CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let p= 0.666.....(1) Multiplying eq.(1) by 10,we get 10p=6.666.....(2) Subtracting eq(1) from eq(2), we get = 10p - p = 6.666 - 0.666 = 9p=6 =. p=6/9 =. p=2/3

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indicate the place value of digit 4 in 5467

Posted by Sports Tribute 5 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Muskan Kumari 5 years, 3 months ago

On hundredth place place value of 4 is 400

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Aastha Barbate 5 years, 3 months ago

Place value of 4 is 400

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Sakshi Singh 5 years, 3 months ago

400(hundredths)

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Charvi Sangwan 5 years, 3 months ago

Hundredth

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Divide (2x^2-x-20) by (x+3) and verify division algorithm

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Divyanshi Rathore ❣ 5 years, 3 months ago

It's 2x^2 - x-20

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Yogita Ingle 5 years, 3 months ago

Quotient = 2x - 5, remainder = -5

Verification:

It can be seen that:

(x + 3) (2x - 5) - 5 = 2x² + 6x - 5x - 15 - 5 = 2x²+ x - 20

Dividend= Divisor x Quotient + Remainder

Hence, the division algorithm is verified.

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In an ap if a is equals to minus 15 a N is equal to 1 is equals to -63 then n is

Posted by Sri Pranathi 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Unique #Seraj Ali ??? 5 years, 3 months ago

Answer

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If d=HCF (48, 72) the value of d is

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Aastha Barbate 5 years, 3 months ago

We have, 48= 2 × 2 × 2 × 2 × 3 = 2^4 × 3 72 = 2 × 2 × 2 ×b3 × 3 =2^3 × 3^2 d = HCF(48,72) = 2^3 × 3 =2×2×2×3 =24 Therefore, the value of d=24

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Charvi Sangwan 5 years, 3 months ago

d=24

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Yogita Ingle 5 years, 3 months ago

If d is the hcf of 48 and 72 so the value of d will be the hcf of later
factor of 48 is
2,3,4,6,8,12,24 and 48
factor of 72 is
2,3,4,6,8,9,12,24,36 and 72
so the hcf is 24 and d= 24

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ANSWER

The (HCF*LCM) for the number 50 and 80 is

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Aastha Barbate 5 years, 3 months ago

Exact ans. is 4000

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Aastha Barbate 5 years, 3 months ago

HCF of no. × LCM of no. =Product of the given no. Thus,HCF ×LCM = 50 × 80 HCF × LCM = 4000

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Divyanshi Rathore ❣ 5 years, 3 months ago

Exactly ans kya hoga

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Gaurav Seth 5 years, 3 months ago

The least common multiple of 50 and 80 can be computed by using the greatest common factor aka gcf of 50 and 80. This is the easiest approach:

lcm (50,80) =

50×80

gcf(50,80)

4000

50×80gcf(50,80)=400010

= 400

Alternatively, the lcm of 50 and 80 can be found using the prime factorization of 50 and 80:

•The prime factorization of 50 is: 2 x 5 x 5

•The prime factorization of 80 is: 2 x 2 x 2 x 2 x 5

•Eliminate the duplicate factors of the two lists, then multiply them once with the remaining factors of the lists to get lcm(50,50) = 400 AND HCF=5

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The decimal expansion of 33/2 ^2 *5 will terminate

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Aastha Barbate 5 years, 3 months ago

33 ---------------- 2^2 × 5 33 × 5. 165 --------------- = -------- 2^2 × 5^2 (2×5)^2 = 165 ---------- (10)^2 = 165 -------- 100 = 1.65 Therefore,1.65 is the decimal expansion of the given value

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Gaurav Seth 5 years, 3 months ago

The decimal expansion of the rational number will terminate after 2 places.

Step-by-step explanation:

To find : The decimal expansion of the rational number will terminate after?

Solution :

The rational number is

Multiply and divide by 5,

Therefore, the decimal expansion of the rational number will terminate after 2 places.

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ANSWER

The cost of 2 kg of apples and 1 kg of grapes on a day was found to be rupees 240 after a month the cost of 4 kg of apples and 2 kg of grapes is rupees 500 represent the situation graphically

Posted by Atul Pandey 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

Given:

Cost of 2kg of apples and 1kg of grapes is ₹ 240

Cost of 4kg of apples and 2kg of grapes is ₹ 500

To find:

Graphical representation of the Situation.

Solution:

1) Let the price of 1 kg apple is ₹ x

Let the price of 1 kg grapes is ₹ y

2) According to the question:

2x+y =240 ---(I)

After a month:

4x+2y =500
2x+y = 250--(II)

The Solution of the equations graphically.

2x+y =240

| x | 50 | 100 |

| y | 140 | 40 |

2x+y = 250

| x | 50 | 100 |

| y | 150 | 50 |

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Curved surface area of cubiod

Posted by Kajal Sikarwar 5 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Muskan Kumari 5 years, 3 months ago

2h(l+b)

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Charvi Sangwan 5 years, 3 months ago

Lateral surface area and curved surface area both are same thing

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Aastha Barbate 5 years, 3 months ago

Cuboid doesn't have curved surface area it has lateral surface area

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Gaurav Seth 5 years, 3 months ago

The Curved surface area of cuboid is the sum of the areas of its six faces. The surface area is the total area of all the faces of a 3D shape.

The curved surface area of a cuboid is the sum of 4 planes of a rectangle, leaving the top (upper) and the base (lower) a. Mathematically, the Curved Surface Area of a cuboid (CSA) is given as:

Curved Surface Area of a cuboid (LSA) = 2 (lh + wh) = 2 h (l + w) square units

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find the sum of series 1+(1+2)+(1+2+3+4)+........+(1+2+3+4+.....+20)

Posted by Shaswat Dehury 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Itz Raman Here ☺ 5 years, 3 months ago

1540 h

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Itz Raman Here ☺ 5 years, 3 months ago

224

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What length of a solid cylinder 2 cm in diameter must be taken to recast into a hollow cylinder of length 16 cm external diameter 20 cm and thickness 2.5mm

Posted by Jissmol Jacob Varghese 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Itz Raman Here ☺ 5 years, 3 months ago

79 ans

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Yogita Ingle 5 years, 3 months ago

Given diameter of solid cylinder = 2 cm
Radius of solid cylinder, r = 1 cm
Volume of solid cylinder =  πr2h
= π × 12 × h = πh →  (1)
Length of hollow cylinder, H = 16 cm
External diameter = 20 cm
External radius = 10 cm
Thickness = 2.5 mm = 0.25 cm
Internal radius = 10 – 0.25 = 9.75 cm
Volume of hollow cylinder = π[10² – (9.75)²] × 16
= 16π × 19.75 × 0.25 →  (2)
From (1) and (2), we get
Πh = 16π × 19.75 × 0.25
  ∴ h = 16 × 19.75 × 0.25 = 79 cm

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Gaurav Seth 5 years, 3 months ago

Given :

Let 'H’ be length of a solid cylinder.

Diameter of the solid cylinder, D = 2 cm

Length of the hollow cylinder, h = 16 cm

External diameter of the hollow cylinder, d1 = 20 cm

Thickness of the hollow cylinder = 2.5 mm = 0.25 cm

Radius of the Solid cylinder , R = 2/2 = 1 cm

External radius of the hollow cylinder, r1 = 20/2 = 10 cm

Internal radius of the hollow cylinder , r2 = External radius of the hollow cylinder - Thickness

Internal radius of the hollow cylinder, r2 = 10 - 0.25 = 9.75 cm

Volume of the hollow cylinder = πh(r1² −r2²)

Since the solid cylinder is recast into a hollow cylinder, so

Volume of solid cylinder = Volume of hollow cylinder

πR²H = πh(r1² −r2²)

R²H = 16(10² - 9.75²)

1²H = 16(100 - 95.0625)

H = 16 × 4.9375

H = 79 cm .

Hence, the length of a solid cylinder is 79 cm .

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ANSWER

gud afternooon everyone

Posted by Itz Raman Here ☺ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Itz Raman Here ☺ 5 years, 3 months ago

ohh sry☹️☹️

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Anupama ?? 5 years, 3 months ago

Here you can only ask questions u are not allowed to chat

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(v) (k - 12) x2 + 2 (k - 12) x ·+ 2 = 0 . ( vz) x2 - 4kx + k = 0 these two questions has real and equal roots find the value of k

Posted by Abhay Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

Here, a = k – 12, b = 2 (k – 12), c = 2
∴ D = b² – 4ac = [2(k– 12)]²
– 4(k – 12) x 2
= 4 (k – 12)²– 8 (k– 12)
Roots are equal, if D = 0
⇒ 4 (k – 12) 2 – 8 (k – 12) = 0
⇒ 4(k – 12)(k – 12 – 2) = 0
⇒ (k – 12) (k – 14) = 0
⇒ k = 12 or 14
But k = 12 does not satisfy the eqn.
k = 14 Ans.

A quadratic equation ....[1] has equal roots when discriminant is 0.

Discriminant is given by:

As per the equation:

Given the quadratic equation:

On comparing with [1] we have;

a = 1 , b = -4k and c = k

Since, the given quadratic equation has equal root

⇒D =0

Squaring both sides we have;

⇒

Substitute the given values we have;

Simplify:

Divide both sides by 4k we have;

therefore, the value of k is, 1/4

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Please solve this two anyone fast

Posted by Abhay Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Atul Pandey 5 years, 3 months ago

Where is the question first put question

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Abhay Singh 5 years, 3 months ago

My question is below

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Avatar ? 5 years, 3 months ago

Where is the question?

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Palak Gupta 5 years, 3 months ago

First Send your problem

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ANSWER

(v) (k - 12) x2 + 2 (k - 12) x ·+ 2 = 0 . ( vz) x2 - 4kx + k = 0

Posted by Abhay Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

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t²-15 Que. From polynomials

Posted by Jithu 11 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aastha Barbate 5 years, 3 months ago

By comparing the given poly. with ax^2 + bx + c =0,we get a = 1, b=0, c=-15 We have, t^2-15=0 t=+_√15 Therefore, the zeroes of the polynomial t^2-√15 are √15,-√15 Now, sum of zeroes=-b/a √15 - √15= -0/1 0=0 Also, product of zeroes=c/a √15 × (-√15) = 15/1 15 = 15 Hence, Verified

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if -4 is the root of the quadratic equation X2+px-4=0and the quadratic equation X2+px+k=0 has equal roots find the value of k give this questions solution its important

Posted by Abhay Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aastha Barbate 5 years, 3 months ago

p(x) = x^2+px-4 p(-4)= (-4)^2 + p(-4) - 4 = 16 - 4p - 4 = 0 = -4p = -12 = p = 3. .....(1) Now,for equal roots equation must satisfy, b^2 - 4ac =0. ...(2) On comparing eq.x^2+px+k=0 with ax^2 +bx +c=0 We get, a=1 , b= p =3(by eq.1), c=k Putting the value in eq (2) we get = (3)^2 - 4(1)(k)=0 = 9 - 4k = 0 = -4k= -9 = k= 9/4 Therefore the value of k is 9/4

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Express 3825 as a product of prime factors

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Great Mission Public School 5 years, 3 months ago

3825=3×3×5×5×17

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Express each number as product of its prime factors 7429

Posted by Vaibhav Ghuge 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aastha Barbate 5 years, 3 months ago

7429 = 17 x 19 x 23

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ANSWER

Ex 6.2

Posted by Ashish Tripathy 5 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Proof that√5, is irrational number

Posted by Saurabh Vishwakarma 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 3 months ago

Let us assume that √5 is a rational number.

Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0
⇒√5=p/q

On squaring both the sides we get,
⇒5=p²/q²
⇒5q²=p² —————–(i)

p²/5= q²

So 5 divides p
p is a multiple of 5
⇒p=5m
⇒p²=25m² ————-(ii)
From equations (i) and (ii), we get,
5q²=25m²
⇒q²=5m²
⇒q² is a multiple of 5
⇒q is a multiple of 5
Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√5 is an irrational number

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How many number of termsrequired for an arithmetic series 10+8+6+……………., to get the sum is-126.

Posted by Pavithra Cs 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aditya Raj 5 years, 3 months ago

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Definition of allotropes

Posted by Ritika Tiwari 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Aditya Raj 5 years, 3 months ago

The version physical form in which elements can be exist

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Dj Rohit 5 years, 3 months ago

Yes

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Tushar Agrawal 5 years, 3 months ago

Exist in two or three different forms in the same physical state is known as an allotropes

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Ex.10.2

Posted by Sunita Naik 4 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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Class tenth maths ex 6.4 question no 3

Posted by Lehashree Srinivasan 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Avatar ? 5 years, 3 months ago

To prove: ar(ABC)/ar(DBC) =OA/ OD First of all we have to do construction. Draw two perpendiculars AP& DM on Bc Proof : In ∆ ABC & ∆ DCB Area of ∆ Abc÷Area of∆ Dcb= 1/2 × BC×AP÷1/2 × BC × DM Area of∆ Abc/ Area of∆ Dcb= AP/DM.......(1) Now, In ∆Aop & ∆ Dom Angle p = Angle M( due to 90°) angle Aop= angle Dom( V.O.A) ∆ AOP~ ∆ DOM( A.A criteria) Ap/ DM= OP/ OM = AO/DO AP/DM= AO/DO....(2) So from 1 & 2 we can say that ar(ABC)/ar(DBC)= OA/DO I hope that it will help you!

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Dj Rohit 5 years, 3 months ago

It's too easy

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Dj Rohit 5 years, 3 months ago

Yes I know

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Divide 6x^3 +13x^2+x-2 by 2x+1 find remainder

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

▄︻̷Řãj 05┻̿═━一 5 years, 3 months ago

Remainder=(-3)=3x²+5+2x+1)(6x³+x-2-6x³+3x²+x-2=10x-2 10x (5)=(-3)

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Aditya Vavhal 5 years, 3 months ago

Remainder = (-3) => 3x² + 5 2x+1)6x³ +13x²+ x-2 - 6x³ + 3x² + x -2 = 10 x- 2 - 10 x -2 10x (5) = (- 3)

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If one zeroes of 2x^2-3x+k is reciprocal to other then find value of k

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gargi Nawghade 5 years, 3 months ago

Let, the zeroes of 2x²-3x+k be A and B. B= 1/A 2x²-3x+k = 0 a=2 , b=-3 , c=k So, Product of zeroes,A×1/A=c/a => 1 = k/2 => k = 2 Thus, the value of k is 2.

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If two zeroes of the polynomial x^4+x^3-15x^2-29x-6 and 2+_√5 find other zeroes

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Aastha Barbate 5 years, 3 months ago

Two zeroes of given equation are x=2+√5 & x=2-√5=0 x-2-√5=0 & x-2+√5=0 Both are the factors of the given poly. =[(x-2)-(√5)]×[(x-2)+(√5)] = (x-2)^2 - (√5)^2 [ Since (a+b)(a-b)=a^2-b^2] = x^2 - 4x + 4 - 5 = x^2 - 4x - 1 = 0 ...(1) Dividing the given poly. By eq. (1), we get, x^4 + x^3 - 15x^2 - 29x -6 ---------------------------------- x^2 -4x - 1 =x^2 +5x + 6=0 Above equation is another factor of given equation By solving it, =x^2 + 3x + 2x + 6 = 0 =x(x + 3) + 2(x +3) = 0 =(x+3) (x+2) = 0 x+3=0 & x+2=0 x=-3 & x= -2 x = -3,-2 are another's zeroes of the given poly.

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Aastha Barbate 5 years, 3 months ago

Given equation.x^4 + x^3 - 15x^2 - 29x - 6

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Form a quadratic polynomial p(y) with sum and product of zeroes are 2 and -3/ 5

Posted by Divyanshi Rathore ❣ 5 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Gargi Nawghade 5 years, 3 months ago

Quadratic polynomial = 5x² - 10x - 3

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Aditya Vavhal 5 years, 3 months ago

There are two method a+b =2=c/a ab= (-3)/5= (-b)/a Where a= 1, b= 2, c= (-3/5) Other use this formala to find equation K[x²+ (sum of zeroes )x + (product of zeroes

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