 11 months, 2 weeks ago

CBSE > Class 10 > Mathematics